Nuclei – CBSE NCERT Study Resources

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12th

12th - Physics

Nuclei

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Overview of the Chapter: Nuclei

This chapter introduces the fundamental concepts related to atomic nuclei, their properties, and the phenomena associated with them. It covers topics such as nuclear composition, nuclear forces, radioactivity, nuclear reactions, and applications of nuclear physics.

Nucleus: The central part of an atom, composed of protons and neutrons, which contains most of the atom's mass.

Atomic Mass and Composition of Nucleus

The nucleus consists of protons and neutrons, collectively known as nucleons. The number of protons defines the atomic number (Z), while the sum of protons and neutrons gives the mass number (A).

Isotopes: Atoms of the same element with the same atomic number but different mass numbers due to varying numbers of neutrons.

Nuclear Forces and Binding Energy

Nuclear forces are the strong attractive forces that hold nucleons together. The binding energy of a nucleus is the energy required to disassemble it into its constituent nucleons.

Binding Energy per Nucleon: The average energy required to remove a nucleon from the nucleus, which is a measure of nuclear stability.

Radioactivity

Radioactivity is the spontaneous emission of particles or radiation from unstable nuclei. The three common types of radioactive decay are alpha (α), beta (β), and gamma (γ) decay.

Half-life: The time taken for half of the radioactive nuclei in a sample to decay.

Nuclear Reactions and Energy

Nuclear reactions involve changes in the nucleus, leading to the release or absorption of energy. Nuclear fission and fusion are two important types of nuclear reactions.

Nuclear Fission: The splitting of a heavy nucleus into smaller nuclei with the release of energy.

Nuclear Fusion: The combining of light nuclei to form a heavier nucleus with the release of energy.

Applications of Nuclear Physics

Nuclear physics has numerous applications, including nuclear power generation, medical diagnostics and treatment (e.g., radiotherapy), and archaeological dating (e.g., carbon dating).

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define nuclear force.
Answer:

The strong attractive force between nucleons (protons and neutrons) in a nucleus.

Question 2:
What is the binding energy per nucleon?
Answer:

Energy required to separate a nucleon from the nucleus, averaged per nucleon.

Question 3:
State the law of radioactive decay.
Answer:

The rate of decay is proportional to the number of undecayed nuclei.

Question 4:
What is the half-life of a radioactive element?
Answer:

Time taken for half of the radioactive nuclei to decay.

Question 5:
Name the process in which a heavy nucleus splits into lighter nuclei.
Answer:

Nuclear fission.

Question 6:
What is nuclear fusion?
Answer:

Process where lighter nuclei combine to form a heavier nucleus.

Question 7:
Which isotope of hydrogen is used in nuclear fusion reactions?
Answer:

Deuterium (²H) or Tritium (³H).

Question 8:
What is the role of a moderator in a nuclear reactor?
Answer:

Slows down fast neutrons to sustain the chain reaction.

Question 9:
Define mass defect.
Answer:

Difference between the mass of a nucleus and the sum of its nucleons.

Question 10:
What is the SI unit of activity of a radioactive substance?
Answer:

Becquerel (Bq).

Question 11:
Name the radioactive isotope used in carbon dating.
Answer:

Carbon-14 (¹⁴C).

Question 12:
What is alpha decay?
Answer:

Emission of an alpha particle (⁴He nucleus) from a radioactive nucleus.

Question 13:
State the relation between half-life (T) and decay constant (λ).
Answer:

T = 0.693/λ.

Question 14:
What is the approximate radius of a nucleus with mass number A?
Answer:

R = R₀A¹ᐟ³, where R₀ ≈ 1.2 fm.

Question 15:
Define nuclear fusion.
Answer:

Nuclear fusion is the process where two lighter nuclei combine to form a heavier nucleus, releasing a large amount of energy.
Example: Fusion of hydrogen isotopes to form helium in the Sun.

Question 16:
What is the binding energy of a nucleus?
Answer:

Binding energy is the minimum energy required to disassemble a nucleus into its constituent protons and neutrons.
It is a measure of nuclear stability.

Question 17:
State the SI unit of activity of a radioactive substance.
Answer:

The SI unit of activity is the becquerel (Bq), where 1 Bq = 1 disintegration per second.

Question 18:
What is the role of control rods in a nuclear reactor?
Answer:

Control rods (made of cadmium or boron) absorb excess neutrons to regulate the chain reaction and prevent overheating.

Question 19:
Name the phenomenon responsible for the energy production in stars.
Answer:

Nuclear fusion is responsible for energy production in stars, where hydrogen nuclei fuse to form helium under extreme temperature and pressure.

Question 20:
Why is nuclear fission considered an exothermic process?
Answer:

Nuclear fission releases energy because the total binding energy of the resulting nuclei is greater than that of the original nucleus.

Question 21:
What is the function of a moderator in a nuclear reactor?
Answer:

The moderator (e.g., heavy water or graphite) slows down fast neutrons to thermal energies to sustain the chain reaction.

Question 22:
Define mass defect in nuclear physics.
Answer:

Mass defect is the difference between the mass of a nucleus and the sum of the masses of its individual nucleons.
It accounts for the binding energy.

Question 23:
What is the significance of the neutron-proton ratio in stable nuclei?
Answer:

Stable nuclei have a specific neutron-proton ratio (≈1 for light nuclei, >1 for heavier nuclei) to balance nuclear forces and minimize repulsion.

Question 24:
Name the radioactive isotope used in radioactive dating of ancient artifacts.
Answer:

Carbon-14 is used in radioactive dating due to its predictable half-life (5730 years) and presence in organic materials.

Question 25:
What happens to the atomic number during alpha decay?
Answer:

During alpha decay, the atomic number decreases by 2 because the nucleus emits an alpha particle (helium nucleus).

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
Define binding energy of a nucleus.
Answer:

The binding energy of a nucleus is the minimum energy required to disassemble the nucleus into its constituent protons and neutrons.
It represents the energy equivalent of the mass defect (Δm) according to Einstein's equation E = Δmc².

Question 2:
What is the significance of the mass number (A) in nuclear physics?
Answer:

The mass number (A) represents the total number of protons and neutrons (nucleons) in a nucleus.
It determines the isotope of an element and influences properties like nuclear stability and binding energy.

Question 3:
State the relation between half-life (T½) and decay constant (λ).
Answer:

The half-life (T½) and decay constant (λ) are related as:
T½ = ln(2)/λ ≈ 0.693/λ.
This shows that a higher decay constant implies a shorter half-life.

Question 4:
Why are heavy nuclei unstable?
Answer:

Heavy nuclei (A > 200) are unstable due to the Coulomb repulsion between protons overpowering the strong nuclear force.
This leads to radioactive decay (like α-decay) to achieve stability.

Question 5:
What is nuclear fusion? Give an example.
Answer:

Nuclear fusion is the process where two lighter nuclei combine to form a heavier nucleus, releasing energy.
Example: Deuterium-Tritium fusion in stars:
²H + ³H → ⁴He + n + 17.6 MeV.

Question 6:
Differentiate between nuclear fission and nuclear fusion in one point.
Answer:
  • Nuclear fission involves splitting a heavy nucleus (e.g., Uranium-235), while nuclear fusion combines light nuclei (e.g., Hydrogen isotopes).
Question 7:
Calculate the energy equivalent of 1 atomic mass unit (u) in MeV.
Answer:

Using E = mc²:
1 u = 931.5 MeV/c².
Thus, E = 931.5 MeV (since c² is numerically 1 in natural units).

Question 8:
Name the force responsible for holding nucleons together in a nucleus.
Answer:

The strong nuclear force (or strong interaction) binds protons and neutrons in the nucleus.
It is short-range (acts within ~1 fm) and overcomes Coulomb repulsion.

Question 9:
Why is a neutron preferred over a proton for nuclear bombardment?
Answer:

Neutrons are uncharged, so they are not repelled by the nucleus.
Protons face Coulomb repulsion, making neutron-induced reactions more efficient.

Question 10:
What is the Q-value of a nuclear reaction?
Answer:

The Q-value is the energy released or absorbed in a nuclear reaction.
Q > 0 for exothermic reactions (energy released),
Q < 0 for endothermic reactions (energy absorbed).

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
Define binding energy of a nucleus and explain its significance in nuclear reactions.
Answer:

The binding energy of a nucleus is the minimum energy required to disassemble a nucleus into its constituent protons and neutrons.

It is significant because:

  • It determines the stability of the nucleus—higher binding energy per nucleon means greater stability.
  • It explains energy release in nuclear fusion (light nuclei combining) and nuclear fission (heavy nuclei splitting).
For example, iron (Fe-56) has the highest binding energy per nucleon, making it the most stable nucleus.

Question 2:
Differentiate between nuclear fission and nuclear fusion with one example of each.
Answer:

Nuclear fission is the splitting of a heavy nucleus into smaller nuclei, releasing energy (e.g., Uranium-235 splitting into barium and krypton).

Nuclear fusion is the combining of light nuclei to form a heavier nucleus, releasing energy (e.g., deuterium and tritium fusing to form helium in the Sun).

Key differences:

  • Fission occurs with heavy nuclei; fusion occurs with light nuclei.
  • Fission is used in nuclear reactors; fusion powers stars.

Question 3:
Explain why the mass of a nucleus is always less than the sum of the masses of its individual nucleons.
Answer:

The mass of a nucleus is less than the sum of its individual nucleons due to the mass defect, which arises because some mass is converted into binding energy (as per Einstein’s equation E=mc²).

This energy holds the nucleus together, making it stable. For example, in a helium nucleus, the mass defect accounts for the strong nuclear force binding protons and neutrons.

Question 4:
Describe the role of control rods and moderators in a nuclear reactor.
Answer:

Control rods (e.g., cadmium or boron) absorb excess neutrons to regulate the chain reaction and prevent overheating.

Moderators (e.g., heavy water or graphite) slow down fast neutrons to thermal energies, increasing the likelihood of fission in Uranium-235.

Together, they ensure a controlled and sustained nuclear reaction.

Question 5:
What is radioactive decay? Derive the relationship between half-life (T½) and decay constant (λ).
Answer:

Radioactive decay is the spontaneous disintegration of unstable nuclei, emitting radiation (alpha, beta, or gamma).

The relationship is derived as:
N = N₀e-λt
At half-life, N = N₀/2.
Substituting: N₀/2 = N₀e-λT½
Simplifying: T½ = ln(2)/λ ≈ 0.693/λ.

Question 6:
State Einstein’s mass-energy equivalence and calculate the energy released when 1 u (unified atomic mass unit) of mass is converted entirely into energy.
Answer:

Einstein’s equation states: E = mc², where m is mass and c is the speed of light (~3×10⁸ m/s).

For 1 u (~1.66×10-27 kg):
E = (1.66×10-27) × (3×10⁸)²
E ≈ 1.49×10-10 J or 931.5 MeV (since 1 MeV = 1.6×10-13 J).

Question 7:
Define binding energy of a nucleus and explain its significance in nuclear physics.
Answer:

The binding energy of a nucleus is the minimum energy required to disassemble a nucleus into its constituent protons and neutrons.

It represents the energy equivalent of the mass defect (Δm) according to Einstein's equation E = Δmc².

Significance: Higher binding energy per nucleon indicates greater stability of the nucleus. It explains why energy is released in nuclear fusion (light nuclei combine) and fission (heavy nuclei split).

Question 8:
Differentiate between nuclear fusion and nuclear fission with one example of each.
Answer:

Nuclear Fusion:
- Light nuclei combine to form a heavier nucleus.
- Releases enormous energy (e.g., Sun's energy via hydrogenhelium).

Nuclear Fission:
- Heavy nucleus splits into smaller nuclei.
- Used in nuclear reactors (e.g., uranium-235 splitting into barium and krypton).

Question 9:
Explain why the density of nuclear matter is nearly constant for all nuclei.
Answer:

The nuclear density is constant because nuclei are packed tightly with nucleons (protons/neutrons).

Since the nuclear radius (R) ∝ A1/3 (where A is mass number), volume ∝ A.

Thus, density (ρ = mass/volume) remains ~2.3 × 10¹⁷ kg/m³ for all nuclei, independent of size.

Question 10:
Describe the role of neutrons in stabilizing a nucleus.
Answer:

Neutrons stabilize nuclei by:
- Counteracting proton-proton repulsion via the strong nuclear force.
- Increasing the binding energy per nucleon (especially in heavier nuclei like uranium).

Example: Carbon-12 has 6 protons and 6 neutrons, but carbon-14 (radioactive) has 8 neutrons for stability.

Question 11:
State the law of radioactive decay and derive the expression for half-life.
Answer:

Law: The rate of decay (dN/dt) is proportional to the number of undecayed nuclei (N): dN/dt = -λN (λ = decay constant).

Derivation:
Integrate to get N = N₀e-λt.
At half-life (T½), N = N₀/2.
Substitute: T½ = ln(2)/λ ≈ 0.693/λ.

Question 12:
What is a nuclear chain reaction? List two conditions for its controlled use in reactors.
Answer:

A nuclear chain reaction is a self-sustaining process where fission neutrons trigger further fissions.

Conditions for control:
1. Critical mass: Enough fissile material (uranium-235) to sustain the reaction.
2. Moderators: Slow down neutrons (e.g., graphite or heavy water) to increase fission probability.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Explain the binding energy per nucleon curve and its significance in nuclear stability. How does it justify the energy release in nuclear fusion and fission?
Answer:
Theoretical Framework

The binding energy per nucleon curve plots the average energy required to remove a nucleon from a nucleus. It peaks around iron-56, indicating maximum stability.

Evidence Analysis
  • For lighter nuclei (e.g., hydrogen), fusion increases binding energy, releasing energy (e.g., Sun's energy).
  • For heavier nuclei (e.g., uranium-235), fission increases binding energy, releasing energy (e.g., nuclear reactors).
Critical Evaluation

Our textbook shows iron-56 as the most stable, explaining why fusion occurs in stars and fission in reactors.

Future Implications

This principle guides sustainable energy research, like ITER for fusion power.

Question 2:
Describe the nuclear force and compare it with gravitational and electrostatic forces. Why is it crucial for nuclear stability?
Answer:
Theoretical Framework

Nuclear force is the strong, short-range (<1 fm) attraction between nucleons, overcoming electrostatic repulsion between protons.

Evidence Analysis
  • It is 100× stronger than electrostatic force but acts only within nuclei (e.g., helium-4 stability).
  • Gravity is negligible at nuclear scales (e.g., neutron stars show dominance of nuclear force).
Critical Evaluation

We studied that without nuclear force, nuclei would disintegrate due to proton repulsion.

Future Implications

Understanding it aids in quark-gluon plasma research at CERN.

Question 3:
Analyze the radioactive decay law mathematically and derive the expression for half-life. How is it used in carbon dating?
Answer:
Theoretical Framework

The decay law states N = N0e-λt, where λ is the decay constant. Half-life (T½) is ln(2)/λ.

Evidence Analysis
  • Carbon-14 (T½ = 5730 years) decays predictably, enabling age estimation (e.g., fossils).
  • Example: A sample with 25% C-14 implies two half-lives (≈11,460 years).
Critical Evaluation

Our textbook shows logarithmic decay fits observed data precisely.

Future Implications

Accurate dating refines archaeological and geological timelines.

Question 4:
Discuss the mass-energy equivalence principle in nuclear reactions. Calculate the energy released in the fusion of deuterium and tritium (given masses: D=2.0141u, T=3.0160u, He=4.0026u, n=1.0087u).
Answer:
Theoretical Framework

Einstein's E=mc² states mass defect (Δm) converts to energy (E=Δm×931.5 MeV/u).

Evidence Analysis
  • D + T → He + n: Δm = (2.0141+3.0160) − (4.0026+1.0087) = 0.0188u.
  • Energy = 0.0188 × 931.5 = 17.5 MeV (e.g., ITER reactor fuel).
Critical Evaluation

We studied this in the context of the Sun’s energy output.

Future Implications

Fusion energy could replace fossil fuels with minimal waste.

Question 5:
Explain the nuclear shell model and how it predicts magic numbers. Why are magic-numbered nuclei exceptionally stable?
Answer:
Theoretical Framework

The shell model proposes nucleons occupy discrete energy levels, with magic numbers (2, 8, 20, etc.) indicating filled shells.

Evidence Analysis
  • Double-magic nuclei (e.g., helium-4, oxygen-16) show high stability and abundance.
  • Lead-208 (Z=82, magic) is the heaviest stable nucleus.
Critical Evaluation

Our textbook correlates magic numbers with low decay rates and high binding energy.

Future Implications

This model guides synthesis of superheavy elements like oganesson (Z=118).

Question 6:
Describe the radioactive decay law mathematically and experimentally. How is the half-life of a substance determined using this law?
Answer:
Theoretical Framework

The decay law states dN/dt=−λN, where λ is the decay constant. Integrated form: N=N0e−λt.

Evidence Analysis
  • Half-life (t1/2) is when N=N0/2, giving t1/2=ln2/λ.
  • Experimentally, Geiger-Müller counters track decay rates over time (e.g., C-14 dating).
Critical Evaluation

We studied that λ is unique for each isotope (e.g., U-238: 4.5×109 years). This predictability enables applications like nuclear medicine.

Future Implications

Accurate half-life measurements are vital for radiation therapy and archaeological dating.

Question 7:
Compare nuclear fusion and fission reactions in terms of energy output, conditions required, and byproducts. Provide one example of each.
Answer:
Theoretical Framework

Fusion combines light nuclei (e.g., 2H+3H→4He+n), while fission splits heavy ones (e.g., 235U+n→fragments).

Evidence Analysis
ParameterFusionFission
Energy/Nucleon~17.6 MeV (D-T)~0.9 MeV (U-235)
Conditions107 K plasmaCritical mass needed
Critical Evaluation

Fusion produces minimal waste (helium) versus fission's radioactive fragments (e.g., Sr-90). However, fusion remains experimentally challenging (ITER project).

Future Implications

Fusion could offer clean energy if confinement issues are solved.

Question 8:
Explain the liquid drop model of the nucleus. How does it account for the semi-empirical mass formula's terms?
Answer:
Theoretical Framework

The model treats the nucleus as an incompressible liquid drop. The mass formula includes:

  • Volume energy (A)
  • Surface energy (−A2/3)
  • Coulomb repulsion (−Z2/A1/3)
Evidence Analysis

Our textbook shows binding energy B=avA−asA2/3−acZ2/A1/3+pairing terms. This matches observed nuclear masses within 1%.

Critical Evaluation

While successful for medium nuclei, it fails to explain magic numbers, addressed by the shell model.

Future Implications

The model remains foundational for predicting nuclear properties in astrophysics.

Question 9:
Discuss the neutrino hypothesis in β-decay. How was it experimentally verified? What role do neutrinos play in modern physics?
Answer:
Theoretical Framework

Pauli proposed neutrinos (ν) to conserve energy in β-decay (n→p+e+ν̄e). They carry missing energy/momentum.

Evidence Analysis
  • Reines-Cowan experiment (1956) detected ν̄e via ν̄e+p→n+e+.
  • Modern detectors like Super-Kamiokande observe solar neutrinos.
Critical Evaluation

We studied that neutrinos have tiny mass (<0.1 eV/c2) and oscillate between flavors, proving beyond Standard Model physics.

Future Implications

They're key to understanding supernovae and dark matter candidates.

Question 10:
Explain the binding energy per nucleon curve and its significance in nuclear stability. Discuss how it varies with mass number.
Answer:
Theoretical Framework

The binding energy per nucleon is the energy required to disassemble a nucleus into its constituent protons and neutrons. It is a measure of nuclear stability. Our textbook shows that the curve peaks around iron-56 (A=56), indicating maximum stability.

Evidence Analysis
  • For light nuclei (A < 20), the curve rises sharply due to strong nuclear forces overcoming Coulomb repulsion.
  • For intermediate nuclei (20 < A < 60), the curve is nearly flat, showing optimal stability.
  • For heavy nuclei (A > 60), the curve declines due to increasing Coulomb repulsion.
Critical Evaluation

This explains why fusion occurs in stars (light nuclei) and fission occurs in heavy nuclei like uranium-235. The curve validates the semi-empirical mass formula.

Future Implications

Understanding this curve helps in designing nuclear reactors and predicting energy release in fusion/fission processes.

Question 11:
Describe the nuclear fusion process in stars. How does the proton-proton chain contribute to energy production in the Sun?
Answer:
Theoretical Framework

Nuclear fusion is the process where lighter nuclei combine to form heavier nuclei, releasing energy. In stars like the Sun, the proton-proton chain is the dominant fusion mechanism.

Evidence Analysis
  • Step 1: Two protons fuse to form deuterium, a positron, and a neutrino.
  • Step 2: Deuterium fuses with another proton to form helium-3.
  • Step 3: Two helium-3 nuclei combine to form helium-4, releasing two protons.
Critical Evaluation

This process converts 0.7% of mass into energy (E=mc²). Our textbook shows it produces 26.7 MeV per helium-4 nucleus, sustaining solar energy.

Future Implications

Replicating controlled fusion on Earth could provide clean, limitless energy, as seen in ITER experiments.

Question 12:
Compare nuclear fission and nuclear fusion reactions based on energy output, conditions required, and applications.
Answer:
Theoretical Framework

Fission splits heavy nuclei (e.g., uranium-235), while fusion combines light nuclei (e.g., hydrogen). Both release energy via mass defect (E=mc²).

Evidence Analysis
ParameterFissionFusion
Energy per reaction~200 MeV~26.7 MeV (per proton-proton chain)
ConditionsCritical mass, neutron moderationHigh temperature (10⁷ K), plasma confinement
ApplicationsNuclear reactors, atomic bombsStars, experimental reactors (ITER)
Critical Evaluation

Fission is commercially viable but produces radioactive waste. Fusion is cleaner but technologically challenging.

Future Implications

Fusion could revolutionize energy if confinement and sustainability issues are resolved.

Question 13:
Analyze the radioactive decay law mathematically. Derive the expression for half-life and mean life, and explain their interdependence.
Answer:
Theoretical Framework

The decay law states dN/dt = -λN, where λ is the decay constant. Integrating gives N = N₀e^(-λt), showing exponential decay.

Evidence Analysis
  • Half-life (T½): Time for half the nuclei to decay. At t = T½, N = N₀/2. Substituting, we get T½ = ln(2)/λ ≈ 0.693/λ.
  • Mean life (τ): Average lifetime of a nucleus. Calculated as τ = 1/λ.
Critical Evaluation

Thus, T½ = τ·ln(2). For carbon-14 (T½=5730 years), τ≈8267 years. Our textbook confirms this via decay simulations.

Future Implications

These concepts are vital in radiometric dating (e.g., carbon dating) and nuclear medicine (e.g., half-life of isotopes).

Question 14:
Explain the binding energy per nucleon curve and its significance in nuclear stability. How does it justify the energy release in nuclear fission and fusion?
Answer:
Theoretical Framework

The binding energy per nucleon is the energy required to disassemble a nucleus into its constituent protons and neutrons. It peaks around iron-56, indicating maximum stability.

Evidence Analysis
  • For heavy nuclei (e.g., uranium-235), fission releases energy as products have higher binding energy per nucleon.
  • For light nuclei (e.g., hydrogen), fusion increases binding energy per nucleon, releasing energy.
Critical Evaluation

Our textbook shows the curve's peak explains why iron-56 is the most stable. Deviations indicate energy release potential.

Future Implications

This principle underpins nuclear power and stellar energy production, highlighting its universal relevance.

Question 15:
Describe the radioactive decay law mathematically and derive the expression for half-life. How is it experimentally verified using a Geiger-Müller counter?
Answer:
Theoretical Framework

The decay law states N = N0e-λt, where λ is the decay constant. Half-life (T1/2) is derived as ln(2)/λ.

Evidence Analysis
  • Geiger-Müller counters measure activity (e.g., for cobalt-60), showing exponential decay.
  • Plotting ln(N) vs time yields a straight line, validating the law.
Critical Evaluation

We studied that half-life is independent of initial quantity, confirmed by consistent T1/2 in experiments.

Future Implications

This law is crucial for radiometric dating and medical applications like radiotherapy.

Question 16:
Compare nuclear fission and fusion reactions in terms of energy output, conditions required, and byproducts. Provide one example of each from real-world applications.
Answer:
Theoretical Framework

Fission splits heavy nuclei (e.g., uranium-235), while fusion combines light nuclei (e.g., hydrogen isotopes).

Evidence Analysis
  • Fission: Requires neutron bombardment, releases 200 MeV/event (e.g., nuclear reactors).
  • Fusion: Needs high temperature/pressure (e.g., sun, ITER project), yields ~17 MeV per reaction.
Critical Evaluation

Our textbook shows fusion is cleaner but technologically challenging compared to fission.

Future Implications

Fusion could offer limitless energy if confinement challenges are overcome.

Question 17:
Analyze the mass defect and Einstein’s mass-energy equivalence in the context of nuclear reactions. How does this explain the energy released in the sun?
Answer:
Theoretical Framework

Mass defect is the difference between a nucleus's mass and its nucleons' total mass. Einstein's E=mc2 converts this to energy.

Evidence Analysis
  • In the sun, 4 hydrogen nuclei (mass ~4.032 u) fuse to helium (4.0026 u), releasing 26.73 MeV.
  • This 0.7% mass defect powers stars via proton-proton chain.
Critical Evaluation

We studied that even tiny mass defects yield enormous energy, validating nuclear astrophysics.

Future Implications

Harnessing this process on Earth could revolutionize energy production.

Question 18:
Explain the nuclear binding energy and its significance in the stability of nuclei. Derive the expression for binding energy per nucleon and discuss its variation with mass number.
Answer:

The nuclear binding energy is the energy required to disassemble a nucleus into its constituent protons and neutrons. It is a measure of the stability of the nucleus, as a higher binding energy indicates a more stable nucleus. The binding energy arises due to the strong nuclear force, which overcomes the electrostatic repulsion between protons.


The binding energy (B.E.) can be calculated using the mass defect (Δm) and Einstein's mass-energy equivalence formula: B.E. = Δm × c², where c is the speed of light. The mass defect is the difference between the mass of the separated nucleons and the actual mass of the nucleus.


To derive the binding energy per nucleon, we divide the total binding energy by the mass number (A): B.E. per nucleon = B.E. / A. This value indicates the average energy needed to remove a nucleon from the nucleus.


The binding energy per nucleon varies with the mass number as follows:

  • For light nuclei (A < 30), the binding energy per nucleon increases rapidly due to the increasing dominance of the strong nuclear force.
  • For medium nuclei (30 < A < 90), it reaches a peak (around 8.8 MeV for iron-56), indicating maximum stability.
  • For heavy nuclei (A > 90), it gradually decreases due to the increasing Coulomb repulsion between protons.

This variation explains why nuclear fusion occurs in light nuclei (to increase binding energy) and fission occurs in heavy nuclei (to achieve more stable configurations).

Question 19:
Describe the radioactive decay law and derive the expression for the half-life of a radioactive substance. How is the half-life related to the decay constant?
Answer:

The radioactive decay law states that the rate of decay of radioactive nuclei is proportional to the number of undecayed nuclei present at any time. Mathematically, it is expressed as: dN/dt = -λN, where N is the number of undecayed nuclei, t is time, and λ is the decay constant.


To derive the expression for half-life (T1/2), we start by solving the decay law equation. Integrating both sides gives: N = N0e-λt, where N0 is the initial number of nuclei.


Half-life is defined as the time taken for half of the radioactive nuclei to decay. At t = T1/2, N = N0/2. Substituting into the decay equation:


N0/2 = N0e-λT1/2

Simplifying, we get:


1/2 = e-λT1/2

Taking the natural logarithm on both sides:


ln(1/2) = -λT1/2

Which simplifies to:


T1/2 = ln(2)/λ ≈ 0.693/λ

This shows that the half-life is inversely proportional to the decay constant. A smaller decay constant (λ) means a longer half-life, indicating a slower decay process.


This relationship is crucial in applications like radiometric dating and nuclear medicine, where knowing the half-life helps predict the decay behavior of radioactive substances.

Question 20:
Explain the process of nuclear fission with an example. Discuss the role of chain reaction in this process and its significance in nuclear power generation.
Answer:

Nuclear fission is the process where a heavy nucleus, such as uranium-235 or plutonium-239, splits into smaller nuclei when bombarded with a neutron, releasing a large amount of energy. For example, when a neutron strikes a uranium-235 nucleus, it splits into barium-141 and krypton-92, along with the emission of three neutrons and energy.


The chain reaction occurs when the neutrons released during fission strike other uranium-235 nuclei, causing them to split and release more neutrons. This self-sustaining process is crucial for controlled energy release in nuclear reactors.


In nuclear power plants, the chain reaction is carefully controlled using control rods (like cadmium or boron) to absorb excess neutrons, ensuring a steady energy output. This process is significant because it provides a large amount of energy from a small amount of fuel, reducing reliance on fossil fuels and minimizing greenhouse gas emissions.

Question 21:
Describe the binding energy per nucleon curve and its implications. How does it explain the energy release in nuclear fusion and fission?
Answer:

The binding energy per nucleon curve is a plot of the binding energy per nucleon against the mass number (A) of nuclei. It peaks around iron-56, indicating that nuclei with mass numbers near iron are the most stable.


Implications:

  • For nuclear fission, heavy nuclei (like uranium) split into smaller fragments closer to the peak of the curve, releasing energy because the binding energy per nucleon increases.
  • For nuclear fusion, light nuclei (like hydrogen) combine to form heavier nuclei (like helium), moving toward the peak of the curve and releasing energy.


This curve explains why both fusion and fission release energy. Fusion occurs in stars, including the Sun, where hydrogen nuclei fuse to form helium. Fission is used in nuclear reactors, where heavy nuclei split to produce energy. The curve highlights the stability of intermediate-mass nuclei and the energy potential of nuclear reactions.

Question 22:
Explain the process of nuclear fission with an example. Discuss the role of chain reaction in this process and its significance in energy production.
Answer:

Nuclear fission is the process where a heavy nucleus, such as uranium-235 or plutonium-239, splits into smaller nuclei when bombarded with a neutron, releasing a large amount of energy. For example, when a neutron strikes a uranium-235 nucleus, it splits into barium-141 and krypton-92, along with the emission of three neutrons and energy.


The chain reaction occurs when the neutrons released during fission strike other uranium-235 nuclei, causing them to split and release more neutrons. This self-sustaining process multiplies the energy output exponentially.


The significance of chain reactions in energy production lies in their ability to release massive amounts of energy from a small amount of fuel. Controlled chain reactions in nuclear reactors are used to generate electricity, while uncontrolled reactions lead to nuclear explosions.


Additional Information: The energy released in fission is due to the conversion of a small amount of mass into energy, as described by Einstein's mass-energy equivalence (E=mc²).

Question 23:
Describe the binding energy per nucleon curve and its implications on nuclear stability. How does it explain the energy release in nuclear fusion and fission?
Answer:

The binding energy per nucleon curve plots the average energy required to remove a nucleon from a nucleus against the mass number. It peaks around iron-56, indicating that nuclei near this region are the most stable.


Implications on nuclear stability:

  • Nuclei with low mass numbers (e.g., hydrogen, helium) have lower binding energy per nucleon, making them less stable.
  • Nuclei with mass numbers near iron-56 have higher binding energy, making them highly stable.
  • Heavy nuclei (e.g., uranium) have slightly lower binding energy, making them prone to fission.


In nuclear fusion, lighter nuclei combine to form a heavier nucleus closer to the peak of the curve, releasing energy due to the increase in binding energy per nucleon. For example, fusion in stars converts hydrogen into helium, releasing vast energy.


In nuclear fission, heavy nuclei split into smaller fragments closer to the peak, releasing energy because the products have higher binding energy per nucleon than the original nucleus.


Additional Information: The curve explains why fusion is dominant in stars (light nuclei) and fission is used on Earth (heavy nuclei) for energy production.

Question 24:
Explain the process of nuclear fission with an example. Discuss the role of chain reaction in this process and its applications in energy production.
Answer:

Nuclear fission is the process in which a heavy nucleus, such as uranium-235 or plutonium-239, splits into two or more smaller nuclei, along with the release of a large amount of energy and several neutrons. This occurs when the nucleus absorbs a slow-moving neutron, becomes unstable, and splits.


For example, when a uranium-235 nucleus absorbs a neutron, it forms uranium-236, which is highly unstable. It then splits into two smaller nuclei like barium-141 and krypton-92, along with the release of three neutrons and a tremendous amount of energy (approximately 200 MeV per fission).


The released neutrons can further cause fission in other uranium-235 nuclei, leading to a chain reaction. For a sustained chain reaction, the critical mass of the fissile material must be achieved, ensuring that enough neutrons are available to continue the process.


Applications in energy production include:

  • Nuclear power plants: Controlled chain reactions are used to generate heat, which produces steam to drive turbines and generate electricity.
  • Nuclear weapons: Uncontrolled chain reactions result in massive energy release, as seen in atomic bombs.

Understanding nuclear fission and chain reactions is crucial for harnessing nuclear energy safely and efficiently, contributing to clean energy solutions.

Question 25:
Explain the process of nuclear fusion in stars with reference to the proton-proton chain and carbon-nitrogen-oxygen (CNO) cycle. How does this process release energy?
Answer:

Nuclear fusion is the process by which lighter nuclei combine to form heavier nuclei, releasing a tremendous amount of energy. In stars like the Sun, fusion occurs primarily through two processes: the proton-proton (p-p) chain and the carbon-nitrogen-oxygen (CNO) cycle.


Proton-Proton Chain:
1. Two protons (hydrogen nuclei) fuse to form a deuterium nucleus, releasing a positron and a neutrino.
2. The deuterium nucleus fuses with another proton to form helium-3, releasing a gamma-ray photon.
3. Two helium-3 nuclei combine to form helium-4, releasing two protons.


CNO Cycle:
1. A proton fuses with a carbon-12 nucleus to form nitrogen-13, releasing a gamma-ray photon.
2. Nitrogen-13 decays into carbon-13, emitting a positron and a neutrino.
3. Carbon-13 fuses with another proton to form nitrogen-14.
4. Nitrogen-14 captures another proton to form oxygen-15, which decays into nitrogen-15.
5. Nitrogen-15 fuses with a proton to produce carbon-12 and helium-4, completing the cycle.


Energy Release:
The mass of the resulting nucleus is slightly less than the sum of the original nuclei. This mass defect is converted into energy as per Einstein's equation E=mc², where E is energy, m is mass, and c is the speed of light. This energy sustains the star's luminosity and heat.

Question 26:
Explain the process of nuclear fission with an example. Discuss the role of chain reaction in this process and how it is controlled in a nuclear reactor.
Answer:

Nuclear fission is the process where a heavy nucleus, such as uranium-235 (U-235) or plutonium-239 (Pu-239), splits into smaller nuclei when bombarded with a neutron, releasing a large amount of energy. For example, when U-235 absorbs a slow neutron, it becomes unstable and splits into barium-141 and krypton-92, along with 2-3 neutrons and energy.


The released neutrons can further cause fission in other U-235 nuclei, leading to a chain reaction. This self-sustaining process multiplies the energy output exponentially if left uncontrolled.


In a nuclear reactor, the chain reaction is controlled using:

  • Control rods (made of cadmium or boron) to absorb excess neutrons.
  • Moderators (like heavy water or graphite) to slow down neutrons, ensuring efficient fission.
  • Coolants to regulate temperature and transfer heat for energy production.

This controlled fission ensures steady energy release without explosions, making it useful for power generation.

Question 27:
Explain the process of nuclear fusion in stars with reference to the proton-proton chain and carbon-nitrogen-oxygen (CNO) cycle. How does this process contribute to stellar energy production?
Answer:

Nuclear fusion is the process by which lighter nuclei combine to form heavier nuclei, releasing a tremendous amount of energy. In stars like the Sun, the primary mechanism is the proton-proton (p-p) chain, while in more massive stars, the CNO cycle dominates.


Proton-Proton Chain:

  • Two protons fuse to form a deuterium nucleus, releasing a positron and a neutrino.
  • The deuterium nucleus fuses with another proton to form helium-3.
  • Two helium-3 nuclei combine to form helium-4, releasing two protons.

CNO Cycle:

  • Carbon-12 acts as a catalyst, capturing protons to form nitrogen and oxygen isotopes.
  • Eventually, helium-4 is produced, and carbon-12 is regenerated.

These processes convert mass into energy as per Einstein's mass-energy equivalence (E=mc²), sustaining the star's luminosity and heat. The energy released counteracts gravitational collapse, maintaining stellar equilibrium.

Question 28:
Describe the principle and working of a nuclear reactor with a labeled diagram. Explain the roles of moderator, control rods, and coolant in ensuring a controlled chain reaction.
Answer:

A nuclear reactor harnesses energy from controlled nuclear fission of uranium-235 or plutonium-239. The key components and their roles are:


1. Fuel Rods: Contain fissile material (e.g., U-235) where fission occurs, releasing neutrons and energy.


2. Moderator: (e.g., graphite or heavy water) slows down fast neutrons to thermal energies, increasing the likelihood of further fission.


3. Control Rods: (e.g., cadmium or boron) absorb excess neutrons to regulate the reaction rate and prevent runaway chain reactions.


4. Coolant: (e.g., water or liquid sodium) transfers heat from the reactor core to a steam generator, producing electricity.


Diagram (Conceptual):

  • Core: Contains fuel rods immersed in moderator.
  • Control rods inserted/withdrawn to adjust reactivity.
  • Coolant circulates through the core to extract heat.

The reactor operates in a critical state, where the neutron production rate equals the loss rate, ensuring stable energy output. Safety systems prevent meltdowns by emergency shutdown mechanisms.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
A nuclear reactor uses Uranium-235 as fuel. Explain the chain reaction process and how control rods regulate it. Also, compare the energy output of nuclear fission with coal combustion.
Answer:
Case Deconstruction

In a nuclear reactor, Uranium-235 undergoes fission, releasing neutrons that trigger further fission reactions, creating a chain reaction.

Theoretical Application
  • Control rods absorb excess neutrons to prevent an uncontrolled reaction.
  • Fission of 1 kg U-235 releases ~3.9 × 1013 J, while coal combustion yields ~3 × 107 J/kg.
Critical Evaluation

Our textbook shows nuclear energy is more efficient but poses radioactive waste challenges, unlike coal.

Question 2:
The binding energy per nucleon curve peaks at Iron-56. Analyze why fusion occurs in stars for lighter nuclei and fission for heavier ones, referencing the curve.
Answer:
Case Deconstruction

The binding energy per nucleon curve shows Iron-56 as the most stable nucleus.

Theoretical Application
  • Lighter nuclei (e.g., Hydrogen) fuse to increase binding energy, releasing energy.
  • Heavier nuclei (e.g., Uranium) fission to move toward Iron-56, also releasing energy.
Critical Evaluation

We studied that stars fuse lighter elements, while reactors fission heavy ones, both optimizing energy output.

Question 3:
A student claims alpha decay reduces nuclear stability. Using the neutron-proton ratio, justify or refute this with examples of Thorium-232 and Polonium-210.
Answer:
Case Deconstruction

Alpha decay emits a He-4 nucleus, altering the neutron-proton ratio.

Theoretical Application
  • Thorium-232 (N/Z = 1.59) decays to Radium-228 (N/Z = 1.55), moving toward stability.
  • Polonium-210 (N/Z = 1.52) decays to Lead-206 (N/Z = 1.51), also stabilizing.
Critical Evaluation

Our textbook shows alpha decay improves stability by reducing excess nucleons, refuting the claim.

Question 4:
The half-life of Carbon-14 is 5730 years. Discuss its application in archaeology and compare its decay with a medical isotope like Technetium-99m (half-life: 6 hours).
Answer:
Case Deconstruction

Half-life determines the decay rate of isotopes like Carbon-14 and Technetium-99m.

Theoretical Application
  • Carbon-14 dates fossils (e.g., 50,000-year-old bones).
  • Technetium-99m is used in scans due to its short half-life, minimizing radiation exposure.
Critical Evaluation

We studied that long half-lives suit archaeology, while short ones are safer for medical imaging.

Question 5:
In a nuclear reactor, moderators and control rods play crucial roles. Explain their functions and why materials like graphite and cadmium are chosen for these purposes.
Answer:
Case Deconstruction

Moderators slow down fast neutrons to thermal energies for sustained fission. Control rods absorb excess neutrons to regulate the reaction.

Theoretical Application
  • Graphite is used as a moderator due to its low neutron absorption and effective slowing capability.
  • Cadmium, in control rods, has high neutron absorption cross-section, preventing chain reaction runaway.
Critical Evaluation

Our textbook shows that without moderators, fission would stop, and without control rods, the reactor could overheat. These materials ensure stability.

Question 6:
The binding energy per nucleon curve peaks at iron-56. Analyze why fusion occurs in stars for lighter nuclei and fission occurs for heavier nuclei, referencing this curve.
Answer:
Case Deconstruction

Lighter nuclei (like hydrogen) fuse to reach higher binding energy, releasing energy. Heavier nuclei (like uranium) split to move toward the peak.

Theoretical Application
  • Stars fuse hydrogen into helium, climbing the curve.
  • Fission of uranium-235 releases energy as fragments approach iron-56.
Critical Evaluation

We studied that iron-56 is the most stable. The curve explains why fusion and fission both release energy but operate on opposite sides of the peak.

Question 7:
A student claims alpha decay is 'safer' than beta decay due to lower penetration. Validate this with evidence on ionizing effects and shielding requirements.
Answer:
Case Deconstruction

Alpha particles have high ionization but low penetration, while beta particles penetrate deeper with less ionization.

Theoretical Application
  • Alpha radiation is stopped by paper but harmful if ingested.
  • Beta requires aluminum shielding due to higher penetration.
Critical Evaluation

Our textbook shows alpha is safer externally but dangerous internally. Beta’s penetration makes shielding critical, complicating safety claims.

Question 8:
Compare nuclear fission and nuclear fusion reactions in terms of energy output, conditions required, and byproducts. Use examples like uranium-235 and the sun.
Answer:
Case Deconstruction

Fission splits heavy nuclei (uranium-235) under neutron bombardment, while fusion combines light nuclei (hydrogen in the sun) at high temperatures.

Theoretical Application
  • Fission releases ~200 MeV/event; fusion releases ~26 MeV per deuterium-tritium reaction.
  • Fission produces radioactive waste; fusion yields helium.
Critical Evaluation

We studied that fusion requires extreme conditions but is cleaner. Fission is feasible now but has waste challenges.

Question 9:
In a nuclear reactor, control rods and moderators play crucial roles. Analyze how these components regulate the fission process and maintain reactor stability.
Answer:
Case Deconstruction

Control rods absorb excess neutrons to prevent uncontrolled chain reactions, while moderators slow down fast neutrons to sustain fission. Our textbook shows cadmium or boron as common control rod materials.

Theoretical Application
  • Moderators like heavy water or graphite reduce neutron kinetic energy.
  • Control rods adjust reactor power by varying neutron absorption.
Critical Evaluation

Without moderators, fast neutrons would escape without causing fission. Evidence from reactor designs confirms this balance ensures safe energy output.

Question 10:
The binding energy per nucleon curve peaks at Iron-56. Explain why fusion occurs in stars for lighter nuclei and fission for heavier ones, referencing this curve.
Answer:
Case Deconstruction

Iron-56 has maximum binding energy/nucleon (8.8 MeV), making it the most stable nucleus. We studied that lighter nuclei (e.g., hydrogen) fuse to climb the curve, releasing energy.

Theoretical Application
  • Fusion in stars combines protons into helium, moving toward the peak.
  • Heavy nuclei (e.g., uranium) fission to descend toward Iron-56.
Critical Evaluation

NASA data confirms stellar fusion aligns with the curve. This explains energy release patterns in both processes.

Question 11:
A student claims nuclear density is constant for all nuclei. Validate this using the nuclear radius formula (R = R0A1/3) and provide two examples.
Answer:
Case Deconstruction

Nuclear density (ρ) = mass/volume. Since volume ∝ A (mass number) and mass ∝ A, ρ remains constant. Our textbook shows R0 ≈ 1.2 fm.

Theoretical Application
  • For Carbon-12: R ≈ 2.7 fm, ρ ≈ 2.3×1017 kg/m³.
  • For Uranium-238: R ≈ 7.4 fm, same ρ.
Critical Evaluation

This uniformity confirms nuclei are incompressible, as evidenced by electron scattering experiments.

Question 12:
Compare alpha, beta, and gamma decay in terms of penetrating power and ionizing ability. Support with a table if necessary.
Answer:
Case Deconstruction

Alpha particles (He nuclei) are least penetrating but highly ionizing, while gamma rays penetrate deeply with minimal ionization. Beta particles (electrons) exhibit intermediate properties.

Theoretical Application
DecayPenetrationIonization
AlphaLow (paper)High
BetaModerate (aluminum)Medium
GammaHigh (lead)Low
Critical Evaluation

Radiation shielding strategies rely on these differences, as seen in nuclear medicine protocols.

Question 13:
A radioactive isotope X has a half-life of 10 days. A sample initially contains 8 × 10²³ nuclei of X.

(a) Calculate the number of nuclei remaining after 30 days.

(b) If the decay constant of another isotope Y is twice that of X, compare their half-lives.

Answer:

(a) To find the number of nuclei remaining after 30 days:


Given: Half-life of X (T½) = 10 days, Initial nuclei (N0) = 8 × 10²³.
Total time (t) = 30 days.
Number of half-lives (n) = t / T½ = 30 / 10 = 3.
Remaining nuclei (N) = N0 × (1/2)n = 8 × 10²³ × (1/2)3 = 8 × 10²³ × 1/8 = 1 × 10²³ nuclei.

(b) Comparison of half-lives:


Decay constant (λ) is inversely proportional to half-life (T½).
Given: λY = 2λX.
Since T½ ∝ 1/λ, T½ of Y will be half of X.
Thus, T½ of Y = 5 days (since X has 10 days).
Question 14:
In a nuclear reactor, U-235 undergoes fission, releasing 200 MeV of energy per fission event.

(a) Calculate the energy released in joules when 1 kg of U-235 undergoes complete fission.

(b) Discuss one advantage and one disadvantage of nuclear energy over fossil fuels.

Answer:

(a) Energy released from 1 kg of U-235:


Given: Energy per fission = 200 MeV = 200 × 1.6 × 10-13 J = 3.2 × 10-11 J.
Number of U-235 atoms in 1 kg:
Avogadro's number (NA) = 6.022 × 10²³ atoms/mol.
Molar mass of U-235 = 235 g/mol.
Number of moles in 1 kg = 1000 g / 235 g/mol ≈ 4.255 mol.
Total atoms = 4.255 × 6.022 × 10²³ ≈ 2.56 × 10²⁴ atoms.
Total energy = 2.56 × 10²⁴ × 3.2 × 10-11 J ≈ 8.19 × 1013 J.

(b) Advantages and disadvantages:


  • Advantage: Nuclear energy produces significantly less greenhouse gases compared to fossil fuels, reducing environmental pollution.
  • Disadvantage: Nuclear waste is highly radioactive and requires careful long-term storage, posing environmental and health risks.
Question 15:
A radioactive isotope X has a half-life of 5 days. A sample initially contains 1000 nuclei of X.

(a) Calculate the number of nuclei remaining after 15 days.

(b) If the decay constant of another isotope Y is twice that of X, compare their half-lives.

Answer:

(a) To find the number of nuclei remaining after 15 days:


Given: Initial nuclei (N0) = 1000, Half-life (T1/2) = 5 days, Total time (t) = 15 days.
Number of half-lives (n) = t / T1/2 = 15 / 5 = 3.
Remaining nuclei (N) = N0 × (1/2)n = 1000 × (1/2)3 = 1000 × 1/8 = 125 nuclei.

(b) Comparison of half-lives:


Decay constant (λ) of Y = 2 × λ of X.
Since T1/2 = ln(2) / λ, T1/2 of Y = (ln(2) / 2λ) = ½ × T1/2 of X.
Thus, half-life of Y is half of X.
Question 16:
In a nuclear reactor, U-235 undergoes fission, releasing 200 MeV of energy per reaction.

(a) Calculate the energy released in joules when 1 kg of U-235 undergoes complete fission.

(b) Explain why control rods are essential in a nuclear reactor.

Answer:

(a) Energy released per fission = 200 MeV = 200 × 1.6 × 10-13 J = 3.2 × 10-11 J.
Number of U-235 atoms in 1 kg = (6.022 × 1023) / 235 ≈ 2.56 × 1024.
Total energy released = (3.2 × 10-11) × (2.56 × 1024) ≈ 8.19 × 1013 J.


(b) Control rods (e.g., cadmium or boron) absorb excess neutrons, ensuring the chain reaction remains steady.

  • Prevents runaway reactions by regulating neutron population.
  • Maintains criticality for sustained energy output.
  • Ensures safety by shutting down the reactor during emergencies.
Question 17:
A radioactive isotope X has a half-life of 5 days. A sample initially contains 8000 nuclei of X.

(a) Calculate the number of nuclei remaining after 15 days.

(b) If the decay constant of another isotope Y is twice that of X, compare their half-lives.

Answer:

(a) To find the number of nuclei remaining after 15 days:


Given: Initial number of nuclei (N0) = 8000, Half-life (T1/2) = 5 days, Total time (t) = 15 days.
Number of half-lives (n) = t / T1/2 = 15 / 5 = 3.
Remaining nuclei (N) = N0 × (1/2)n = 8000 × (1/2)3 = 8000 × 1/8 = 1000 nuclei.

(b) The decay constant (λ) is inversely proportional to the half-life (T1/2).


Given: λY = 2 × λX.
Since T1/2 ∝ 1/λ, T1/2 of Y will be half of T1/2 of X.
Thus, Y has a shorter half-life compared to X.
Question 18:
In a nuclear reaction, a neutron is absorbed by a U-235 nucleus, leading to the formation of Ba-141 and Kr-92 along with the release of three neutrons.

(a) Identify the type of nuclear reaction and write the balanced equation.

(b) Explain why such reactions release a large amount of energy.

Answer:

(a) This is an example of nuclear fission. The balanced equation is:


U-235 + nBa-141 + Kr-92 + 3n + energy.

(b) Nuclear fission releases a large amount of energy due to the mass defect.


The total mass of the products is slightly less than the mass of the reactants.
This lost mass is converted into energy as per Einstein's equation E = mc2.
Since c (speed of light) is very large, even a small mass defect results in a tremendous amount of energy.
Question 19:
A nuclear reactor uses Uranium-235 as fuel and operates at a power output of 1000 MW. Assuming the energy released per fission of Uranium-235 is 200 MeV, calculate the number of fissions occurring per second in the reactor. Also, discuss the role of control rods and moderator in maintaining a sustained chain reaction.
Answer:

To calculate the number of fissions per second:


Power output = 1000 MW = 1000 × 106 W = 1000 × 106 J/s
Energy per fission = 200 MeV = 200 × 1.6 × 10-13 J = 3.2 × 10-11 J
Number of fissions per second = Power output / Energy per fission
= 1000 × 106 / 3.2 × 10-11
= 3.125 × 1019 fissions/s

Control rods (e.g., cadmium or boron) absorb excess neutrons to regulate the chain reaction and prevent it from becoming uncontrollable.

The moderator (e.g., heavy water or graphite) slows down fast neutrons to thermal energies, increasing the likelihood of further fission events.

Question 20:
In a radioactive decay process, a nucleus X decays to nucleus Y with a half-life of 10 days. If initially, there are 8000 nuclei of X, calculate the number of nuclei of X remaining after 30 days. Also, explain why the mass number and atomic number of Y will differ from X depending on the type of decay (α or β).
Answer:

Number of half-lives in 30 days = 30 / 10 = 3 half-lives
Remaining nuclei = Initial nuclei × (1/2)n
= 8000 × (1/2)3
= 8000 × 1/8
= 1000 nuclei of X

In α-decay:

  • Mass number of Y decreases by 4.
  • Atomic number of Y decreases by 2.
In β-decay:
  • Mass number remains unchanged.
  • Atomic number increases by 1 (for β-) or decreases by 1 (for β+).
This change occurs because α-particles carry away mass and charge, while β-decay involves the conversion of a neutron or proton within the nucleus.

Question 21:
A radioactive isotope X has a half-life of 5 days. A sample initially contains 8 × 10²³ nuclei of X.

(a) Calculate the number of nuclei remaining after 15 days.

(b) If the decay produces Y as a stable daughter nucleus, determine the number of Y nuclei formed in this time.

Answer:

(a) Number of nuclei remaining after 15 days:


The half-life (T½) of X is 5 days. Total time elapsed = 15 days.
Number of half-lives (n) = Total time / Half-life = 15 / 5 = 3.
Using the decay formula: N = N0 × (1/2)n, where N0 = initial nuclei.
N = 8 × 10²³ × (1/2)³ = 8 × 10²³ × 1/8 = 1 × 10²³ nuclei.

(b) Number of Y nuclei formed:


Since Y is stable, the number of Y nuclei formed equals the number of X nuclei decayed.
Decayed nuclei = N0 - N = 8 × 10²³ - 1 × 10²³ = 7 × 10²³ nuclei.
Question 22:
In a nuclear reactor, U-235 undergoes fission, releasing 200 MeV of energy per reaction. A power plant generates 800 MW of electricity with 30% efficiency.

(a) Calculate the number of U-235 nuclei fissioned per second.

(b) If the plant operates for 24 hours, determine the total mass of U-235 consumed (given: 1 u = 931.5 MeV/c², mass of U-235 ≈ 235 u).

Answer:

(a) Number of U-235 nuclei fissioned per second:


Total energy output = 800 MW = 800 × 10⁶ J/s.
Efficiency = 30%, so energy input = (800 × 10⁶) / 0.30 ≈ 2.67 × 10⁹ J/s.
Energy per fission = 200 MeV = 200 × 1.6 × 10⁻¹³ J ≈ 3.2 × 10⁻¹¹ J.
Number of fissions per second = Energy input / Energy per fission = 2.67 × 10⁹ / 3.2 × 10⁻¹¹ ≈ 8.34 × 10¹⁹ nuclei/s.

(b) Total mass of U-235 consumed in 24 hours:


Total fissions in 24 hours = 8.34 × 10¹⁹ × 3600 × 24 ≈ 7.21 × 10²⁴ nuclei.
Mass of one U-235 nucleus = 235 u = 235 × 931.5 MeV/c² ≈ 3.9 × 10⁻²⁵ kg.
Total mass consumed = 7.21 × 10²⁴ × 3.9 × 10⁻²⁵ ≈ 2.81 kg.
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