Magnetism and Matter – CBSE NCERT Study Resources

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12th - Physics

Magnetism and Matter

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Overview

This chapter, Magnetism and Matter, introduces the fundamental concepts of magnetism, magnetic materials, and their behavior under different conditions. It covers topics such as the Earth's magnetism, magnetic properties of materials, and the classification of magnetic substances. The chapter also explores the relationship between electricity and magnetism, along with practical applications of magnetic phenomena.

Key Concepts

Magnetic Dipole

A magnetic dipole consists of two equal and opposite magnetic poles separated by a small distance. It is analogous to an electric dipole and is characterized by its magnetic dipole moment.

Magnetic Field Lines

Magnetic field lines represent the direction and strength of a magnetic field. They emerge from the north pole and terminate at the south pole of a magnet, forming continuous closed loops.

Earth's Magnetism

The Earth behaves like a giant magnet with its magnetic poles near the geographic poles. The angle between the magnetic meridian and the geographic meridian is called the magnetic declination.

Types of Magnetic Materials

  • Diamagnetic: Weakly repelled by a magnetic field (e.g., Bismuth, Copper).
  • Paramagnetic: Weakly attracted by a magnetic field (e.g., Aluminum, Platinum).
  • Ferromagnetic: Strongly attracted by a magnetic field and retain magnetism (e.g., Iron, Cobalt, Nickel).

Hysteresis Loop

The hysteresis loop is a graph that shows the relationship between the magnetizing force (H) and the magnetic flux density (B) in a ferromagnetic material. It demonstrates the lagging of magnetization behind the applied field, leading to energy loss.

Applications of Magnetism

  • Electric motors and generators.
  • Magnetic resonance imaging (MRI) in medical diagnostics.
  • Magnetic storage devices like hard disks.

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define magnetic dipole moment.
Answer:
Definition: Product of pole strength and length of the magnet.
Question 2:
State the SI unit of magnetic susceptibility.
Answer:
Dimensionless (no unit).
Question 3:
What is the angle of dip at the magnetic equator?
Answer:
0° (horizontal component is maximum).
Question 4:
What happens to the magnetic moment when a magnet is cut into two equal parts?
Answer:
Halves (M/2 for each part).
Question 5:
Define hysteresis in magnetism.
Answer:
Definition: Lagging of magnetization behind magnetizing field.
Question 6:
What is the net magnetic moment of an atom in diamagnetic material?
Answer:
Zero (paired electrons cancel out).
Question 7:
State Gauss’s law for magnetism.
Answer:
Magnetic flux through a closed surface is zero.
Question 8:
Why are ferromagnetic materials strongly attracted to magnets?
Answer:
Due to alignment of domains in the field.
Question 9:
What is the direction of Earth’s magnetic field at the poles?
Answer:
Vertical (along the geographic axis).
Question 10:
Name the instrument used to measure magnetic moment.
Answer:
Vibration magnetometer.
Question 11:
What is the effect of temperature on ferromagnetism?
Answer:
Lost above Curie temperature (domains disordered).
Question 12:
Define magnetic declination.
Answer:
Definition: Angle between geographic and magnetic meridians.
Question 13:
Why is soft iron preferred for electromagnets?
Answer:
Low retentivity (easy magnetization/demagnetization).
Question 14:
What is the SI unit of magnetic susceptibility?
Answer:

The SI unit of magnetic susceptibility (χ) is dimensionless because it is the ratio of magnetization (M) to the applied magnetic field intensity (H).
χ = M / H (both M and H have the same units, making χ unitless).

Question 15:
What is the angle between the magnetic moment and the magnetic field for maximum torque?
Answer:

The angle between the magnetic moment (m) and the magnetic field (B) for maximum torque is 90°.
Torque (τ) = m × B × sinθ, which is maximum when sinθ = 1 (θ = 90°).

Question 16:
What happens to the magnetic susceptibility of a diamagnetic material when cooled?
Answer:

The magnetic susceptibility (χ) of a diamagnetic material remains nearly constant with temperature.
Diamagnetic materials weakly repel magnetic fields, and their susceptibility is independent of temperature.

Question 17:
What is the significance of Curie temperature?
Answer:

The Curie temperature (TC) is the temperature above which a ferromagnetic material loses its spontaneous magnetization and becomes paramagnetic.
For iron, TC ≈ 770°C.

Question 18:
Why are the poles of a magnet called north and south poles?
Answer:

The poles of a magnet are named based on their alignment with Earth's magnetic field.
The pole pointing towards Earth's geographic north is called the south pole of the magnet (attracted to Earth's north), and vice versa.

Question 19:
What is the net force on a magnetic dipole in a uniform magnetic field?
Answer:

The net force on a magnetic dipole in a uniform magnetic field is zero.
However, it experiences a torque tending to align the dipole with the field.

Question 20:
State the law used to determine the direction of the magnetic field due to a current-carrying loop.
Answer:

The right-hand thumb rule is used to determine the direction of the magnetic field due to a current-carrying loop.
If the thumb points in the direction of current, curled fingers show the field lines.

Question 21:
What is the effect of a ferromagnetic core in a solenoid?
Answer:

A ferromagnetic core (like iron) in a solenoid increases the magnetic field strength due to its high permeability.
It aligns its domains with the field, amplifying the solenoid's magnetism.

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
What is the angle of dip at the magnetic equator?
Answer:

The angle of dip at the magnetic equator is .
This is because the Earth's magnetic field lines are parallel to the surface here, resulting in no vertical component.

Question 2:
State Gauss's law for magnetism.
Answer:

Gauss's law for magnetism states that the magnetic flux through any closed surface is always zero.
Mathematically, ∮B · dA = 0.
This implies that magnetic monopoles do not exist.

Question 3:
Why are soft iron cores preferred in electromagnets?
Answer:

Soft iron cores are preferred in electromagnets because they have:

  • High permeability, which enhances the magnetic field.
  • Low retentivity, allowing quick demagnetization when the current is switched off.

Question 4:
Differentiate between ferromagnetic and paramagnetic materials.
Answer:

  • Ferromagnetic materials:
    - Strongly attracted by magnets.
    - Have high permeability and retentivity.
    - Example: Iron, Nickel.
  • Paramagnetic materials:
    - Weakly attracted by magnets.
    - Low permeability and no retentivity.
    - Example: Aluminum, Platinum.

Question 5:
Explain why magnetic field lines form closed loops.
Answer:

Magnetic field lines form closed loops because:

  • Magnetic monopoles do not exist (as per Gauss's law).
  • The divergence of the magnetic field (∇ · B = 0) ensures continuous loops.

Question 6:
How does the magnetic moment of an electron in an atom contribute to its magnetism?
Answer:

The magnetic moment of an electron arises due to:

  • Orbital motion (around the nucleus).
  • Spin (intrinsic angular momentum).

These microscopic moments align to produce the net magnetism of the atom.

Question 7:
What is the effect of a uniform magnetic field on a current-carrying circular loop?
Answer:

A uniform magnetic field exerts a torque (τ = m × B) on the loop, aligning its magnetic moment (m) with the field.
No net force acts on the loop as the field is uniform.

Question 8:
Define hysteresis in ferromagnetic materials.
Answer:

Hysteresis is the lagging of magnetization (B) behind the magnetizing field (H) in ferromagnetic materials.
It results in energy loss (as heat) due to the hysteresis loop during magnetization cycles.

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
Define magnetic dipole moment of a current loop. Write its SI unit and dimensional formula.
Answer:

The magnetic dipole moment (m) of a current loop is defined as the product of the current (I) flowing through the loop and the area (A) enclosed by the loop. Its direction is perpendicular to the plane of the loop, following the right-hand thumb rule.


SI unit: Ampere-meter² (A·m²)
Dimensional formula: [M⁰ L² T⁰ A¹]
Question 2:
Explain why magnetic field lines form continuous closed loops.
Answer:

Magnetic field lines form continuous closed loops because magnetic monopoles do not exist. Unlike electric field lines that originate from positive charges and terminate at negative charges, magnetic field lines emerge from the north pole and enter the south pole of a magnet, forming a closed loop. This is a direct consequence of Gauss's law for magnetism, which states that the net magnetic flux through any closed surface is zero.

Question 3:
Differentiate between diamagnetic, paramagnetic, and ferromagnetic materials with one example of each.
Answer:
  • Diamagnetic materials: Weakly repelled by a magnetic field. They have no unpaired electrons. Example: Bismuth.
  • Paramagnetic materials: Weakly attracted by a magnetic field. They have some unpaired electrons. Example: Aluminum.
  • Ferromagnetic materials: Strongly attracted by a magnetic field. They have domains with aligned magnetic moments. Example: Iron.
Question 4:
State the Curie's law for paramagnetic substances and write its mathematical expression.
Answer:

Curie's law states that the magnetization (M) of a paramagnetic material is directly proportional to the applied magnetic field (H) and inversely proportional to the absolute temperature (T).


Mathematical expression: M = C(H/T)
where C is the Curie constant, characteristic of the material.
Question 5:
Describe how a moving coil galvanometer can be converted into an ammeter.
Answer:

To convert a moving coil galvanometer into an ammeter, a low resistance called a shunt is connected in parallel with the galvanometer. The shunt diverts most of the current, allowing only a small fraction to pass through the galvanometer.


Steps:
1. Determine the maximum current (I) to be measured.
2. Calculate the shunt resistance (S) using the formula: S = (Ig * G) / (I - Ig), where Ig is the galvanometer's full-scale deflection current and G is its resistance.
Question 6:
What is the significance of hysteresis loop in ferromagnetic materials?
Answer:

The hysteresis loop represents the relationship between the magnetic field intensity (H) and the magnetization (B) of a ferromagnetic material. It is significant because:

  • It shows the energy loss (hysteresis loss) due to the realignment of magnetic domains.
  • It helps in selecting materials for specific applications (e.g., soft magnets for transformers, hard magnets for permanent magnets).
  • The area of the loop indicates the energy dissipated as heat during one complete cycle of magnetization.
Question 7:
State Curie's law for paramagnetic substances. Write the mathematical expression.
Answer:

Curie's law states that the magnetization (M) of a paramagnetic material is directly proportional to the applied magnetic field (H) and inversely proportional to the absolute temperature (T).


Mathematical expression: M = C(H/T)
where C is the Curie constant.
Question 8:
Describe the hysteresis loop for a ferromagnetic material. What does the area of the loop represent?
Answer:

The hysteresis loop is a graph plotted between the magnetic field intensity (H) and the magnetization (B) of a ferromagnetic material. It shows the lagging of B behind H during the magnetization and demagnetization process.


The area of the hysteresis loop represents the energy loss per unit volume of the material during one complete cycle of magnetization and demagnetization. This energy is dissipated as heat.

Question 9:
What is the significance of Earth's magnetic field? How is the angle of dip related to the magnetic latitude?
Answer:

The Earth's magnetic field protects the planet from harmful solar radiation and cosmic rays by deflecting charged particles. It also aids in navigation using compasses.


The angle of dip (δ) is the angle between the Earth's magnetic field and the horizontal plane. It increases as we move from the equator (magnetic latitude 0°) towards the poles (magnetic latitude 90°), where it becomes 90°.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Explain the hysteresis loop in ferromagnetic materials and its significance in magnetic storage devices.
Answer:
Theoretical Framework

The hysteresis loop represents the lagging of magnetization (M) behind the magnetizing field (H) in ferromagnetic materials. It shows how the material retains some magnetization even after the external field is removed, known as remanence.


Evidence Analysis
  • Our textbook shows that the area of the loop indicates energy loss as heat during magnetization cycles.
  • Materials like iron and cobalt exhibit large loops, making them suitable for permanent magnets.

Critical Evaluation

In magnetic storage (e.g., hard disks), small loops are preferred for quick data rewriting, while large loops ensure data retention.


Future Implications

Research focuses on nanomaterials with tunable loops for high-density storage.

Question 2:
Describe how Earth's magnetic field is generated and its role in protecting life.
Answer:
Theoretical Framework

Earth's magnetic field arises from the dynamo effect, where convective currents in the liquid outer core generate electric currents, producing a magnetic field.


Evidence Analysis
  • Our textbook shows the field deflects solar winds, preventing atmospheric stripping.
  • Paleomagnetic studies confirm field reversals over geological time.

Critical Evaluation

Without this field, harmful cosmic rays would increase mutation rates, threatening life.


Future Implications

Monitoring field strength helps predict space weather hazards to satellites.

Question 3:
Compare diamagnetic, paramagnetic, and ferromagnetic materials with examples.
Answer:
Theoretical Framework

Materials respond differently to external fields: diamagnetic (weak repulsion), paramagnetic (weak attraction), and ferromagnetic (strong attraction).


Evidence Analysis
  • Diamagnetic: Bismuth repels fields (used in levitation experiments).
  • Paramagnetic: Aluminum shows weak attraction in MRI machines.
  • Ferromagnetic: Iron retains magnetization (used in transformers).

Critical Evaluation

Ferromagnets dominate technology due to high permeability.


Future Implications

Graphene-based diamagnets may enable frictionless transport.

Question 4:
Analyze the working principle of a moving coil galvanometer and its conversion into an ammeter.
Answer:
Theoretical Framework

A moving coil galvanometer measures current via torque on a coil in a magnetic field, with deflection proportional to current.


Evidence Analysis
  • Our textbook shows a low-resistance shunt converts it into an ammeter.
  • The shunt bypasses excess current, preserving coil sensitivity.

Critical Evaluation

Without shunts, high currents would damage the delicate coil.


Future Implications

Digital ammeters now replace analog ones for precision.

Question 5:
Discuss Gauss's law for magnetism and its experimental verification.
Answer:
Theoretical Framework

Gauss's law for magnetism states that magnetic flux through a closed surface is zero, implying no magnetic monopoles exist.


Evidence Analysis
  • Our textbook shows experiments with bar magnets always produce dipoles.
  • Quantum theories predict monopoles, but none are observed yet.

Critical Evaluation

The law underpins Maxwell's equations, essential for electromagnetic theory.


Future Implications

Discovering monopoles could revolutionize particle physics.

Question 6:
Explain the hysteresis loop in ferromagnetic materials and its significance in selecting materials for electromagnets.
Answer:
Theoretical Framework

The hysteresis loop represents the lag between magnetization (B) and magnetizing force (H) in ferromagnetic materials. Our textbook shows it is due to domain alignment resistance.

Evidence Analysis
  • Soft iron has a narrow loop (low coercivity), ideal for electromagnets.
  • Steel has a wide loop (high coercivity), used for permanent magnets.
Critical Evaluation

Energy loss (area under loop) is higher in steel, making it inefficient for AC applications. Soft iron’s rapid magnetization reversal minimizes energy dissipation.

Future Implications

Nanocrystalline alloys are emerging with tunable hysteresis, improving efficiency in transformers.

Question 7:
Compare diamagnetic, paramagnetic, and ferromagnetic materials using susceptibility and examples.
Answer:
Theoretical Framework

Magnetic susceptibility (χ) quantifies material response to external fields. We studied χ values: diamagnets (χ<0), paramagnets (χ>0), ferromagnets (χ≫0).

Evidence Analysis
  • Diamagnets: Bismuth (χ=−1.66×10⁻⁵) repels fields weakly.
  • Paramagnets: Aluminum (χ=+2.2×10⁻⁵) aligns weakly with fields.
  • Ferromagnets: Iron (χ~10³) retains magnetization.
Critical Evaluation

Ferromagnets dominate technology (e.g., hard drives) due to high χ. Diamagnets enable MRI shielding.

Future Implications

Graphene-based diamagnets show potential for levitation technologies.

Question 8:
Derive the expression for torque on a magnetic dipole in a uniform magnetic field and discuss its applications.
Answer:
Theoretical Framework

Torque (τ) on dipole moment (m) in field (B) is τ = m×B. Our textbook derives it from force pairs on pole strengths.

Evidence Analysis
  • Example 1: Moving coil galvanometer uses τ = NIABsinθ for current measurement.
  • Example 2: Electric motors rely on τ to rotate armatures.
Critical Evaluation

Maximum τ occurs at θ=90°. Precision instruments minimize frictional losses to enhance sensitivity.

Future Implications

MEMS-based micro-dipoles are enabling nanoscale actuators in medical devices.

Question 9:
Analyze Earth’s magnetic field components and their variation with latitude using current data.
Answer:
Theoretical Framework

Earth’s field (B) has: horizontal (H), vertical (V), and total (T) components. We studied B = √(H²+V²).

Evidence Analysis
  • At equator: V≈0, H≈30μT (IGRF 2020 data).
  • At poles: H≈0, V≈60μT.
Critical Evaluation

Compasses use H, which vanishes at magnetic poles. Satellite data shows 5% field strength decline since 1850.

Future Implications

Geomagnetic models predict pole reversal in ~2000 years, impacting navigation systems.

Question 10:
Compare diamagnetic, paramagnetic, and ferromagnetic materials based on their magnetic susceptibility and behavior in external fields.
Answer:
Theoretical Framework

Magnetic susceptibility (χ) defines how materials respond to external fields. We studied χ values: diamagnetic (χ<0), paramagnetic (χ>0), ferromagnetic (χ≫0).

Evidence Analysis
  • Diamagnetic (e.g., Bismuth) weakly repel fields.
  • Paramagnetic (e.g., Aluminum) weakly attract fields.
  • Ferromagnetic (e.g., Iron) retain magnetization.
Critical Evaluation

Ferromagnets dominate tech applications due to high χ. Diamagnets are used in MRI shielding.

Future Implications

Graphene-based diamagnets show promise for quantum levitation.

Question 11:
Describe the Earth’s magnetic field and its role in protecting life from solar winds. Include a diagram.
Answer:
Theoretical Framework

Earth acts as a giant dipole magnet with field lines from S to N geographic poles. [Diagram: Field lines deflecting solar winds].

Evidence Analysis
  • Magnetosphere deflects charged particles, preventing atmospheric stripping.
  • Van Allen belts trap radiation, as per NCERT data.
Critical Evaluation

Pole reversals (every 200k years) weaken protection temporarily.

Future Implications

Space missions study field decay (10% loss since 1800s) for risk assessment.

Question 12:
Analyze how magnetic domains explain the macroscopic magnetism of materials. Use iron as an example.
Answer:
Theoretical Framework

Magnetic domains are regions with aligned atomic dipoles. In unmagnetized iron, domains cancel out net magnetism.

Evidence Analysis
  • External fields align domains, creating net magnetization (Curie point: 770°C for iron).
  • Domain walls move, shown in Barkhausen effect experiments.
Critical Evaluation

Domain theory bridges atomic spin and bulk magnetic properties.

Future Implications

Single-domain nanoparticles could revolutionize high-density data storage.

Question 13:
Explain the concept of magnetic dipole moment and derive its expression for a current-carrying loop. Discuss its significance in the context of torque experienced by the loop in a uniform magnetic field.
Answer:

The magnetic dipole moment (m) is a vector quantity that represents the strength and orientation of a magnetic dipole, such as a current-carrying loop. It is defined as the product of the current (I) flowing through the loop and the area vector (A) of the loop. Mathematically, it is expressed as:
m = I × A
where the direction of A is perpendicular to the plane of the loop, following the right-hand thumb rule.

To derive the expression for a circular loop of radius r:
1. Area of the loop, A = πr²
2. Magnetic dipole moment, m = I × πr²
The SI unit of m is Am² (ampere-meter squared).

Significance in torque: When a current-carrying loop is placed in a uniform magnetic field (B), it experiences a torque (τ) given by:
τ = m × B
This torque tends to align the magnetic dipole moment with the magnetic field, minimizing potential energy. The magnitude of torque is maximum when m and B are perpendicular and zero when they are parallel.

Question 14:
Describe the Earth's magnetic field and its elements. Explain how a magnetic needle aligns itself with the Earth's magnetic field, including the concept of angle of dip.
Answer:

The Earth's magnetic field resembles that of a giant bar magnet with its south pole near the geographic north and vice versa. It has three key elements:
1. Magnetic Declination: The angle between the geographic meridian and magnetic meridian at a place.
2. Angle of Dip (δ): The angle between the Earth's magnetic field and the horizontal plane.
3. Horizontal Component (BH): The component of Earth's field parallel to the surface.

A magnetic needle aligns itself along the resultant magnetic field of the Earth. In the absence of other influences:
1. The needle's north pole points towards the Earth's magnetic south.
2. It dips downward in the northern hemisphere and upward in the southern hemisphere due to the angle of dip.

The angle of dip varies with latitude:
- At the magnetic equator, δ = 0° (field is horizontal).
- At the magnetic poles, δ = 90° (field is vertical).
This alignment helps in navigation and compass applications.

Question 15:
Compare and contrast diamagnetic, paramagnetic, and ferromagnetic materials with examples. Discuss their behavior in an external magnetic field and their susceptibility values.
Answer:

The three types of magnetic materials differ in their response to an external magnetic field:

  • Diamagnetic (e.g., Bismuth, Copper):
    - Weakly repelled by a magnetic field.
    - No permanent dipole moment; induced moment opposes the field.
    - Susceptibility (χ) is small and negative (~10-5).
  • Paramagnetic (e.g., Aluminum, Oxygen):
    - Weakly attracted by a magnetic field.
    - Has permanent dipoles that align with the field.
    - Susceptibility is small and positive (~10-3 to 10-5).
  • Ferromagnetic (e.g., Iron, Nickel):
    - Strongly attracted by a magnetic field.
    - Permanent dipoles align in domains, creating a large net moment.
    - Susceptibility is large and positive (~103 to 105).

Behavior in a field:
- Diamagnets develop weak magnetization opposite to the field.
- Paramagnets align with the field but lose alignment when the field is removed.
- Ferromagnets retain alignment even after the field is removed (hysteresis).

Question 16:
Explain the concept of magnetic dipole moment and derive its expression for a current-carrying loop. Discuss its significance in determining the behavior of a magnetic dipole in an external magnetic field.
Answer:

The magnetic dipole moment (m) is a vector quantity that represents the strength and orientation of a magnetic dipole, such as a current-carrying loop or a bar magnet. It is defined as the product of the current (I) flowing through the loop and the area (A) enclosed by the loop, with its direction given by the right-hand thumb rule.


Derivation for a current-carrying loop:


Consider a circular loop of radius r carrying current I. The area of the loop is A = πr².


The magnetic dipole moment is given by: m = I × A.


Since the loop is circular, m = I × πr².


The direction of m is perpendicular to the plane of the loop, following the right-hand rule.


Significance:

  • The torque (τ) experienced by the dipole in an external magnetic field B is given by τ = m × B, which determines its rotational behavior.
  • The potential energy (U) of the dipole in the field is U = -m · B, indicating stable equilibrium when m aligns with B.
  • It helps classify materials as diamagnetic, paramagnetic, or ferromagnetic based on their dipole moments.
Question 17:
Describe the Earth's magnetic field and its elements. Explain how the angle of dip varies with latitude and its importance in navigation.
Answer:

The Earth's magnetic field resembles that of a giant bar magnet tilted at an angle to its rotational axis. Its key elements are:

  • Magnetic Declination (θ): The angle between geographic north and magnetic north.
  • Angle of Dip (δ): The angle between the Earth's magnetic field and the horizontal plane.
  • Horizontal Component (BH): The component of the field parallel to the surface.

Variation of Angle of Dip with Latitude:

  • At the magnetic equator, the field is entirely horizontal (δ = 0°).
  • As latitude increases, the angle of dip increases, reaching 90° at the magnetic poles.

Importance in Navigation:

  • Compasses align with BH, so accurate knowledge of δ ensures proper directional guidance.
  • Pilots and sailors use dip circles to correct for deviations caused by δ at different latitudes.
  • Helps in mapping and surveying by accounting for local magnetic anomalies.
Question 18:
Explain the concept of magnetic dipole moment and derive its expression for a current-carrying loop. Discuss its significance in determining the behavior of the loop in a uniform magnetic field.
Answer:

The magnetic dipole moment (m) is a vector quantity that represents the strength and orientation of a magnetic dipole, such as a current-carrying loop. It is defined as the product of the current (I) flowing through the loop and the area vector (A) of the loop. The direction of the area vector is perpendicular to the plane of the loop, following the right-hand thumb rule.


For a circular loop of radius r carrying current I, the magnetic dipole moment is given by:
m = I × A
where A = πr² is the area of the loop. Thus, m = Iπr².


Significance:

  • The torque (τ) experienced by the loop in a uniform magnetic field (B) is given by τ = m × B, which determines the rotational effect on the loop.
  • The potential energy (U) of the loop in the magnetic field is U = -m · B, indicating stable equilibrium when m and B are aligned.


This concept is crucial in understanding the behavior of magnetic materials and devices like electric motors and MRI machines.

Question 19:
Describe the Earth's magnetic field and explain how a compass needle aligns itself with the magnetic meridian. Include a labeled diagram to illustrate the elements of Earth's magnetism.
Answer:

The Earth's magnetic field resembles that of a giant bar magnet tilted at an angle to its geographic axis. It has three main components:

  • Magnetic Declination: The angle between the geographic meridian and magnetic meridian at a place.
  • Magnetic Inclination (Dip): The angle made by the Earth's magnetic field with the horizontal.
  • Horizontal Component (BH): The component of Earth's magnetic field parallel to the surface.


A compass needle aligns itself with the magnetic meridian due to the torque exerted by Earth's magnetic field. The needle's magnetic dipole moment (m) experiences a torque τ = m × B, causing it to rotate until it aligns with B. The horizontal component (BH) directs the needle north-south, while the vertical component influences its tilt.


Diagram (labeled):
[Earth's Magnetic Field Diagram]
1. Geographic North and South Poles
2. Magnetic North and South Poles
3. Magnetic field lines
4. Angle of Declination (θ)
5. Angle of Inclination (δ)


This alignment helps in navigation and studying Earth's geomagnetic properties.

Question 20:
Explain the concept of magnetic dipole moment and derive its expression for a current-carrying circular loop. Discuss its significance in determining the behavior of a magnetic dipole in an external magnetic field.
Answer:

The magnetic dipole moment (m) is a vector quantity that represents the strength and orientation of a magnetic dipole, such as a current-carrying loop or a bar magnet. It is defined as the product of the current (I) and the area (A) enclosed by the loop, with its direction given by the right-hand thumb rule.


For a circular loop of radius r carrying current I, the magnetic dipole moment is derived as follows:


Step 1: Area of the circular loop, A = πr².
Step 2: Magnetic dipole moment, m = I × A.
Step 3: Substituting the area, m = I × πr².


The direction of m is perpendicular to the plane of the loop, following the right-hand rule. The significance of magnetic dipole moment lies in its ability to determine the torque (τ) experienced by the dipole in an external magnetic field (B), given by τ = m × B. It also helps calculate the potential energy (U) of the dipole in the field, U = -m · B, which explains the alignment of dipoles along the field to minimize energy.

Question 21:
Describe the hysteresis loop for a ferromagnetic material. Explain how it demonstrates the properties of retentivity and coercivity, and discuss its practical implications in devices like transformers.
Answer:

The hysteresis loop is a graphical representation of the relationship between the magnetizing force (H) and the magnetic flux density (B) in a ferromagnetic material. It shows how the material retains magnetization even after the external field is removed.


Key features of the hysteresis loop:

  • Retentivity: The residual magnetization (Br) when H is reduced to zero. It indicates the material's ability to retain magnetism.
  • Coercivity: The reverse magnetizing force (Hc) required to reduce B to zero. It measures the resistance to demagnetization.

The loop is formed due to the lagging of B behind H, caused by domain alignment and energy losses. In transformers, a narrow hysteresis loop (low Hc and Br) is preferred to minimize energy loss as heat (hysteresis loss). Materials like soft iron are used for efficient energy transfer.

Question 22:
Describe the hysteresis loop for a ferromagnetic material. Explain how it demonstrates the retentivity and coercivity of the material, and discuss its practical implications in the design of electromagnets and permanent magnets.
Answer:

The hysteresis loop is a graphical representation of the relationship between the magnetic field intensity (H) and the magnetic flux density (B) in a ferromagnetic material. It shows how the material retains magnetization even after the external field is removed, highlighting its retentivity and coercivity.


Key features of the hysteresis loop:

  • Retentivity: The residual magnetization (Br) when H is reduced to zero. It indicates the material's ability to retain magnetism.
  • Coercivity: The reverse field (Hc) required to reduce B to zero. It measures the resistance to demagnetization.


Practical implications:

  • Electromagnets: Soft ferromagnetic materials (narrow loop) are used due to low Hc, enabling easy magnetization and demagnetization.
  • Permanent magnets: Hard ferromagnetic materials (wide loop) with high Br and Hc retain magnetism for long periods.


The loop also illustrates energy loss as heat (hysteresis loss), which is minimized in transformers using soft iron cores.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
A student observes that a ferromagnetic material loses its magnetism when heated beyond its Curie temperature. Explain this phenomenon using domain theory and discuss its implications in industrial applications.
Answer:
Case Deconstruction

Ferromagnetic materials have tiny magnetic domains aligned in the same direction. Heating disrupts this alignment due to increased thermal energy.

Theoretical Application
  • At Curie temperature, domains randomize, causing loss of magnetism.
  • Example: Iron loses ferromagnetism at 770°C.
Critical Evaluation

Industries use this property in temperature-controlled switches, like in electric irons, where heating demagnetizes the material to cut off current.

Question 2:
Compare the magnetic susceptibility of diamagnetic, paramagnetic, and ferromagnetic materials. Tabulate their properties and explain why superconductors exhibit perfect diamagnetism.
Answer:
Case Deconstruction

Magnetic susceptibility measures how a material responds to an external magnetic field.

Theoretical Application
MaterialSusceptibility
DiamagneticSmall, negative
ParamagneticSmall, positive
FerromagneticLarge, positive
Critical Evaluation

Superconductors expel magnetic fields (Meissner effect), resulting in χ = −1, perfect diamagnetism.

Question 3:
Analyze how Earth’s magnetic field protects life from solar winds. Use the concept of magnetosphere and provide evidence from recent space missions.
Answer:
Case Deconstruction

Earth’s magnetic field deflects charged particles from solar winds.

Theoretical Application
  • Magnetosphere acts as a shield, funneling particles to the poles (auroras).
  • Example: NASA’s MMS mission studies magnetic reconnection.
Critical Evaluation

Without this field, solar radiation would strip our atmosphere, as seen on Mars.

Question 4:
A hysteresis loop for a ferromagnet shows energy loss. Calculate the energy dissipated per cycle if the loop area is 50 J/m³ and the material’s volume is 0.02 m³. Discuss its impact on transformer cores.
Answer:
Case Deconstruction

Hysteresis loss occurs due to domain realignment in AC fields.

Theoretical Application
  • Energy loss = Area × Volume = 50 × 0.02 = 1 J/cycle.
  • Example: Silicon steel reduces losses in transformers.
Critical Evaluation

High losses cause inefficiency, leading to heat and energy waste.

Question 5:
Explain why Gauss’s law for magnetism (∇⋅B = 0) implies no magnetic monopoles exist. Contrast this with Coulomb’s law and cite experimental validations.
Answer:
Case Deconstruction

Gauss’s law states magnetic field lines are continuous loops.

Theoretical Application
  • Unlike electric fields (Coulomb’s law), no isolated poles exist.
  • Example: LHC experiments found no evidence of monopoles.
Critical Evaluation

This symmetry underpins Maxwell’s equations, confirmed by quantum theories.

Question 6:
A student observes that a ferromagnetic material loses its magnetism when heated beyond its Curie temperature. Using domain theory, explain this phenomenon and its implications for industrial applications.
Answer:
Case Deconstruction

Ferromagnetic materials have aligned magnetic domains below the Curie temperature (e.g., 770°C for iron). Heating disrupts this alignment, turning the material paramagnetic.


Theoretical Application
  • Domain theory states thermal energy randomizes spins, erasing net magnetization.
  • Industrial use: Temperature-controlled magnetic switches rely on this property.

Critical Evaluation

Our textbook shows this limits high-temperature applications (e.g., transformers), but alloys like Alnico retain magnetism longer.

Question 7:
Compare the magnetic susceptibility of diamagnetic and paramagnetic substances using quantum mechanics. Provide two examples where this difference is technologically significant.
Answer:
Case Deconstruction

Diamagnetic materials (χ∼−10⁻⁵) repel fields due to Lenz’s law, while paramagnetic ones (χ∼+10⁻³) align with fields via unpaired electrons.


Theoretical Application
  • Quantum spin states explain weak vs. strong responses.
  • Examples: MRI uses diamagnetic water, while paramagnetic O₂ sensors exploit χ differences.

Critical Evaluation

NCERT highlights how superconductors (perfect diamagnets) enable Maglev trains, showing practical scalability.

Question 8:
Analyze how Earth’s magnetic field varies with latitude using a dipole model. How does this affect navigation systems?
Answer:
Case Deconstruction

Earth acts as a dipole with field strength (B) varying as (1+3sin²θ)^(1/2), where θ is magnetic latitude.


Theoretical Application
  • B is maximum at poles (60μT) vs. equator (30μT).
  • Compass needles dip vertically near poles, requiring tilt compensation in aircraft.

Critical Evaluation

Modern GPS supplements this, but our textbook shows migratory animals still rely on geomagnetic cues.

Question 9:
A solenoid with soft iron core produces stronger magnetism than an air-core solenoid. Derive the relationship using relative permeability (μᵣ) and discuss energy efficiency.
Answer:
Case Deconstruction

Magnetic field B = μ₀μᵣnI, where μᵣ of soft iron (~2000) amplifies B versus air (μᵣ=1).


Theoretical Application
  • Hysteresis loss is lower in soft iron, improving efficiency.
  • Example: Transformers use laminated cores to reduce eddy currents.

Critical Evaluation

We studied how μᵣ trade-offs exist—ferrites have lower μᵣ but higher resistivity for high-frequency uses.

Question 10:
The hysteresis loop of a steel specimen shows higher coercivity than soft iron. Relate this to permanent magnetism and material selection for loudspeakers.
Answer:
Case Deconstruction

Steel’s wide hysteresis loop indicates high coercivity (Hc), retaining magnetization better than soft iron.


Theoretical Application
  • Permanent magnets need high Hc (e.g., steel in compass needles).
  • Loudspeakers use soft iron cores for rapid field reversal.

Critical Evaluation

NCERT data shows modern neodymium magnets (Hc~10⁶ A/m) outperform both, revolutionizing compact devices.

Question 11:

A student performs an experiment to study the magnetic properties of a bar magnet using a compass needle. The compass needle deflects when brought near the magnet. Based on this observation, answer the following:

  • Why does the compass needle deflect near the bar magnet?
  • What does the deflection indicate about the magnetic field lines of the bar magnet?
Answer:

The compass needle deflects near the bar magnet because it aligns itself along the magnetic field lines of the bar magnet. The needle, being a small magnet itself, experiences a torque due to the magnetic field of the bar magnet, causing it to deflect.


The deflection indicates the direction of the magnetic field lines of the bar magnet. The north pole of the compass needle points towards the south pole of the bar magnet, showing that magnetic field lines emerge from the north pole and terminate at the south pole outside the magnet.


Additionally, the deflection angle depends on the strength of the magnetic field at that point. A stronger field causes a larger deflection.

Question 12:

A diamagnetic material is placed in an external magnetic field. The material shows a weak repulsion when subjected to the field. Explain the behavior of the material and compare it with the behavior of a ferromagnetic material in the same situation.

Answer:

The diamagnetic material shows weak repulsion because it develops a magnetization in the opposite direction to the applied magnetic field. This happens due to the induced orbital motion of electrons, which generates a magnetic moment opposing the external field.


In contrast, a ferromagnetic material would show strong attraction when placed in the same field. This is because ferromagnetic materials have domains that align with the external field, creating a large net magnetic moment in the same direction as the field.


Key differences:

  • Diamagnetic materials have no permanent magnetic moment, while ferromagnetic materials have strong permanent moments.
  • Diamagnetism is a universal property of all materials but is very weak, whereas ferromagnetism is exhibited only by certain materials like iron and is very strong.
Question 13:

A student performs an experiment to study the magnetic properties of a bar magnet using a compass needle. The compass needle deflects when brought near the magnet. Based on this observation:

  • Explain why the compass needle deflects.
  • Describe how the magnetic dipole moment of the bar magnet can be determined using this setup.
Answer:

The compass needle deflects because it aligns itself along the magnetic field lines produced by the bar magnet. The needle, being a small magnetic dipole, experiences a torque due to the external magnetic field of the bar magnet, causing it to rotate and align.


To determine the magnetic dipole moment (m) of the bar magnet:

  • Place the bar magnet at a known distance d from the compass needle along its axial line.
  • Measure the angle of deflection θ of the compass needle.
  • Use the formula for the magnetic field due to a bar magnet at an axial point: B = (μ₀/4π) * (2m/d³).
  • Equate this to the horizontal component of Earth's magnetic field BH causing the deflection: B = BH tanθ.
  • Solve for m using the measured values.

This method relies on balancing the torque due to the bar magnet's field with Earth's magnetic field.

Question 14:

A ferromagnetic material is placed in an external magnetic field, and its magnetization (M) is studied. The material shows hysteresis when the field is varied.

  • Define hysteresis in this context.
  • Explain how the area of the hysteresis loop relates to the energy loss in the material.
Answer:

Hysteresis refers to the lagging of magnetization (M) behind the applied magnetic field H. When the external field is cycled (increased and decreased), the material does not retrace its magnetization curve, resulting in a loop called the hysteresis loop.


The area of the hysteresis loop represents the energy loss per unit volume of the material during one complete cycle of magnetization. This is because:

  • Work is done to align the magnetic domains during magnetization.
  • Energy is dissipated as heat due to domain wall motion and realignment.
  • The larger the loop area, the greater the energy loss (e.g., in transformers, this leads to core loss).

Materials with narrow hysteresis loops (e.g., soft iron) are preferred for applications requiring minimal energy loss, while those with wide loops (e.g., steel) are used for permanent magnets.

Question 15:
A student performs an experiment to study the hysteresis loop of a ferromagnetic material using a solenoid. The graph obtained shows the relationship between magnetic field intensity (H) and magnetic induction (B).

Explain the significance of the area enclosed by the hysteresis loop. How does this relate to the energy loss in the material during one complete cycle of magnetization?

Answer:

The area enclosed by the hysteresis loop represents the energy loss per unit volume of the ferromagnetic material during one complete cycle of magnetization and demagnetization.

This energy loss occurs due to the work done against the internal friction of the magnetic domains as they realign with the changing external magnetic field.

The larger the area, the greater the energy dissipated as heat, which is undesirable in applications like transformer cores where efficiency is crucial.

Materials with narrow hysteresis loops (e.g., soft iron) are preferred for such applications to minimize energy loss.

Question 16:
A bar magnet of magnetic moment M is placed in a uniform magnetic field B at an angle θ.

Derive the expression for the torque acting on the magnet. Also, explain how this torque tends to align the magnet with the magnetic field.

Answer:

The torque (τ) acting on the bar magnet is given by:

τ = M × B = MB sinθ

where M is the magnetic moment, B is the magnetic field, and θ is the angle between them.

The torque arises because the two poles of the magnet experience equal and opposite forces, creating a rotational effect.

This torque tends to align the magnet with the field because:

  • When θ = 0°, sinθ = 0, so τ = 0 (stable equilibrium).
  • When θ = 90°, sinθ = 1, so τ is maximum.
Thus, the torque rotates the magnet until M and B are parallel, minimizing potential energy.

Question 17:
A student performs an experiment to study the variation of magnetic field along the axis of a circular coil carrying current. The observations are plotted as a graph of magnetic field (B) versus distance (x) from the center of the coil.

(i) Identify the nature of the graph obtained.
(ii) Derive the expression for magnetic field at a point on the axis of the coil.
(iii) How does the magnetic field vary if the number of turns in the coil is doubled?

Answer:

(i) The graph of magnetic field (B) versus distance (x) from the center of the coil is a symmetric curve with a maximum at the center (x = 0) and gradually decreasing as we move away from the center along the axis. The field is directly proportional to the current and number of turns but inversely proportional to the distance for points far from the coil.


(ii) The magnetic field (B) at a point on the axis of a circular coil of radius R, carrying current I, and having N turns is given by:
B = (μ₀ N I R²) / (2(R² + x²)^(3/2))
where:
- μ₀ is the permeability of free space,
- x is the distance from the center along the axis.
Derivation steps:
1. Use Biot-Savart Law to find the field due to a small current element.
2. Integrate over the entire coil, considering axial symmetry.
3. Resolve components and simplify for axial points.


(iii) If the number of turns (N) is doubled, the magnetic field (B) also doubles, as B ∝ N. This is because each turn contributes equally to the net field, and the effect is additive.

Question 18:
A bar magnet of magnetic moment M is cut into two equal parts along its length.

(i) What happens to the pole strength and magnetic moment of each part?
(ii) If the two parts are arranged perpendicular to each other, calculate the net magnetic moment of the combination.
(iii) How does the magnetic field at a point along the axial line change compared to the original magnet?

Answer:

(i) When the bar magnet is cut into two equal parts:
- Pole strength (m) remains the same for each part, as it depends on the nature of the material.
- Magnetic moment (M) of each part becomes M/2, since magnetic moment is given by M = m × 2l (where 2l is the length), and length is halved.


(ii) If the two parts are arranged perpendicularly, the net magnetic moment is the vector sum of the individual moments.
Since each part has M/2 and they are perpendicular:
M_net = √[(M/2)² + (M/2)²] = M/√2.
The direction will be at 45° to both parts.


(iii) The magnetic field at a point along the axial line of the original magnet is given by:
B = (μ₀ / 4π) (2M / r³)
For each half, the field reduces to:
B' = (μ₀ / 4π) (2(M/2) / r³) = B/2
Thus, the field due to one half is half of the original field. If both halves contribute (e.g., side by side), the net field may vary based on configuration.

Question 19:
A student performs an experiment to study the hysteresis loop of a ferromagnetic material using a solenoid. The graph obtained shows the relationship between magnetic field intensity (H) and magnetic induction (B).

Explain why the area of the hysteresis loop represents energy loss per unit volume during one complete cycle of magnetization. Also, suggest one practical application where minimizing this energy loss is crucial.

Answer:

The hysteresis loop depicts the lagging of magnetic induction (B) behind the magnetic field intensity (H) due to the domain alignment resistance in ferromagnetic materials.

The area enclosed by the loop represents the energy dissipated as heat per unit volume during one complete magnetization cycle. This occurs because work is done to align the magnetic domains, and energy is lost when domains resist realignment during demagnetization.

Application: In transformer cores, minimizing hysteresis loss is critical to improve efficiency. Soft iron with a narrow hysteresis loop is used to reduce energy wastage as heat.

Question 20:
A bar magnet of magnetic moment M is cut into two equal parts along its length.

Compare the new magnetic moments of the resulting pieces with the original magnet. How does this affect the pole strength? Justify your answer with a diagram showing the orientation of the poles before and after cutting.

Answer:

When the bar magnet is cut into two equal parts:

Magnetic Moment (M): Each new piece will have a magnetic moment of M/2. Since magnetic moment depends on both pole strength and length (M = m × 2l), halving the length reduces the moment by half.

Pole Strength (m): The pole strength remains unchanged because cutting does not alter the intrinsic strength of the poles.

Diagram:
Before Cutting: N —— S (Full length, moment = M)
After Cutting: N —— S | N —— S (Two magnets, each with moment = M/2).

Thus, the number of poles doubles, but individual pole strength stays the same.

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