Dual Nature of Radiation and Matter – CBSE NCERT Study Resources

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12th - Physics

Dual Nature of Radiation and Matter

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Overview of the Chapter: Dual Nature of Radiation and Matter

This chapter explores the dual nature of radiation and matter, a fundamental concept in modern physics. It discusses how particles like electrons exhibit wave-like properties (wave-particle duality) and how electromagnetic radiation can behave as both waves and particles. Key topics include the photoelectric effect, de Broglie's hypothesis, and Davisson-Germer experiment.

Wave-Particle Duality: The concept that every particle or quantum entity exhibits both particle and wave properties.

Photoelectric Effect

The photoelectric effect refers to the emission of electrons from a metal surface when light of a suitable frequency is incident on it. Key observations include:

  • Emission is instantaneous.
  • Kinetic energy of emitted electrons depends on the frequency of incident light, not its intensity.
  • Below a threshold frequency, no emission occurs regardless of intensity.

Work Function (Φ): The minimum energy required to eject an electron from a metal surface.

Einstein’s Photoelectric Equation

Einstein explained the photoelectric effect using Planck’s quantum theory:

Energy of a photon (E) = hν

According to Einstein: hν = Φ + Kmax, where Kmax is the maximum kinetic energy of emitted electrons.

De Broglie’s Hypothesis

Louis de Broglie proposed that matter also exhibits wave-like properties. The wavelength (λ) associated with a particle is given by:

λ = h/p, where p is the momentum of the particle.

Matter Waves: The wave nature associated with moving particles, as proposed by de Broglie.

Davisson-Germer Experiment

This experiment confirmed the wave nature of electrons by observing diffraction patterns when electrons were scattered by a nickel crystal. The results aligned with de Broglie’s hypothesis.

Applications

The dual nature of radiation and matter has applications in:

  • Electron microscopes (using wave properties of electrons).
  • Photocells (based on the photoelectric effect).
  • Quantum mechanics and modern technology.

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define work function of a metal.
Answer:

Minimum energy needed to eject an electron from a metal surface.

Question 2:
What is the unit of stopping potential?
Answer:

Volt (V).

Question 3:
Name the experiment that confirms the wave nature of electrons.
Answer:

Davisson-Germer experiment.

Question 4:
State the relation between de Broglie wavelength and kinetic energy of an electron.
Answer:

λ = h/√(2mE), where E is kinetic energy.

Question 5:
What happens to the photoelectric current if intensity of light increases?
Answer:

Current increases proportionally.

Question 6:
Define threshold frequency in photoelectric effect.
Answer:

Minimum frequency needed to eject electrons from a metal.

Question 7:
What is the value of Planck's constant (approx.)?
Answer:

6.63 × 10-34 Js.

Question 8:
Why does classical wave theory fail to explain photoelectric effect?
Answer:

It cannot explain threshold frequency and instant emission.

Question 9:
What is the nature of matter waves?
Answer:

Probability waves associated with moving particles.

Question 10:
How does stopping potential vary with light frequency?
Answer:

Increases linearly with frequency.

Question 11:
Name the phenomenon where light behaves as particles.
Answer:

Photoelectric effect.

Question 12:
What is the photoelectric equation given by Einstein?
Answer:

K.E.max = hν - φ.

Question 13:
Define quantum efficiency of a photoelectric device.
Answer:

Ratio of emitted electrons to incident photons.

Question 14:
What is the de Broglie wavelength of an electron accelerated by 100V?
Answer:

1.23 Å.

Question 15:
What is the significance of the threshold frequency in the photoelectric effect?
Answer:

The threshold frequency is the minimum frequency of incident light below which no photoelectrons are emitted, regardless of intensity. It depends on the work function of the metal.

Question 16:
State the de Broglie wavelength formula for a particle.
Answer:

The de Broglie wavelength (λ) is given by:
λ = h / p
where h is Planck's constant and p is the momentum of the particle.

Question 17:
Why does the photoelectric effect support the particle nature of light?
Answer:

The photoelectric effect shows that light interacts with matter in discrete packets (photons). The instantaneous emission of electrons and dependence on frequency (not intensity) align with particle behavior.

Question 18:
What happens to the kinetic energy of emitted photoelectrons if the intensity of incident light is doubled?
Answer:

The kinetic energy of photoelectrons remains unchanged because it depends only on the frequency of light, not intensity. However, the number of emitted electrons increases.

Question 19:
Name the experiment that confirmed the wave nature of electrons.
Answer:

The Davisson-Germer experiment confirmed the wave nature of electrons by observing diffraction patterns when electrons were scattered by a nickel crystal.

Question 20:
How does the stopping potential vary with the frequency of incident light in the photoelectric effect?
Answer:

The stopping potential increases linearly with the frequency of incident light, as described by the equation:
eV₀ = hν - Φ
where V₀ is the stopping potential.

Question 21:
What is the physical meaning of the wave-particle duality?
Answer:

Wave-particle duality means that particles (like electrons) exhibit both wave-like (interference, diffraction) and particle-like (localized energy, momentum) properties depending on the experiment.

Question 22:
Calculate the de Broglie wavelength of an electron accelerated through a potential of 100 V.
Answer:

Using λ = h / √(2meV):
λ = (6.63 × 10⁻³⁴) / √(2 × 9.11 × 10⁻³¹ × 1.6 × 10⁻¹⁹ × 100)
λ ≈ 1.23 Å (angstroms).

Question 23:
Why can't the photoelectric effect be explained by classical wave theory?
Answer:

Classical wave theory predicts:

  • Energy depends on intensity, not frequency.
  • No threshold frequency.
  • Delayed emission (not instantaneous).
These contradict experimental observations.

Question 24:
What is the unit of Planck's constant?
Answer:

Planck's constant (h) has units of joule-seconds (J·s) or electron volt-seconds (eV·s).

Question 25:
How does the de Broglie wavelength change if the kinetic energy of a particle is doubled?
Answer:

Since λ ∝ 1/√(KE), doubling the kinetic energy reduces the de Broglie wavelength by a factor of √2.

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
What is the significance of threshold frequency in the photoelectric effect?
Answer:

The threshold frequency (ν₀) is the minimum frequency of incident light below which no photoelectrons are emitted, regardless of intensity.
It is related to the work function by Φ = hν₀, where h is Planck's constant.

Question 2:
State de Broglie's hypothesis.
Answer:

De Broglie proposed that all moving particles exhibit wave-like properties. The wavelength (λ) associated with a particle is given by:
λ = h/p, where h is Planck's constant and p is the momentum of the particle.

Question 3:
Calculate the de Broglie wavelength of an electron accelerated through a potential of 100V.
Answer:

Given: V = 100V, m = 9.1 × 10⁻³¹ kg, e = 1.6 × 10⁻¹⁹ C, h = 6.63 × 10⁻³⁴ Js.
Step 1: Find kinetic energy: K = eV = 100 eV.
Step 2: Convert to joules: K = 100 × 1.6 × 10⁻¹⁹ = 1.6 × 10⁻¹⁷ J.
Step 3: Calculate momentum: p = √(2mK) = √(2 × 9.1 × 10⁻³¹ × 1.6 × 10⁻¹⁷).
Step 4: Compute wavelength: λ = h/p ≈ 1.23 Å.

Question 4:
What is the stopping potential in the photoelectric effect?
Answer:

The stopping potential (V₀) is the minimum reverse potential applied to stop the fastest photoelectrons.
It measures the maximum kinetic energy of emitted electrons: Kmax = eV₀.

Question 5:
How does the intensity of light affect the photoelectric current?
Answer:

Higher intensity increases the number of photons striking the surface per second, leading to more ejected electrons.
Thus, photoelectric current increases linearly with intensity, provided frequency is above threshold.

Question 6:
Explain why wave theory fails to explain the photoelectric effect.
Answer:

Wave theory predicts:

  • Energy depends on intensity, not frequency (contrary to observations).
  • Emission should occur at all frequencies given enough time (no threshold frequency).
  • Energy absorption should be gradual, not instantaneous.
These discrepancies led to the photon concept.

Question 7:
What is the relation between the kinetic energy of photoelectrons and the frequency of incident light?
Answer:

The maximum kinetic energy (Kmax) of photoelectrons is given by:
Kmax = hν - Φ, where ν is the frequency and Φ is the work function.
This shows a linear dependence on frequency.

Question 8:
Define matter waves. Give an example where they are significant.
Answer:

Matter waves are the wave-like behavior exhibited by particles, as proposed by de Broglie.
Example: Electron diffraction in crystals (Davisson-Germer experiment) confirms their wave nature.

Question 9:
Why are photons considered quanta of light?
Answer:

Photons are discrete packets of light energy (E = hν), where energy is quantized.
They explain phenomena like the photoelectric effect, where energy transfer happens in fixed amounts, not continuously.

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
Define work function of a metal. How does it relate to the photoelectric effect?
Answer:

The work function (Φ) of a metal is the minimum energy required to eject an electron from its surface. It is a characteristic property of the material.

In the photoelectric effect, when light of frequency ν strikes the metal surface, electrons are emitted only if the photon energy () exceeds the work function (hν ≥ Φ). The excess energy appears as the kinetic energy of the emitted electron.

Question 2:
State de Broglie’s hypothesis. Write the expression for the de Broglie wavelength associated with a moving electron.
Answer:

De Broglie’s hypothesis states that all matter exhibits wave-like properties. A moving particle has an associated wavelength called the de Broglie wavelength.

The expression is:
λ = h / p
where λ is the wavelength, h is Planck’s constant, and p is the momentum of the particle (for an electron, p = mv).

Question 3:
Explain why the photoelectric effect cannot be explained by the wave theory of light.
Answer:

The wave theory predicts:

  • Energy depends on intensity (amplitude), not frequency.
  • Electrons should be emitted at all frequencies if given enough time.

However, in the photoelectric effect:

  • Emission depends on frequency, not intensity.
  • No emission below the threshold frequency, regardless of intensity.
  • Electrons are emitted instantaneously.

These observations align with Einstein’s particle (photon) theory, not wave theory.

Question 4:
What is the significance of Davisson-Germer experiment?
Answer:

The Davisson-Germer experiment confirmed the wave nature of electrons, supporting de Broglie’s hypothesis.

Key observations:

  • Electrons were diffracted by a nickel crystal, producing an interference pattern.
  • The measured wavelength matched de Broglie’s formula (λ = h/p).

This established that particles like electrons exhibit wave-particle duality.

Question 5:
Differentiate between photoelectric emission and thermionic emission.
Answer:

Photoelectric emission:

  • Occurs when light of suitable frequency strikes a metal surface.
  • Depends on photon energy (hν ≥ Φ).
  • Instantaneous process.

Thermionic emission:

  • Occurs when a metal is heated to high temperatures.
  • Depends on thermal energy overcoming the work function.
  • Gradual process as temperature increases.
Question 6:
An electron is accelerated through a potential difference of 100 V. Calculate its de Broglie wavelength.
Answer:

Given: Potential difference (V) = 100 V.

Steps:


1. Kinetic energy of electron: K.E. = eV = 1.6 × 10-19 × 100 = 1.6 × 10-17 J.
2. Momentum (p) = √(2meK.E.) = √(2 × 9.1 × 10-31 × 1.6 × 10-17) ≈ 1.7 × 10-23 kg m/s.
3. de Broglie wavelength: λ = h/p = (6.6 × 10-34) / (1.7 × 10-23) ≈ 0.123 nm.

The wavelength is approximately 0.123 nm.

Question 7:
Define work function of a metal. How does it relate to the threshold frequency in the photoelectric effect?
Answer:

The work function (Φ) of a metal is the minimum energy required to eject an electron from its surface. It is a characteristic property of the material.


Mathematically, it relates to the threshold frequency (ν₀) as:
Φ = hν₀, where h is Planck's constant.
If the incident light's frequency is below ν₀, no photoelectric emission occurs, regardless of intensity.

Question 8:
Explain why the photoelectric effect supports the particle nature of light.
Answer:

The photoelectric effect demonstrates light's particle nature because:

  • Electrons are ejected instantaneously, contradicting wave theory's energy accumulation prediction.
  • Kinetic energy of emitted electrons depends on frequency, not intensity, aligning with Einstein's photon energy equation (E = hν).
  • No emission below threshold frequency, proving energy quantization.
Question 9:
Derive the expression for the de Broglie wavelength of an electron accelerated through a potential difference V.
Answer:

Starting from de Broglie's equation:
λ = h/p, where p is momentum.

For an electron with kinetic energy eV:
p = √(2m_e eV)

Substituting:
λ = h/√(2m_e eV)

Final form:
λ = 12.27/√V Å (for V in volts).

Question 10:
State two observations from Davisson-Germer experiment that confirm wave nature of matter.
Answer:

Key observations:

  • Intensity peaks at specific angles, showing constructive interference (a wave property).
  • The measured wavelength matched de Broglie's prediction (λ = h/p), validating matter waves.

This proved electrons exhibit diffraction, a phenomenon exclusive to waves.

Question 11:
How does the stopping potential vary with the frequency of incident light in photoelectric effect? Justify mathematically.
Answer:

The stopping potential (V₀) increases linearly with frequency (ν):


From Einstein's equation:
eV₀ = hν - Φ

Rearranged:
V₀ = (h/e)ν - Φ/e

This shows V₀ vs ν is a straight line with slope h/e, independent of light intensity.

Question 12:
Differentiate between photoelectric effect and thermionic emission based on energy source and temperature dependence.
Answer:

Photoelectric effect:

  • Energy source: Photons (hν ≥ Φ)
  • Independent of temperature

Thermionic emission:
  • Energy source: Thermal energy (kT)
  • Highly temperature-dependent (exponential increase with T)

Both release electrons but via fundamentally different mechanisms.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Explain the photoelectric effect and derive Einstein’s photoelectric equation using the quantum theory of light.
Answer:
Theoretical Framework

We studied that the photoelectric effect involves emission of electrons when light of suitable frequency strikes a metal surface. Einstein proposed that light consists of discrete packets called photons, each carrying energy E = hν.

Evidence Analysis
  • Einstein’s equation: K.E.max = hν - φ, where φ is work function.
  • Threshold frequency (ν0) is minimum frequency for electron emission.
Critical Evaluation

This theory resolved the wave-particle duality debate. Experimental data (e.g., Millikan’s experiment) validated it.

Future Implications

Applications include solar cells and photodetectors, leveraging quantum principles.

Question 2:
Compare the wave nature and particle nature of light with experimental evidence supporting each.
Answer:
Theoretical Framework

Light exhibits dual nature: wave (interference, diffraction) and particle (photoelectric effect, Compton scattering).

Evidence Analysis
  • Wave: Young’s double-slit experiment shows interference patterns.
  • Particle: Photoelectric effect confirms quantized energy (photons).
Critical Evaluation

De Broglie’s hypothesis (λ = h/p) unified both behaviors. Modern tech like electron microscopy relies on this duality.

Future Implications

Quantum computing exploits wave-particle duality for advanced processing.

Question 3:
Describe Davisson-Germer experiment and its role in confirming the de Broglie hypothesis.
Answer:
Theoretical Framework

De Broglie proposed matter waves (λ = h/mv). Davisson-Germer demonstrated electron diffraction, confirming wave nature.

Evidence Analysis
  • Electrons scattered by nickel crystal produced interference patterns.
  • Measured wavelength matched de Broglie’s equation.
Critical Evaluation

This experiment validated quantum mechanics. Textbook data shows 54° angle for peak intensity.

Future Implications

Led to technologies like electron microscopes, enabling atomic-scale imaging.

Question 4:
Explain how the stopping potential in photoelectric effect depends on frequency and intensity of light.
Answer:
Theoretical Framework

Stopping potential (V0) is the voltage needed to halt photoelectrons. It depends on frequency (ν) but not intensity.

Evidence Analysis
  • V0 ∝ ν (linear relation per Einstein’s equation).
  • Intensity increases photocurrent but not V0, as K.E.max depends on ν.
Critical Evaluation

NCERT graphs show V0 vs ν is a straight line, supporting quantum theory.

Future Implications

Used in designing light sensors with frequency-selective response.

Question 5:
Discuss the significance of work function in photoelectric emission with two examples of its practical applications.
Answer:
Theoretical Framework

Work function (φ) is minimum energy to eject electrons from a metal. It’s material-specific (e.g., φ for cesium is 2.14 eV).

Evidence Analysis
  • Low-φ materials (e.g., alkali metals) emit electrons under visible light.
  • High-φ metals (e.g., tungsten) need UV light.
Critical Evaluation

Photocells and night-vision devices use low-φ materials for efficiency.

Future Implications

Research focuses on φ engineering for renewable energy tech like photocatalysts.

Question 6:
Explain the photoelectric effect and derive Einstein's photoelectric equation. Discuss how this supports the particle nature of light.
Answer:
Theoretical Framework

The photoelectric effect involves emission of electrons when light strikes a metal surface. Einstein proposed that light consists of discrete packets called photons, each carrying energy E = hν.

Evidence Analysis
  • Einstein's equation: K.E.max = hν - φ, where φ is work function.
  • Threshold frequency (ν0) validates quantum theory, as emission occurs only if ν ≥ ν0.
Critical Evaluation

Classical wave theory fails to explain instantaneous emission and ν0, while photon theory aligns with observations.

Future Implications

This concept underpins solar cells and quantum mechanics. Example: Photocells use this principle for light detection.

Question 7:
Describe de Broglie’s hypothesis and derive the expression for the wavelength of matter waves. How does this establish wave-particle duality?
Answer:
Theoretical Framework

De Broglie proposed that particles like electrons exhibit wave-like properties, with wavelength λ = h/p, where p is momentum.

Evidence Analysis
  • Davisson-Germer experiment confirmed electron diffraction, validating λ = h/mv.
  • Electron microscopes leverage this principle for high-resolution imaging.
Critical Evaluation

Duality bridges classical and quantum physics. Macroscopic objects have negligible λ due to large mass.

Future Implications

Applications include nanotechnology and quantum computing. Example: TEM uses electron waves for atomic-scale imaging.

Question 8:
Compare the characteristics of photons and electrons in tabular form. Analyze how their dual nature is experimentally verified.
Answer:
Theoretical Framework

Both photons and electrons exhibit wave-particle duality, but differ in rest mass and charge.

Evidence Analysis
PropertyPhotonElectron
Rest MassZero9.1×10-31 kg
ChargeNeutral-1.6×10-19 C
Critical Evaluation

Photoelectric effect (photon) and electron diffraction (electron) confirm duality.

Future Implications

Dual behavior is foundational for quantum technologies like LEDs and electron microscopy.

Question 9:
Explain how the stopping potential in the photoelectric experiment depends on the frequency of incident light. Support your answer with a graph.
Answer:
Theoretical Framework

Stopping potential (V0) is the minimum voltage to halt photoelectrons, given by eV0 = hν - φ.

Evidence Analysis
  • Graph of V0 vs ν shows a linear slope h/e, intersecting ν-axis at ν0.
  • Example: For sodium, ν0 ≈ 5.5×1014 Hz.
Critical Evaluation

The linearity confirms quantization, as V0 ∝ ν.

Future Implications

This principle aids in designing light sensors. [Diagram: V0 vs ν graph with labeled axes]

Question 10:
Compare Davisson-Germer experiment and de Broglie hypothesis in establishing the wave nature of matter. Provide mathematical insights.
Answer:
Theoretical Framework

De Broglie proposed λ = h/p for particles, while Davisson-Germer demonstrated electron diffraction, confirming wave-particle duality.

Evidence Analysis
  • Davisson-Germer showed constructive interference at specific angles, matching Bragg's law: nλ = 2d sinθ.
  • Electron wavelength calculated from accelerating voltage agreed with de Broglie’s formula.
Critical Evaluation

This unified microscopic particle/wave behavior. Example: Electron microscopes leverage this duality.

Future Implications

Advances in quantum computing rely on manipulating matter waves.

Question 11:
Analyze how stopping potential in photoelectric experiments varies with light frequency and intensity. Support with graphical analysis.
Answer:
Theoretical Framework

Stopping potential (V0) measures the energy needed to halt emitted electrons. It depends on frequency (ν) but not intensity.

Evidence Analysis
  • Graph of V0 vs ν is linear: V0 = (h/e)ν - φ/e, with slope h/e.
  • Intensity increases current but not V0, proving light's quantized nature.
Critical Evaluation

This contradicts classical predictions. Example: UV light triggers emission even at low intensity.

Future Implications

Precision instruments like photomultipliers use these principles.

Question 12:
Describe how wave-particle duality resolves the limitations of classical physics in explaining blackbody radiation and atomic spectra.
Answer:
Theoretical Framework

Classical theories failed to explain discrete atomic spectra and blackbody curves. Quantum theory introduced dual behavior.

Evidence Analysis
  • Planck’s quantum hypothesis (E = nhν) resolved blackbody radiation.
  • Bohr’s model used quantized electron orbits (L = nħ) to predict spectral lines.
Critical Evaluation

Duality bridges wave interference and particle collisions. Example: LASERs rely on stimulated emission.

Future Implications

Nanotechnology exploits wave-particle properties for material design.

Question 13:
Explain the photoelectric effect and derive Einstein's photoelectric equation. Discuss how this experiment validates the particle nature of light.
Answer:
Theoretical Framework

The photoelectric effect occurs when light of sufficient frequency ejects electrons from a metal surface. Einstein proposed that light consists of discrete packets of energy called photons, each with energy E = hν.

Evidence Analysis
  • Einstein's equation: K.E.max = hν - φ, where φ is the work function.
  • Threshold frequency (ν0) confirms light's particle nature, as energy depends on frequency, not intensity.
Critical Evaluation

Classical wave theory failed to explain instantaneous emission and K.E. dependence on ν. Millikan's experiments validated Einstein's theory.

Future Implications

This concept underpins solar cells and quantum mechanics. For example, photocells use this principle to convert light to electricity.

Question 14:
Describe de Broglie's hypothesis and derive the expression for the wavelength of matter waves. How does this support the dual nature of matter?
Answer:
Theoretical Framework

De Broglie proposed that matter exhibits wave-particle duality, with wavelength λ = h/p, where p is momentum.

Evidence Analysis
  • For an electron accelerated through potential V: λ = h/√(2meV).
  • Davisson-Germer experiment confirmed electron diffraction, validating wave nature.
Critical Evaluation

This unified particle and wave theories. Macroscopic objects have negligible λ due to large mass, explaining why we don't observe wave effects daily.

Future Implications

Electron microscopes leverage this principle for atomic-scale imaging. For example, TEMs achieve resolutions beyond optical microscopes.

Question 15:
Compare the characteristics of photons and electrons in the context of wave-particle duality. Provide experimental evidence for each.
Answer:
Theoretical Framework

Both photons and electrons exhibit dual nature: photons as EM waves/particles, electrons as matter/waves.

Evidence Analysis
PhotonElectron
Photoelectric effect (particle)Davisson-Germer (wave)
Double-slit interference (wave)Cloud chamber tracks (particle)
Critical Evaluation

Photons are massless with E=hν, while electrons have rest mass and λ=h/mv. Both require quantum mechanics for full description.

Future Implications

This duality is fundamental to technologies like LEDs (photons) and electron microscopy (electrons).

Question 16:
Analyze how the stopping potential in photoelectric experiments depends on the frequency of incident radiation. What does this reveal about the quantum nature of energy?
Answer:
Theoretical Framework

Stopping potential (V0) is the minimum voltage to halt photoelectrons, related to their K.E.max by eV0 = hν - φ.

Evidence Analysis
  • Graph of V0 vs ν is linear with slope h/e, confirming quantized energy.
  • Example: For sodium (φ=2.28eV), V0=0 at ν0=5.5×1014Hz.
Critical Evaluation

This directly proves energy quantization, as classical theory predicted V0 should depend on intensity, not ν.

Future Implications

Understanding this relationship enabled precise measurements of h (Planck's constant) and work functions.

Question 17:
Explain the photoelectric effect and derive Einstein’s photoelectric equation using the quantum theory of light. Discuss how this experiment validates the particle nature of light.
Answer:
Theoretical Framework

The photoelectric effect occurs when light of sufficient frequency ejects electrons from a metal surface. Einstein proposed that light consists of discrete packets called photons, each carrying energy E = hν.

Evidence Analysis
  • Einstein’s equation: Kmax = hν - φ, where Kmax is max kinetic energy of ejected electrons and φ is work function.
  • Threshold frequency (ν0) confirms light's particle nature, as energy depends on frequency, not intensity.
Critical Evaluation

Classical wave theory failed to explain instantaneous emission and Kmax independence of intensity. Quantum theory resolved these anomalies.

Future Implications

This principle underpins solar cells and photon detectors, showcasing light's dual behavior.

Question 18:
Describe Davisson-Germer’s experiment and explain how it confirmed the wave nature of matter. Include a labeled diagram of the setup.
Answer:
Theoretical Framework

Davisson-Germer demonstrated electron diffraction, proving de Broglie’s hypothesis (λ = h/p) that particles exhibit wave nature.

Evidence Analysis
  • Electrons scattered from nickel crystal showed constructive interference at specific angles, matching Bragg’s law: nλ = 2d sinθ.
  • [Diagram: Electron gun, crystal, detector setup with labeled θ and d].
Critical Evaluation

The measured λ agreed with de Broglie’s formula, rejecting classical particle-only models.

Future Implications

This experiment laid the foundation for electron microscopy and quantum mechanics.

Question 19:
Compare the wave and particle properties of electrons using de Broglie’s hypothesis and Heisenberg’s uncertainty principle. Provide two examples where each nature dominates.
Answer:
Theoretical Framework

De Broglie proposed λ = h/mv, linking momentum (particle property) to wavelength (wave property). Heisenberg’s principle (ΔxΔp ≥ h/4π) limits simultaneous precision of position (particle) and momentum (wave).

Evidence Analysis
  • Wave dominance: Electron diffraction patterns in crystals.
  • Particle dominance: Tracks in cloud chambers.
Critical Evaluation

Dual nature is context-dependent; microscopic systems (e.g., atoms) emphasize wave behavior, while macroscopic systems favor particle traits.

Future Implications

This duality is exploited in technologies like SEM (particle) and holography (wave).

Question 20:
Analyze how the stopping potential in a photoelectric experiment varies with light frequency and intensity. Support your answer with a graph of V0 vs ν.
Answer:
Theoretical Framework

Stopping potential (V0) measures the kinetic energy of photoelectrons (eV0 = Kmax). Einstein’s equation predicts V0 = (h/e)ν - φ/e.

Evidence Analysis
  • Graph: Linear V0 vs ν plot with slope h/e and x-intercept ν0 (threshold frequency).
  • V0 is frequency-dependent but intensity-independent, as Kmax ∝ ν.
Critical Evaluation

Classical theory incorrectly predicted V0 ∝ intensity. Quantum theory’s accuracy validated photon concept.

Future Implications

This principle is vital for designing light sensors with precise threshold controls.

Question 21:
Explain the photoelectric effect and derive Einstein's photoelectric equation. Discuss how this equation explains the experimental observations of the photoelectric effect.
Answer:

The photoelectric effect is a phenomenon where electrons are emitted from a metal surface when light of a suitable frequency (or wavelength) is incident on it. This effect provided strong evidence for the particle nature of light, as explained by Albert Einstein in 1905.

Einstein's photoelectric equation is derived as follows:


Energy of incident photon () = Work function (Φ) + Maximum kinetic energy of emitted electron (Kmax)

Mathematically, it is expressed as:
hν = Φ + Kmax
where:
  • h = Planck's constant
  • ν = frequency of incident light
  • Φ = work function (minimum energy required to eject an electron)
  • Kmax = ½ mv2 (maximum kinetic energy of photoelectrons)

The equation explains key experimental observations:

  • Threshold frequency: No photoelectrons are emitted if ν < ν0 (where 0 = Φ).
  • Instantaneous emission: Electrons are ejected immediately, supporting the particle nature of light.
  • Kinetic energy dependence: Kmax depends on the frequency of light, not its intensity.
  • Intensity effect: Higher intensity increases the number of photoelectrons but not their kinetic energy.

This equation was pivotal in establishing the dual nature of radiation (wave-particle duality) and laid the foundation for quantum mechanics.

Question 22:
Describe Davisson and Germer's experiment to verify the wave nature of electrons. Explain how the results support de Broglie's hypothesis.
Answer:

Davisson and Germer's experiment demonstrated the wave nature of electrons by observing diffraction patterns, similar to X-rays.

Experimental setup:

  • A beam of electrons was accelerated and directed at a nickel crystal.
  • The scattered electrons were detected at various angles.

Observations:

  • A peak in electron intensity was observed at a specific angle (50°) for a given accelerating voltage (54 V).
  • This peak corresponded to constructive interference, confirming wave-like behavior.

Support for de Broglie's hypothesis:
The wavelength calculated from the diffraction pattern matched de Broglie's equation:
λ = h/p
where p is the electron's momentum. This validated that electrons exhibit wave-particle duality.

Question 23:
Compare and contrast the wave and particle nature of light using the phenomena of interference and photoelectric effect, respectively.
Answer:

Wave nature (Interference):

  • Light exhibits interference patterns (e.g., Young's double-slit experiment), proving it behaves as a wave.
  • Constructive and destructive interference occur due to superposition of waves.

Particle nature (Photoelectric effect):

  • Light ejects electrons from a metal surface, behaving as discrete energy packets (photons).
  • Emission depends on frequency, not intensity, supporting the particle model.

Contrast:

  • Waves explain interference/diffraction, while particles explain quantized energy transfer.
  • Wave theory cannot explain the photoelectric effect, and particle theory cannot explain interference.

Together, these phenomena demonstrate the dual nature of light.

Question 24:
Explain the phenomenon of photoelectric effect with the help of Einstein's photoelectric equation. Discuss how this equation successfully explains the experimental observations of the photoelectric effect.
Answer:

The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when light of a suitable frequency is incident on it. According to Einstein's photoelectric equation:
hν = φ + K.E.max
where is the energy of the incident photon, φ is the work function of the metal (minimum energy required to eject an electron), and K.E.max is the maximum kinetic energy of the emitted electron.

This equation successfully explains the experimental observations:

  • Threshold Frequency: No photoelectric emission occurs if the frequency of light (ν) is below a certain threshold (ν0), as hν must be ≥ φ.
  • Instantaneous Emission: Electrons are emitted immediately because energy transfer occurs via photons (quantum nature).
  • Kinetic Energy Dependence: K.E.max depends only on the frequency of light, not its intensity, as per K.E.max = hν - φ.
  • Intensity Effect: Higher intensity increases the number of photons, thus increasing the number of emitted electrons but not their energy.
Einstein's theory validated the particle nature of light (wave-particle duality), a cornerstone of quantum mechanics.

Question 25:
Describe Davisson-Germer's experiment that established the wave nature of electrons. Explain how the observations support de Broglie's hypothesis of matter waves.
Answer:

Davisson-Germer's experiment (1927) demonstrated the wave nature of electrons by observing electron diffraction. The setup involved:
1. A beam of electrons accelerated through a known potential (V) was directed at a nickel crystal.
2. The scattered electrons were detected at varying angles (θ).

Key observations:

  • A peak in electron intensity was observed at θ = 50° for V = 54V, indicating constructive interference.
  • The angular dependence matched Bragg's law (nλ = 2d sinθ), confirming wave-like behavior.
This supported de Broglie's hypothesis (λ = h/p), where:
λ is the electron's wavelength,
p is its momentum (p = √(2meV)).
The calculated λ from de Broglie's formula matched the experimental value, proving electrons exhibit wave-particle duality.

This experiment was pivotal in establishing quantum mechanics, showing that matter (like electrons) has both particle and wave properties.

Question 26:
Describe Davisson-Germer experiment and explain how it provided evidence for the wave nature of matter. Include the significance of this experiment in the development of quantum mechanics.
Answer:

The Davisson-Germer experiment (1927) demonstrated the wave nature of matter by observing electron diffraction. Here’s how it worked:

1. A beam of electrons was accelerated and directed at a nickel crystal.
2. The scattered electrons were detected at varying angles, showing a peak intensity at a specific angle (θ = 50° for 54 eV electrons).
3. The wavelength (λ) calculated from the diffraction pattern matched de Broglie’s hypothesis: λ = h/p, where h is Planck’s constant and p is the electron’s momentum.

Significance:

  • Confirmed de Broglie’s matter-wave hypothesis, proving particles like electrons exhibit wave-like properties.
  • Provided direct evidence for wave-particle duality, a fundamental principle of quantum mechanics.
  • Laid the groundwork for technologies like electron microscopes, which exploit wave properties of electrons for high-resolution imaging.
This experiment bridged classical and quantum physics, emphasizing the dual behavior of matter.

Question 27:
Explain the phenomenon of photoelectric effect with the help of Einstein's photoelectric equation. Discuss the significance of work function and threshold frequency in this context.
Answer:

The photoelectric effect is the emission of electrons from a metal surface when light of suitable frequency (or wavelength) is incident on it. According to Einstein's photoelectric equation:

hν = φ + K.E.max

where:
= energy of the incident photon,
φ = work function of the metal (minimum energy required to eject an electron),
K.E.max = maximum kinetic energy of the emitted photoelectron.

The work function (φ) is a material-specific property representing the minimum energy needed to free an electron from the metal's surface. It is related to the threshold frequency (ν0) by the equation: φ = hν0. If the incident light's frequency is below ν0, no photoelectrons are emitted, regardless of intensity.

Key observations explained by this equation:

  • Photoelectric emission is instantaneous, supporting the particle nature of light.
  • Increasing light intensity increases the number of photoelectrons but not their kinetic energy.
  • Kinetic energy of photoelectrons depends only on the frequency of light, not intensity.

This phenomenon provided strong evidence for the dual nature of radiation, confirming light's particle behavior (photons) alongside its wave nature.

Question 28:
Explain the phenomenon of photoelectric effect with the help of Einstein's photoelectric equation. Discuss how this equation supports the particle nature of light.
Answer:

The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when light of a certain frequency (or higher) is incident on it. This effect cannot be explained by the wave theory of light but is successfully explained by Einstein's photoelectric equation, which is based on the particle nature of light (quantum theory).


Einstein's photoelectric equation is given by:
Kmax = hν - φ
where:

  • Kmax is the maximum kinetic energy of the emitted photoelectrons.
  • is the energy of the incident photon (h is Planck's constant, ν is the frequency of light).
  • φ is the work function of the metal (minimum energy required to eject an electron).


The equation shows that:
1. The energy of the photon () is directly proportional to its frequency, not intensity.
2. If hν < φ, no electrons are emitted, regardless of intensity, explaining the threshold frequency.
3. The kinetic energy of emitted electrons depends only on the frequency of light, not its intensity.


This supports the particle nature of light because:

  • Energy is quantized (transferred in discrete packets called photons).
  • The instantaneous emission of electrons suggests a one-to-one collision between photons and electrons.
  • The wave theory fails to explain the threshold frequency and kinetic energy dependence on frequency.


Thus, Einstein's equation experimentally validates the dual nature of light, where it behaves as a particle in the photoelectric effect.

Question 29:
Explain the photoelectric effect and derive Einstein's photoelectric equation. Discuss how this equation supports the particle nature of light.
Answer:

The photoelectric effect refers to the emission of electrons from a metal surface when light of a suitable frequency (or wavelength) is incident on it. This phenomenon cannot be explained by the wave theory of light, leading to the development of the quantum theory by Albert Einstein.

Einstein's photoelectric equation is derived as follows:
According to Einstein, light consists of discrete packets of energy called photons. The energy of each photon is given by E = hν, where h is Planck's constant and ν is the frequency of light.
When a photon strikes an electron in the metal, it transfers its energy to the electron. A part of this energy is used to overcome the work function (Φ) of the metal (minimum energy required to eject an electron), and the remaining energy appears as the kinetic energy of the emitted electron.
Thus, the equation becomes: hν = Φ + K.E.max, where K.E.max = ½ mv2 is the maximum kinetic energy of the photoelectron.

This equation supports the particle nature of light because:

  • It shows that energy is transferred in discrete packets (photons), not continuously as waves.
  • The kinetic energy of electrons depends on the frequency of light, not its intensity, which aligns with particle-like behavior.
  • The instantaneous emission of electrons contradicts the wave theory, which predicts a time delay for energy accumulation.

Applications of the photoelectric effect include solar cells, photodiodes, and light sensors, demonstrating its practical significance in modern technology.

Question 30:
Describe Davisson-Germer's experiment and explain how it provided evidence for the wave nature of matter. Include the significance of the experiment in the development of quantum mechanics.
Answer:

Davisson-Germer's experiment (1927) demonstrated the wave nature of electrons, confirming de Broglie's hypothesis that matter exhibits wave-particle duality.

Experimental Setup:
A beam of electrons was accelerated and directed at a nickel crystal. The scattered electrons were detected at various angles using a movable detector.

Observations:
At specific angles, a peak in electron intensity was observed, indicating constructive interference. The angle of maximum intensity matched the Bragg's law condition for diffraction: nλ = 2d sinθ, where λ is the de Broglie wavelength of electrons, d is the interatomic spacing in the crystal, and θ is the scattering angle.

Significance:

  • It provided direct evidence for the wave nature of matter, as the diffraction pattern could only be explained if electrons behaved as waves.
  • The measured wavelength matched de Broglie's equation λ = h/p, where p is the momentum of the electron.
  • This experiment bridged the gap between classical and quantum physics, reinforcing the concept of wave-particle duality.

Impact on Quantum Mechanics:
The experiment validated the foundational principles of quantum mechanics, leading to advancements like electron microscopy and solid-state physics. It also influenced the development of Schrödinger's wave equation, which describes the probabilistic behavior of particles at atomic scales.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
In an experiment, electrons are emitted from a metal surface when light of wavelength 400 nm is incident on it. The stopping potential is measured to be 1.2 V. Analyze the data to determine the work function of the metal and justify whether light of 550 nm can eject electrons from the same surface.
Answer:
Case Deconstruction

Given: λ = 400 nm, V0 = 1.2 V. Using Einstein's photoelectric equation: hc/λ = φ + eV0. We calculate φ ≈ 2.9 eV.

Theoretical Application

For λ = 550 nm, E = hc/λ ≈ 2.25 eV. Since E < φ, no photoelectric emission occurs.

Critical Evaluation

Our textbook shows that only photons with energy ≥ φ can eject electrons. Here, 2.25 eV < 2.9 eV confirms the prediction.

Question 2:
A student observes that increasing the intensity of light (500 nm) on a sodium surface does not change the stopping potential but increases the photocurrent. Explain this phenomenon using the particle nature of light and discuss the role of intensity.
Answer:
Case Deconstruction

The stopping potential depends on photon energy (E = hc/λ), not intensity. Higher intensity increases photon count, raising photocurrent.

Theoretical Application

We studied that each photon releases one electron if E ≥ φ. More photons ⇒ more electrons, but energy per electron remains unchanged.

Critical Evaluation

This aligns with Einstein's theory: intensity affects quantity, not energy of photons. Example: Doubling light intensity doubles photocurrent but V0 stays constant.

Question 3:
The de Broglie wavelength of an electron accelerated through 100 V is calculated to be 0.123 nm. Derive this result and compare it with the wavelength of a proton under the same potential, justifying the difference.
Answer:
Case Deconstruction

Using λ = h/√(2meV), we confirm λ ≈ 0.123 nm for electrons (m = 9.11×10-31 kg).

Theoretical Application

For protons (m = 1.67×10-27 kg), λ ≈ 0.00286 nm. The wavelength is shorter due to higher mass.

Critical Evaluation

Our textbook shows λ ∝ 1/√m. Example: Electron microscopes use this principle for higher resolution than optical microscopes.

Question 4:
A graph of kinetic energy (K.E.) of emitted electrons versus frequency (ν) of incident light shows a slope of 4.1 × 10-15 eV·s. Interpret the graph to determine Planck's constant and the threshold frequency of the metal.
Answer:
Case Deconstruction

Slope = h/e ⇒ h ≈ 6.56×10-34 J·s (close to accepted value). The x-intercept gives ν0 ≈ 5×1014 Hz.

Theoretical Application

We studied K.E. = hν - φ. The slope matches h, and ν0 = φ/h.

Critical Evaluation

This experiment validates quantum theory. Example: Different metals show parallel lines with same slope but different ν0.

Question 5:
Explain why a 10 W ultraviolet lamp emits photoelectrons from a zinc plate, while a 50 W visible lamp does not, despite higher power. Support your answer with energy calculations (φZn = 3.4 eV).
Answer:
Case Deconstruction

UV photons (λ ≈ 100 nm) have E = 12.4 eV > φZn. Visible photons (λ ≈ 500 nm) have E = 2.48 eV < φZn.

Theoretical Application

Power affects photon count, not individual energy. Even 50 W visible light cannot overcome φZn.

Critical Evaluation

Our textbook emphasizes E ≥ φ as the threshold. Example: Solar cells use UV/visible light based on material φ.

Question 6:
In an experiment, electrons are accelerated through a potential difference of 100V and directed at a nickel crystal. A sharp peak in intensity is observed at a scattering angle of 50°. Explain the significance of this observation and derive the de Broglie wavelength of the electrons.
Answer:
Case Deconstruction

The sharp peak indicates constructive interference, confirming the wave nature of electrons (Davisson-Germer experiment). Our textbook shows this validates de Broglie's hypothesis.

Theoretical Application

Using λ = h/√(2meV), where V = 100V: λ = (6.63×10-34)/√(2×9.1×10-31×1.6×10-19×100) ≈ 1.23 Å.

Critical Evaluation
  • Matches Bragg's law for nickel's interplanar spacing
  • Proves wave-particle duality for massive particles
Question 7:
A photoelectric setup uses sodium (work function = 2.3eV) illuminated by light of wavelength 400nm. Calculate the stopping potential and explain why no current flows below a certain frequency.
Answer:
Case Deconstruction

We studied that Kmax = hν - φ. For λ = 400nm, ν = c/λ ≈ 7.5×1014Hz.

Theoretical Application

E = hc/λ ≈ 3.1eV. Stopping potential V0 = (3.1-2.3)eV/e = 0.8V. Threshold frequency ν0 = φ/h ≈ 5.6×1014Hz.

Critical Evaluation
  • Below ν0, photons lack energy to eject electrons
  • Confirms Einstein's photoelectric equation
Question 8:
Compare the de Broglie wavelengths of (a) a 1kg ball moving at 10m/s and (b) an electron accelerated through 100V. Analyze the implications of this comparison.
Answer:
Case Deconstruction

λ = h/p. For the ball: λ ≈ 6.6×10-35m (undetectable). For electron: λ ≈ 1.23Å (measurable).

Theoretical Application
  • Macroscopic objects have negligible wavelengths
  • Quantum effects dominate at atomic scales
Critical Evaluation

Our textbook shows this explains why we don't observe wave nature in everyday objects, while it's significant for electrons in crystals.

Question 9:
A modern electron microscope uses 50keV electrons. Justify why electrons are preferred over visible light and calculate the theoretical resolution limit.
Answer:
Case Deconstruction

Resolution ≈ λ/2. Visible light (λ ≈ 500nm) cannot resolve atomic structures (≈Å scale).

Theoretical Application

For 50keV electrons: λ = h/√(2meE) ≈ 0.0055nm. Theoretical resolution ≈ 0.00275nm.

Critical Evaluation
  • Electrons provide 105× better resolution
  • Practical limits occur due to lens aberrations
Question 10:
In an experiment, electrons are accelerated through a potential difference of 100V and directed at a nickel crystal. A sharp peak in intensity is observed at a scattering angle of 50°. Explain the phenomenon and derive the de Broglie wavelength of these electrons.
Answer:
Case Deconstruction

We studied that when high-energy electrons are scattered by a crystal, they exhibit diffraction patterns due to their wave nature. The sharp peak confirms wave-particle duality.

Theoretical Application

Using de Broglie's equation λ = h/p, where p = √(2meV). For V = 100V, λ = 1.22 Å. Our textbook shows similar calculations for electron diffraction.

Critical Evaluation
  • This experiment validates wave-particle duality.
  • The wavelength matches theoretical predictions.
Question 11:
A photoelectric setup uses sodium (work function = 2.3 eV) illuminated by light of wavelength 400 nm. Calculate the stopping potential and explain why no current flows below a certain frequency.
Answer:
Case Deconstruction

We know photoelectric current depends on incident light frequency. Below threshold frequency, electrons aren't emitted.

Theoretical Application

Using Kmax = hν - φ, ν = c/λ = 7.5×1014 Hz. Kmax = 0.8 eV, so V0 = 0.8 V.

Critical Evaluation
  • Results align with Einstein's photoelectric equation.
  • Threshold frequency for Na is 5.6×1014 Hz (φ/h).
Question 12:
An electron microscope uses 50 keV electrons. Compare its resolving power with an optical microscope (λ = 500 nm) and analyze why electron microscopes can detect smaller objects.
Answer:
Case Deconstruction

Resolving power ∝ 1/λ. Electron wavelengths are much smaller than visible light.

Theoretical Application

For 50 keV electrons, λ = 0.0055 nm (using relativistic formula). Optical microscope: λ = 500 nm. Electron microscope has ≈105 times better resolution.

Critical Evaluation
  • Proves matter waves enable nanoscale imaging.
  • Limitation: Requires vacuum unlike optical microscopes.
Question 13:
When UV light of intensity I and frequency ν falls on a photosensitive surface, the photocurrent varies with applied voltage as shown in a graph. Interpret the saturation current and explain how the graph changes when intensity doubles but frequency remains same.
Answer:
Case Deconstruction

Saturation current occurs when all emitted electrons reach the anode. It depends on light intensity.

Theoretical Application

Doubling intensity doubles saturation current (Isat ∝ I). Stopping potential remains unchanged as it depends only on frequency.

Critical Evaluation
  • Confirms photon theory: more photons → more electrons.
  • Kmax remains constant as hν - φ unchanged.
Question 14:
A student performs an experiment to study the photoelectric effect using a sodium surface. When light of wavelength 400 nm is incident on the surface, electrons are emitted. However, no electrons are emitted when light of wavelength 600 nm is used. Explain this observation using Einstein's photoelectric equation and calculate the work function of sodium in eV. (Given: Planck's constant h = 6.63 × 10-34 Js, speed of light c = 3 × 108 m/s, 1 eV = 1.6 × 10-19 J)
Answer:

According to Einstein's photoelectric equation: Kmax = hν - φ, where Kmax is the maximum kinetic energy of emitted electrons, is the energy of incident photons, and φ is the work function of the metal.

For no emission at 600 nm, the photon energy is less than the work function (hν < φ). This wavelength is the threshold wavelength (λ0).


First, calculate the energy of 600 nm photons:
E = hc/λ
= (6.63 × 10-34 × 3 × 108)/(600 × 10-9)
= 3.315 × 10-19 J

Convert to eV:
φ = (3.315 × 10-19)/(1.6 × 10-19)
= 2.07 eV (work function of sodium)
Question 15:
In a Davisson-Germer experiment, electrons accelerated through 54 V are scattered from a nickel crystal. The first-order diffraction maximum is observed at an angle of 50°. Calculate the interatomic spacing of the nickel crystal and explain how this experiment confirms the wave nature of matter. (Given: Planck's constant h = 6.63 × 10-34 Js, electron mass me = 9.1 × 10-31 kg, electron charge e = 1.6 × 10-19 C)
Answer:

The Davisson-Germer experiment confirmed the wave nature of electrons by observing diffraction patterns similar to X-rays, supporting de Broglie's hypothesis.


Step 1: Calculate electron wavelength using de Broglie's formula:
λ = h/p
First find kinetic energy:
K = eV = 54 eV = 54 × 1.6 × 10-19 J

Step 2: Calculate momentum:
p = √(2meK)
= √(2 × 9.1 × 10-31 × 54 × 1.6 × 10-19)
= 3.96 × 10-24 kg m/s

Step 3: Calculate wavelength:
λ = (6.63 × 10-34)/(3.96 × 10-24)
= 1.67 × 10-10 m

Step 4: Use Bragg's law for interatomic spacing (d):
nλ = 2d sinθ (n=1 for first-order)
d = λ/(2 sin50°)
= (1.67 × 10-10)/(2 × 0.766)
= 1.09 × 10-10 m
Question 16:
A student performs an experiment to study the photoelectric effect using a sodium surface. When light of wavelength 400 nm is incident on the surface, electrons are emitted. However, no electrons are emitted when light of wavelength 600 nm is used. Explain this observation using the principles of the photoelectric effect and calculate the work function of sodium in eV. (Given: Planck's constant h = 6.63 × 10-34 Js, speed of light c = 3 × 108 m/s, and 1 eV = 1.6 × 10-19 J).
Answer:

The photoelectric effect occurs when light of sufficient energy (i.e., frequency above the threshold frequency) strikes a metal surface, ejecting electrons. The energy of a photon is given by E = hν, where ν is the frequency. For sodium, light of wavelength 400 nm has enough energy to eject electrons, but 600 nm does not, indicating the latter's energy is below the work function (Φ).


First, calculate the energy of the 400 nm light (which equals the work function since it is the threshold wavelength):
E = hc/λ
E = (6.63 × 10-34 × 3 × 108) / (400 × 10-9)
E = 4.9725 × 10-19 J
Convert this to eV:
Φ = 4.9725 × 10-19 / 1.6 × 10-19 ≈ 3.11 eV

Thus, the work function of sodium is 3.11 eV. Light of 600 nm has lower energy and cannot overcome this threshold, so no electrons are emitted.

Question 17:
In a Davisson-Germer experiment, electrons are accelerated through a potential difference of 54 V and directed at a nickel crystal. A sharp peak in the intensity of scattered electrons is observed at an angle of 50°. Using de Broglie's hypothesis, calculate the wavelength of the electrons and verify if it matches the interatomic spacing of nickel (0.215 nm). (Given: h = 6.63 × 10-34 Js, me = 9.11 × 10-31 kg, e = 1.6 × 10-19 C).
Answer:

According to de Broglie's hypothesis, the wavelength (λ) of an electron is given by λ = h/p, where p is the momentum. For an electron accelerated through a potential difference (V), its kinetic energy is K = eV, and momentum is p = √(2meK).


Calculate the de Broglie wavelength:
K = 1.6 × 10-19 × 54 = 8.64 × 10-18 J
p = √(2 × 9.11 × 10-31 × 8.64 × 10-18) ≈ 1.25 × 10-23 kg·m/s
λ = 6.63 × 10-34 / 1.25 × 10-23 ≈ 0.167 nm

For constructive interference in the Davisson-Germer experiment, the condition is nλ = 2d sinθ, where d is the interatomic spacing. For the first peak (n = 1):


0.167 nm = 2 × 0.215 nm × sin(50°)
0.167 nm ≈ 0.215 nm × 1.532 ≈ 0.167 nm

The calculated wavelength matches the experimental observation, confirming de Broglie's hypothesis and the wave nature of electrons.

Question 18:
A student performs an experiment to study the photoelectric effect using a sodium surface. When light of wavelength 400 nm is incident on the surface, electrons are emitted. However, no electrons are emitted when light of wavelength 600 nm is used. Explain this observation using Einstein's photoelectric equation and calculate the work function of sodium.
Answer:

According to Einstein's photoelectric equation:
E = hν = φ + K.E.max
where E is the energy of incident photon, is the photon energy, φ is the work function, and K.E.max is the maximum kinetic energy of emitted electrons.

For 400 nm light (which emits electrons):
Energy of photon E = hc/λ
Substituting values:
E = (6.63 × 10-34 × 3 × 108) / (400 × 10-9) = 4.97 × 10-19 J
Since electrons are emitted, E > φ.

For 600 nm light (no emission):
E = (6.63 × 10-34 × 3 × 108) / (600 × 10-9) = 3.31 × 10-19 J
Since no electrons are emitted, E < φ.

Thus, the work function φ of sodium must lie between these two values. The threshold wavelength (λ0) is just below 600 nm. Using λ0 = 600 nm for calculation:
φ = hc/λ0 = 3.31 × 10-19 J or 2.07 eV.

Question 19:
In a Davisson-Germer experiment, electrons accelerated through 54 V are scattered by a nickel crystal. A sharp peak in intensity is observed at an angle of 50° to the incident beam. Calculate the de Broglie wavelength of the electrons and show how this confirms the wave nature of matter.
Answer:

Step 1: Calculate de Broglie wavelength theoretically
Using λ = h/√(2meV)
where m = 9.1 × 10-31 kg, e = 1.6 × 10-19 C, V = 54 V
λ = (6.63 × 10-34)/√(2 × 9.1 × 10-31 × 1.6 × 10-19 × 54)
λ = 1.67 × 10-10 m or 1.67 Å

Step 2: Verify using Bragg's Law
For nickel crystal, interplanar spacing d = 0.91 Å (known value)
Using nλ = 2d sinθ (first order peak, n=1)
λ = 2 × 0.91 × sin(50°/2) = 1.65 Å

Conclusion:
The close match between theoretical (1.67 Å) and experimental (1.65 Å) values confirms that electrons exhibit wave-like behavior, validating de Broglie's hypothesis of wave-particle duality.

Question 20:
A student performs an experiment to study the photoelectric effect using a sodium surface. When light of wavelength 400 nm is incident on the surface, electrons are emitted. However, no electrons are emitted when light of wavelength 600 nm is used. Explain this observation using the concept of work function and threshold frequency. Calculate the work function of sodium in eV.
Answer:

The photoelectric effect occurs when light of sufficient energy (greater than the work function) ejects electrons from a metal surface. The threshold frequency (ν₀) is the minimum frequency required to eject electrons.


Given:
Wavelength (λ₁) = 400 nm (emits electrons)
Wavelength (λ₂) = 600 nm (no emission)


Step 1: Calculate energy of photons for λ₂ (600 nm), which does not eject electrons.
Energy (E) = hc/λ
E = (6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s) / (600 × 10⁻⁹ m) ≈ 3.31 × 10⁻¹⁹ J ≈ 2.07 eV


Since no emission occurs at 600 nm, the work function (Φ) of sodium must be greater than 2.07 eV.


Step 2: For λ₁ (400 nm), emission occurs, so energy > Φ.
E = hc/λ = (6.626 × 10⁻³⁴ × 3 × 10⁸) / (400 × 10⁻⁹) ≈ 4.97 × 10⁻¹⁹ J ≈ 3.11 eV


Thus, the work function lies between 2.07 eV and 3.11 eV. From standard data, the work function of sodium is 2.28 eV.


Key takeaway: The threshold wavelength (λ₀) is the maximum wavelength for photoelectric emission, calculated as λ₀ = hc/Φ.

Question 21:
In a Davisson-Germer experiment, electrons are accelerated through a potential difference of 54 V and produce a diffraction pattern. The first-order maximum is observed at an angle of 50°. Calculate the de Broglie wavelength of the electrons and the interatomic spacing of the crystal. Relate this to the wave-particle duality of matter.
Answer:

The Davisson-Germer experiment confirms the wave-particle duality of electrons by observing diffraction patterns, similar to X-rays.


Given:
Potential difference (V) = 54 V
First-order maximum angle (θ) = 50°


Step 1: Calculate de Broglie wavelength (λ) of electrons.
λ = h/√(2meV)
λ = (6.626 × 10⁻³⁴ Js) / √(2 × 9.1 × 10⁻³¹ kg × 1.6 × 10⁻¹⁹ C × 54 V)
λ ≈ 1.67 × 10⁻¹⁰ m ≈ 1.67 Å


Step 2: Use Bragg’s law for first-order diffraction (n = 1).
nλ = 2d sinθ
1 × 1.67 Å = 2 × d × sin(50°)
d = 1.67 Å / (2 × 0.766) ≈ 1.09 Å


The interatomic spacing (d) of the crystal is 1.09 Å.


Connection to duality: The diffraction pattern proves electrons exhibit wave-like behavior, while their particle nature is evident in individual collisions. This duality is fundamental to quantum mechanics.

Question 22:
In a photoelectric experiment, light of wavelength λ is incident on a metal surface. The stopping potential is found to be V0. If the wavelength of the incident light is reduced to λ/2, how will the stopping potential change? Justify your answer using Einstein's photoelectric equation.
Answer:

According to Einstein's photoelectric equation:
hν = φ + Kmax
where is the energy of the incident photon, φ is the work function of the metal, and Kmax is the maximum kinetic energy of the emitted electrons.
The stopping potential V0 is related to Kmax by:
Kmax = eV0
When the wavelength is reduced to λ/2, the frequency ν doubles (since ν = c/λ).
Thus, the new photon energy becomes 2hν.
Substituting into the photoelectric equation:
2hν = φ + eV0'
Comparing with the original equation, the new stopping potential V0' will be greater than V0 because the photon energy has increased.
Value-added point: The exact change depends on the work function, but the stopping potential will always increase when the wavelength decreases (or frequency increases).

Question 23:
A beam of electrons is accelerated through a potential difference of V volts. Calculate the de Broglie wavelength associated with these electrons. How will the wavelength change if the accelerating potential is doubled? Explain.
Answer:

The de Broglie wavelength λ for an electron is given by:
λ = h / p
where h is Planck's constant and p is the momentum of the electron.
For an electron accelerated through potential V, its kinetic energy is eV, and momentum is:
p = √(2meV)
where m is the mass of the electron and e is its charge.
Substituting, the wavelength becomes:
λ = h / √(2meV)
If the potential is doubled (V' = 2V), the new wavelength λ' is:
λ' = h / √(2me(2V)) = λ / √2
Thus, the wavelength decreases by a factor of √2 when the accelerating potential is doubled.
Application: This principle is used in electron microscopes, where higher voltages yield shorter wavelengths and better resolution.

Question 24:
A student performs an experiment to study the photoelectric effect using a metal surface. When light of wavelength λ = 400 nm is incident on the surface, electrons are emitted with a certain kinetic energy. However, when light of wavelength λ = 600 nm is used, no electrons are emitted. Explain this observation using Einstein's photoelectric equation and calculate the work function of the metal.
Answer:

According to Einstein's photoelectric equation, the energy of incident photons (E) is given by:
E = hν = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength.

For electrons to be emitted, the energy of the incident photon must be greater than or equal to the work function (Φ) of the metal. Mathematically,
E ≥ Φ or hc/λ ≥ Φ.

For λ = 400 nm (emission occurs):
E = (6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s) / (400 × 10⁻⁹ m) = 4.97 × 10⁻¹⁹ J.

For λ = 600 nm (no emission):
E = (6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s) / (600 × 10⁻⁹ m) = 3.31 × 10⁻¹⁹ J.

Since no emission occurs at 600 nm, the work function must be greater than 3.31 × 10⁻¹⁹ J but less than or equal to 4.97 × 10⁻¹⁹ J (as emission occurs at 400 nm). Therefore, the work function (Φ) of the metal lies in this range.
Calculation:
To find the exact work function, we use the threshold condition where E = Φ. The threshold wavelength (λ₀) is the maximum wavelength for which emission just occurs. Since 600 nm does not cause emission, λ₀ must be between 400 nm and 600 nm. Assuming the work function corresponds to the threshold wavelength, we can estimate it as the energy at 400 nm (since emission occurs here). Thus,
Φ ≈ 4.97 × 10⁻¹⁹ J (or ~3.10 eV).

Question 25:
In a Davisson-Germer experiment, electrons are accelerated through a potential difference of 54 V and are incident on a nickel crystal. The first-order diffraction maximum is observed at an angle of 50°. Calculate the interatomic spacing of the nickel crystal and explain the significance of this experiment in confirming the wave nature of matter.
Answer:

The Davisson-Germer experiment confirmed the wave nature of matter by demonstrating electron diffraction. The de Broglie wavelength (λ) of electrons accelerated through a potential difference (V) is given by:
λ = h / √(2meV), where h is Planck's constant, m is the electron mass, and e is the electron charge.

Step 1: Calculate the de Broglie wavelength
λ = (6.626 × 10⁻³⁴ Js) / √(2 × 9.11 × 10⁻³¹ kg × 1.6 × 10⁻¹⁹ C × 54 V)
λ ≈ 1.67 × 10⁻¹⁰ m (or 0.167 nm).

Step 2: Relate to diffraction
For first-order diffraction (n = 1), Bragg's law is:
2d sinθ = nλ, where d is the interatomic spacing and θ is the angle of diffraction.
Substituting θ = 50° and λ = 0.167 nm:
d = λ / (2 sinθ) = 0.167 nm / (2 × sin 50°)
d ≈ 0.109 nm.

Significance of the experiment:

  • The observation of electron diffraction confirmed that particles like electrons exhibit wave-particle duality, as proposed by de Broglie.
  • It provided experimental validation for the wave nature of matter, a cornerstone of quantum mechanics.
  • The calculated interatomic spacing matched known values for nickel crystals, reinforcing the accuracy of the theory.

Question 26:
In a Davisson-Germer experiment, electrons are accelerated through a potential difference of 54 V and are incident on a nickel crystal. The first-order diffraction maximum is observed at an angle of 50°. Calculate the interatomic spacing of the nickel crystal and explain how this experiment confirms the wave nature of matter.
Answer:

The Davisson-Germer experiment confirms the wave nature of matter by demonstrating electron diffraction. The de Broglie wavelength (λ) of electrons is given by:


λ = h/√(2meV), where V = 54 V.
Substitute h = 6.63 × 10⁻³⁴ Js, m = 9.11 × 10⁻³¹ kg, e = 1.6 × 10⁻¹⁹ C.
λ = (6.63 × 10⁻³⁴)/√(2 × 9.11 × 10⁻³¹ × 1.6 × 10⁻¹⁹ × 54) ≈ 1.67 × 10⁻¹⁰ m.

For the first-order maximum (n = 1), Bragg's law is: nλ = 2d sinθ.


Here, θ = 50°, so d = λ/(2 sinθ) = (1.67 × 10⁻¹⁰)/(2 × sin50°) ≈ 1.09 × 10⁻¹⁰ m.

The interatomic spacing (d) of the nickel crystal is approximately 1.09 Å.


This experiment confirms the wave-particle duality of electrons because the observed diffraction pattern matches the predictions of wave theory, supporting de Broglie's hypothesis that matter exhibits wave-like properties.

Question 27:
In a Davisson-Germer experiment, electrons are accelerated through a potential difference of 54 V and are incident on a nickel crystal. A sharp peak in the intensity of scattered electrons is observed at an angle of 50°. Explain how this observation supports the wave nature of electrons and calculate the interplanar spacing of the nickel crystal.
Answer:

The Davisson-Germer experiment provides evidence for the wave nature of electrons by demonstrating electron diffraction, a phenomenon characteristic of waves. When electrons are scattered by the nickel crystal, they behave like waves and interfere constructively at specific angles, producing intensity peaks.

Using the de Broglie wavelength formula for electrons accelerated through potential difference V:

λ = h/√(2meV)
where m is the electron mass (9.11 × 10-31 kg), e is the electron charge (1.6 × 10-19 C), and V = 54 V.

Substituting values:
λ = (6.626 × 10-34)/√(2 × 9.11 × 10-31 × 1.6 × 10-19 × 54)
λ ≈ 1.67 × 10-10 m (0.167 nm)

For constructive interference (Bragg's law):
nλ = 2d sinθ
where n = 1 (first-order peak), θ = 50°, and d is the interplanar spacing.

Rearranging:
d = λ/(2 sinθ) = (1.67 × 10-10)/(2 × sin 50°)
d ≈ 1.09 × 10-10 m (0.109 nm)

This matches the known lattice spacing of nickel crystals, confirming the wave-particle duality of electrons.

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