Moving Charges and Magnetism – CBSE NCERT Study Resources

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12th

12th - Physics

Moving Charges and Magnetism

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Overview of the Chapter: Moving Charges and Magnetism

This chapter explores the relationship between moving electric charges and magnetism. It covers fundamental concepts such as the magnetic force on a moving charge, the motion of charged particles in a magnetic field, and the Biot-Savart law. The chapter also discusses Ampere's circuital law and its applications, along with the concept of the solenoid and toroid.

Magnetic Force: The force experienced by a moving charge in a magnetic field, given by the Lorentz force equation: F = q(v × B), where q is the charge, v is the velocity, and B is the magnetic field.

Key Topics Covered

  • Magnetic Force and Motion of Charged Particles
  • Biot-Savart Law and its Applications
  • Ampere's Circuital Law and its Applications
  • Solenoid and Toroid
  • Force Between Two Parallel Current-Carrying Conductors
  • Torque on a Current Loop in a Magnetic Field

Detailed Explanation

Magnetic Force and Motion of Charged Particles

When a charged particle moves in a magnetic field, it experiences a force perpendicular to both its velocity and the magnetic field. This force causes the particle to move in a circular or helical path, depending on the angle between the velocity and the magnetic field.

Biot-Savart Law: This law describes the magnetic field generated by a steady current. The magnetic field dB at a point due to a current element Idl is given by dB = (μ₀/4π) (Idl × r)/r³, where μ₀ is the permeability of free space, and r is the distance from the current element to the point.

Ampere's Circuital Law

Ampere's circuital law relates the magnetic field around a closed loop to the electric current passing through the loop. It is given by ∮B·dl = μ₀I, where I is the total current enclosed by the loop.

Solenoid and Toroid

A solenoid is a coil of wire that produces a uniform magnetic field inside it when an electric current is passed through it. A toroid is a solenoid bent into a circular shape, and its magnetic field is confined entirely within the toroid.

Torque on a Current Loop: When a current-carrying loop is placed in a magnetic field, it experiences a torque given by τ = NIABsinθ, where N is the number of turns, I is the current, A is the area of the loop, B is the magnetic field, and θ is the angle between the normal to the loop and the magnetic field.

Applications

The concepts discussed in this chapter are applied in various devices such as electric motors, galvanometers, and cyclotrons. Understanding these principles is crucial for advancements in technology and engineering.

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define magnetic field.
Answer:
Definition: Region around a magnet where its influence is felt.
Question 2:
State the SI unit of magnetic flux.
Answer:

Weber (Wb).

Question 3:
What is the direction of force on a current-carrying conductor in a magnetic field?
Answer:

Perpendicular to both current and field (Fleming’s Left-Hand Rule).

Question 4:
Name the device converting electrical energy to mechanical energy using Lorentz force.
Answer:

Electric motor.

Question 5:
What happens to the force on a charged particle if its velocity doubles in a uniform magnetic field?
Answer:

Force doubles (F = qvB).

Question 6:
State the principle behind a cyclotron.
Answer:

Charged particles accelerate in spiral paths using oscillating electric fields.

Question 7:
Define Ampere’s circuital law.
Answer:
Definition: Line integral of B around a closed loop equals μ₀ times current enclosed.
Question 8:
What is the nature of force between two parallel wires carrying currents in the same direction?
Answer:

Attractive.

Question 9:
How does a solenoid behave when current passes through it?
Answer:

Acts like a bar magnet with N and S poles.

Question 10:
What is the Biot-Savart law used for?
Answer:

Calculating magnetic field due to a current-carrying element.

Question 11:
Why is the path of an electron in a uniform magnetic field circular?
Answer:

Force acts perpendicular to velocity, causing centripetal acceleration.

Question 12:
Name the material used for making permanent magnets.
Answer:

Alnico or ferromagnetic materials.

Question 13:
What is the effect of increasing current on the torque in a moving coil galvanometer?
Answer:

Torque increases proportionally (τ = nIAB).

Question 14:
State the condition for zero force on a charge moving in a magnetic field.
Answer:

Velocity is parallel or antiparallel to the field (θ = 0° or 180°).

Question 15:
Define magnetic field due to a current-carrying conductor.
Answer:

The magnetic field due to a current-carrying conductor is the region around the conductor where its magnetic influence can be detected. It is produced by moving charges and is represented by magnetic field lines.

Question 16:
State the right-hand thumb rule for the direction of the magnetic field around a straight conductor.
Answer:

The right-hand thumb rule states that if you grasp the conductor in your right hand with the thumb pointing in the direction of the current, the curled fingers indicate the direction of the magnetic field lines around the conductor.

Question 17:
What is the SI unit of magnetic field strength?
Answer:

The SI unit of magnetic field strength is Tesla (T). It measures the force experienced by a unit charge moving perpendicular to the field.

Question 18:
Explain the term cyclotron frequency.
Answer:

The cyclotron frequency is the frequency at which a charged particle moves in a circular path in a uniform magnetic field. It is given by f = qB / (2πm), where q is charge, B is magnetic field, and m is mass.

Question 19:
What is the force experienced by a current-carrying conductor placed in a magnetic field?
Answer:

The force experienced is given by F = I(L × B), where I is current, L is length of conductor, and B is magnetic field. The direction is given by Fleming's left-hand rule.

Question 20:
State the principle of a moving coil galvanometer.
Answer:

A moving coil galvanometer works on the principle that a current-carrying coil placed in a magnetic field experiences a torque, causing it to deflect. The deflection is proportional to the current.

Question 21:
What is the significance of Lorentz force?
Answer:

The Lorentz force describes the combined effect of electric and magnetic fields on a charged particle. It is given by F = q(E + v × B), where q is charge, E is electric field, and v is velocity.

Question 22:
Define magnetic dipole moment of a current loop.
Answer:

The magnetic dipole moment of a current loop is a vector quantity given by m = IA, where I is current and A is area vector of the loop. Its direction is perpendicular to the plane of the loop.

Question 23:
What is the condition for a charged particle to move undeviated in crossed electric and magnetic fields?
Answer:

The particle moves undeviated when the electric force qE balances the magnetic force qvB. Thus, v = E/B, where v is velocity, E is electric field, and B is magnetic field.

Question 24:
Explain the working of a solenoid.
Answer:

A solenoid is a coil of wire that produces a strong magnetic field when current passes through it. The field inside is uniform and parallel to the axis, given by B = μ₀nI, where n is turns per unit length.

Question 25:
What is the role of soft iron core in a moving coil galvanometer?
Answer:

The soft iron core increases the magnetic field strength and ensures radial magnetic field, making the deflection proportional to the current for accurate measurements.

Question 26:
State Ampere's circuital law in magnetism.
Answer:

Ampere's circuital law states that the line integral of the magnetic field around a closed loop is equal to μ₀ times the total current passing through the loop: ∮B·dl = μ₀I.

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
State the Biot-Savart law in vector form.
Answer:

The Biot-Savart law in vector form is given by:
dB = (μ₀/4π) (I dl × r̂)/r²
where:
dB is the magnetic field due to a small current element I dl,
is the unit vector from the current element to the point,
r is the distance, and
μ₀ is the permeability of free space.

Question 2:
What is the direction of the force experienced by a charged particle moving in a magnetic field?
Answer:

The direction of the force on a charged particle moving in a magnetic field is given by the Fleming's left-hand rule (for positive charge). It is perpendicular to both the velocity (v) of the particle and the magnetic field (B).

Question 3:
Explain why two parallel current-carrying conductors attract each other when currents are in the same direction.
Answer:

Two parallel current-carrying conductors attract each other when currents are in the same direction because:
1. Each conductor produces a magnetic field around it.
2. The magnetic field due to one conductor exerts a force on the other conductor.
3. By Fleming's left-hand rule, the forces are attractive when currents are parallel.

Question 4:
What is the cyclotron frequency of a charged particle in a magnetic field?
Answer:

The cyclotron frequency (f) is the frequency at which a charged particle revolves in a circular path in a uniform magnetic field. It is given by:
f = (qB)/(2πm)
where:
q = charge of the particle,
B = magnetic field strength,
m = mass of the particle.

Question 5:
How does the radius of the circular path of a charged particle in a magnetic field depend on its momentum?
Answer:

The radius (r) of the circular path of a charged particle in a magnetic field is directly proportional to its momentum (p):
r = p/(qB)
where:
q = charge of the particle,
B = magnetic field strength.
Higher momentum means a larger radius.

Question 6:
What is the principle behind the working of a moving coil galvanometer?
Answer:

The moving coil galvanometer works on the principle that a current-carrying coil placed in a magnetic field experiences a torque, causing it to deflect. The deflection is proportional to the current passing through the coil.

Question 7:
Define Ampere's circuital law and state its mathematical form.
Answer:

Ampere's circuital law states that the line integral of the magnetic field (B) around a closed loop is equal to μ₀ times the total current (I) passing through the loop:
∮ B · dl = μ₀I
where μ₀ is the permeability of free space.

Question 8:
Why is the magnetic field inside a solenoid uniform?
Answer:

The magnetic field inside a solenoid is uniform because:
1. The field lines are parallel and closely spaced.
2. The contributions from each turn of the solenoid add up constructively.
3. The end effects are negligible for a long solenoid.

Question 9:
What is the Lorentz force? Write its expression.
Answer:

The Lorentz force is the combined force experienced by a charged particle due to electric and magnetic fields. Its expression is:
F = q(E + v × B)
where:
q = charge,
E = electric field,
v = velocity,
B = magnetic field.

Question 10:
Explain the significance of the right-hand thumb rule for a straight current-carrying conductor.
Answer:

The right-hand thumb rule helps determine the direction of the magnetic field around a straight current-carrying conductor:
1. Point the thumb in the direction of the current.
2. The curled fingers show the direction of the magnetic field lines.
This rule is crucial for visualizing field patterns in electromagnetism.

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
State the Biot-Savart law and express it mathematically. Explain the significance of each term in the equation.
Answer:

The Biot-Savart law gives the magnetic field dB produced by a current-carrying element Idl at a point. Mathematically, it is expressed as:

dB = (μ0/4π) * (Idl × r̂)/r2

  • μ0: Permeability of free space (4π × 10-7 Tm/A)
  • Idl: Current element (magnitude and direction)
  • : Unit vector from the current element to the point
  • r: Distance between the current element and the point

The law helps calculate the magnetic field due to any current distribution by integrating over the entire conductor.

Question 2:
Derive the expression for the magnetic field at the center of a circular loop carrying current I with radius R.
Answer:

Using the Biot-Savart law, the magnetic field at the center of a circular loop is derived as follows:

dB = (μ0/4π) * (Idl sinθ)/r2
For a circular loop, θ = 90° (sinθ = 1) and r = R (radius).

Integrating over the entire loop (circumference = 2πR):
B = ∫dB = (μ0I/4πR2) * ∫dl
B = (μ0I/4πR2) * 2πR
B = μ0I/2R

The direction is perpendicular to the plane of the loop, given by the right-hand thumb rule.

Question 3:
Explain how a cyclotron works to accelerate charged particles. Mention its limitations.
Answer:

A cyclotron accelerates charged particles using a combination of electric and magnetic fields:

  • Magnetic Field: Particles move in circular paths due to the perpendicular B field.
  • Electric Field: An alternating voltage across dees accelerates particles each half-cycle.

Limitations:

  • Particles gain relativistic mass at high speeds, disrupting resonance.
  • Not suitable for accelerating neutral particles or electrons (significant energy loss via radiation).
  • Requires large magnets for high-energy applications.
Question 4:
Define Ampere's circuital law and state its mathematical form. Under what conditions is it valid?
Answer:

Ampere's circuital law states that the line integral of the magnetic field B around a closed loop is equal to μ0 times the current enclosed by the loop:

∮B·dl = μ0Ienc

Conditions for validity:

  • Steady current (time-independent).
  • Closed loop with high symmetry (e.g., infinite straight wire, solenoid).
  • Current distribution must be continuous and enclosed by the loop.
Question 5:
Describe the principle and working of a moving coil galvanometer. What factors affect its sensitivity?
Answer:

A moving coil galvanometer measures small currents using the torque on a current-carrying coil in a magnetic field:

  • Principle: A coil in a radial magnetic field experiences torque τ = NIAB, causing deflection proportional to current.
  • Working: Current passes through the coil, creating torque balanced by a spring's restoring torque (θ ∝ I).

Sensitivity factors:

  • Number of turns N in the coil.
  • Strength of the magnetic field B.
  • Area A of the coil.
  • Torsional constant of the spring.
Question 6:
Compare the magnetic fields produced by a solenoid and a bar magnet. How can a solenoid be used to create a bar magnet?
Answer:

Comparison:

  • Solenoid: Field is uniform inside (B = μ0nI) and resembles a bar magnet externally.
  • Bar Magnet: Permanent field with fixed poles; internal structure aligns domains.

Creating a Bar Magnet:
Pass a steady current through a solenoid with a soft iron core. The core gets magnetized, retaining some magnetism (temporary bar magnet) after current is switched off. For a permanent magnet, use materials like steel with high retentivity.

Question 7:
Define the term magnetic dipole moment of a current loop. Write its SI unit and expression.
Answer:

The magnetic dipole moment (m) of a current loop is a vector quantity that represents the strength and orientation of the loop's magnetic field. It is defined as the product of the current (I) flowing through the loop and the area vector (A) of the loop.

Its SI unit is ampere-meter² (A·m²).

The expression for magnetic dipole moment is: m = I × A, where the direction of A is given by the right-hand thumb rule.

Question 8:
Explain how a cyclotron works to accelerate charged particles. Mention one limitation of a cyclotron.
Answer:

A cyclotron accelerates charged particles (like protons) using a combination of electric and magnetic fields.

  • Particles move in a spiral path inside two hollow dees placed in a magnetic field.
  • An alternating electric field between the dees provides acceleration at each gap crossing.
  • The magnetic field keeps the particles in a circular path due to the Lorentz force.

One limitation is that cyclotrons cannot accelerate electrons effectively because their high speed leads to relativistic effects, causing a loss of synchronization with the electric field.

Question 9:
State Biot-Savart law and express it mathematically. What does the law help us determine?
Answer:

The Biot-Savart law gives the magnetic field (dB) produced by a small current-carrying element (Idl) at a point.

Mathematically: dB = (μ₀/4π) × (Idl × r̂)/r², where:

  • μ₀ = permeability of free space
  • = unit vector from current element to the point
  • r = distance between them

The law helps determine the magnetic field due to any current-carrying conductor by integrating contributions from all small elements.

Question 10:
Derive the expression for the force per unit length between two parallel current-carrying conductors. What does this force indicate about the currents?
Answer:

Consider two parallel conductors separated by distance d, carrying currents I₁ and I₂.

The magnetic field due to first conductor at the second: B₁ = (μ₀I₁)/(2πd).

Force on the second conductor: F₂ = I₂L × B₁ (where L is length).

Force per unit length: F/L = (μ₀I₁I₂)/(2πd).

If currents are in the same direction, the force is attractive; if opposite, it is repulsive.

Question 11:
What is an Amperian loop? State Ampère’s circuital law and mention its significance.
Answer:

An Amperian loop is an imaginary closed path around a current-carrying conductor used to apply Ampère’s circuital law.

The law states: ∮B·dl = μ₀Ienc, where:

  • B = magnetic field
  • dl = infinitesimal loop element
  • Ienc = total current enclosed by the loop

Significance: It simplifies calculating magnetic fields for highly symmetric current distributions (e.g., infinite wire, solenoid).

Question 12:
Describe the working principle of a moving coil galvanometer. What is the function of a radial magnetic field in it?
Answer:

A moving coil galvanometer measures small currents based on the torque experienced by a current-carrying coil in a magnetic field.

  • When current flows, the coil experiences a torque: τ = NIAB (N = turns, A = area).
  • The coil deflects, twisting a spring that provides restoring torque.
  • At equilibrium, deflection θ ∝ current.

The radial magnetic field ensures the plane of the coil is always parallel to the field, making torque independent of θ and giving a linear scale.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Explain the Biot-Savart Law and derive the expression for the magnetic field due to a current-carrying straight conductor. How does it differ from Ampere’s Circuital Law?
Answer:
Theoretical Framework

The Biot-Savart Law describes the magnetic field generated by a steady current. It states that the magnetic field dB due to a current element Idl is directly proportional to the current and inversely proportional to the square of the distance.

Evidence Analysis
  • For a straight conductor, integrating the law gives B = (μ₀I)/(4πa) (sinθ₁ + sinθ₂), where a is the perpendicular distance.
  • Ampere’s Law simplifies calculations for symmetric systems like solenoids but lacks precision for arbitrary shapes.
Critical Evaluation

While Biot-Savart is versatile, Ampere’s Law is computationally efficient for symmetrical cases. Both are experimentally validated.

Question 2:
Describe the working principle of a cyclotron with a labeled diagram. Why can’t it accelerate electrons effectively?
Answer:
Theoretical Framework

A cyclotron uses a magnetic field to bend charged particles into circular paths and an electric field to accelerate them. The frequency remains constant due to the non-relativistic assumption.

Evidence Analysis
  • [Diagram: Two D-shaped dees with alternating voltage and perpendicular magnetic field]
  • Electrons gain relativistic mass, causing desynchronization with the electric field.
Critical Evaluation

Cyclotrons are ideal for protons/heavy ions but fail for electrons, which require synchrotrons. Our textbook shows its medical use in radiotherapy.

Question 3:
Derive the expression for the force between two parallel current-carrying conductors. How does this define the ampere?
Answer:
Theoretical Framework

The force per unit length between parallel conductors is F/L = (μ₀I₁I₂)/(2πd), where d is separation. Attraction/repulsion depends on current direction.

Evidence Analysis
  • When I₁ = I₂ = 1A and d = 1m, F/L = 2×10⁻⁷ N/m, defining the ampere.
  • Example: Currents in power lines exhibit this force.
Critical Evaluation

This principle underpins the SI definition of current. It’s experimentally verified using current balances.

Question 4:
Analyze the motion of a charged particle in a uniform magnetic field. What happens if an electric field is superimposed?
Answer:
Theoretical Framework

A charged particle in a magnetic field follows a circular path (F = qvB). With an electric field, the trajectory becomes helical or linear, depending on alignment.

Evidence Analysis
  • In a pure B-field, radius r = mv/qB.
  • Crossed fields (E⊥B) create a straight path when v = E/B (Hall effect).
Critical Evaluation

This explains devices like mass spectrometers. Our textbook shows applications in CRT displays.

Question 5:
Discuss the torque experienced by a current loop in a magnetic field. How is this principle used in galvanometers?
Answer:
Theoretical Framework

Torque (τ = NIABsinθ) acts on a current loop in a B-field, where N is turns, A is area, and θ is the angle between normal and field.

Evidence Analysis
  • In galvanometers, a spring counterbalances torque, giving θ ∝ I.
  • Example: Moving coil meters use this for current measurement.
Critical Evaluation

This principle enables sensitive current detection. Modern digital meters still rely on its foundational physics.

Question 6:
Explain the Biot-Savart Law and derive the expression for the magnetic field due to a current-carrying circular loop at its center.
Answer:
Theoretical Framework

The Biot-Savart Law states that the magnetic field dB due to a current element Idl is directly proportional to the current and the sine of the angle between dl and the position vector r. We studied its mathematical form: dB = (μ₀/4π) (Idl × r̂)/r².

Evidence Analysis

For a circular loop of radius R, integrating the Biot-Savart Law gives the field at the center as B = (μ₀I)/2R. Our textbook shows this by considering symmetry, where all dB components add up along the axis.

Critical Evaluation

This derivation assumes a thin wire and steady current. Real-world deviations occur if the loop isn't perfectly circular or if the current varies.

Question 7:
Describe the working principle of a cyclotron with a labeled diagram. How does it overcome the relativistic limit?
Answer:
Theoretical Framework

A cyclotron accelerates charged particles using a high-frequency alternating electric field and a perpendicular magnetic field. We studied that particles spiral outward due to the Lorentz force, gaining energy with each half-cycle.

[Diagram: Cross-section showing Dees, magnetic field lines, and particle path]Evidence Analysis

The relativistic limit arises when particle mass increases with velocity, desynchronizing the electric field. Modern cyclotrons use variable frequency (synchrocyclotrons) or adjust the magnetic field (isochronous cyclotrons) to compensate.

Critical Evaluation

While effective for protons, cyclotrons become impractical for electrons due to rapid relativistic effects, leading to the development of linear accelerators.

Question 8:
Compare the torque experienced by a current loop in uniform magnetic fields when its plane is: (a) Parallel (b) Perpendicular to the field.
Answer:
Theoretical Framework

Torque (τ) on a current loop is given by τ = NIABsinθ, where θ is the angle between the magnetic moment (μ) and field B.

Evidence Analysis
  • (a) Parallel: θ = 90°, so τ = NIAB (maximum torque)
  • (b) Perpendicular: θ = 0°, so τ = 0 (stable equilibrium)
Critical Evaluation

This explains why galvanometer coils rotate to align with the field. Our textbook shows practical applications in electric motors where commutators maintain θ ≈ 90° for continuous rotation.

Question 9:
Analyze how Ampere's Circuital Law simplifies calculating magnetic fields for symmetric current distributions, with two examples.
Answer:
Theoretical Framework

Ampere's Law states that the line integral of B around a closed loop equals μ₀Ienc. We studied its use for highly symmetric systems where B is constant along the path.

Evidence Analysis
  • Infinite straight wire: Choosing a circular Amperian loop gives B = (μ₀I)/2πr
  • Solenoid: Applying the law to a rectangular loop yields B = μ₀nI inside
Critical Evaluation

While powerful, the law fails for asymmetric distributions like a finite wire segment, requiring Biot-Savart calculations instead.

Question 10:
Derive the expression for the force per unit length between two parallel current-carrying conductors. What does this imply about current definitions?
Answer:
Theoretical Framework

The force arises due to the interaction between the magnetic field (B₁ = μ₀I₁/2πd) of conductor 1 and current I₂ in conductor 2.

Evidence Analysis

Using F = I₂lB₁, we get force per unit length as F/l = (μ₀I₁I₂)/2πd. Our textbook shows this leads to attraction for parallel currents and repulsion for antiparallel currents.

Critical Evaluation

This principle defines the ampere in SI units: 1A is the current producing 2×10-7 N/m force at 1m separation. This bridges electromagnetism and mechanical measurements.

Question 11:
Explain the working principle of a cyclotron with a neat labeled diagram. Derive the expression for the cyclotron frequency and discuss its limitations.
Answer:

A cyclotron is a device used to accelerate charged particles, such as protons or electrons, to high energies using a combination of electric and magnetic fields. It consists of two hollow semicircular electrodes called dees placed in a uniform magnetic field perpendicular to their plane. The charged particles are injected near the center and accelerated by an alternating electric field between the dees.

Working Principle:
1. A charged particle is released at the center of the dees.
2. A magnetic field causes the particle to move in a circular path.
3. An alternating electric field accelerates the particle each time it crosses the gap between the dees.
4. The radius of the path increases as the particle gains energy, leading to a spiral trajectory.

Derivation of Cyclotron Frequency:
The centripetal force is provided by the magnetic force:
$$ qvB = \frac{mv^2}{r} $$
Rearranging gives the angular frequency (ω):
$$ ω = \frac{v}{r} = \frac{qB}{m} $$
The cyclotron frequency (f) is:
$$ f = \frac{ω}{2π} = \frac{qB}{2πm} $$

Limitations:

  • Relativistic effects: As particles approach the speed of light, their mass increases, causing a mismatch with the alternating field frequency.
  • Size and cost: High-energy cyclotrons require large magnets and are expensive to build.
  • Limited to charged particles: Neutral particles cannot be accelerated.

Question 12:
State Biot-Savart law and derive the expression for magnetic field due to a current-carrying circular loop at its center. How does the field vary along the axis of the loop?
Answer:

The Biot-Savart law states that the magnetic field dB due to a current element Idl at a point is:
dB = (μ₀/4π) (Idl × r)/r³
where μ₀ is permeability of free space, r is the position vector from the element to the point, and × denotes the cross product.

Derivation for Circular Loop:
1. Consider a circular loop of radius R carrying current I.
2. The magnetic field at the center is the sum of contributions from all dl elements.
3. For each element, dl and r are perpendicular, so |dl × r| = dl·R.
4. Integrating over the loop:
B = (μ₀I/4πR²) ∮dl = (μ₀I/4πR²) (2πR)
Thus, B = μ₀I/2R at the center.

Variation Along Axis:
The field at a distance x from the center along the axis is:
Bₓ = μ₀IR²/2(R² + x²)^(3/2)
This shows:
1. The field is maximum at the center (x = 0).
2. It decreases as we move away from the center along the axis.
3. At large distances (x >> R), Bₓ ≈ μ₀IR²/2x³ (dipole-like behavior).

Question 13:
Describe the construction and working of a moving coil galvanometer. Derive the expression for the current sensitivity and suggest two methods to increase it.
Answer:

A moving coil galvanometer is a device used to detect and measure small electric currents based on the principle that a current-carrying coil placed in a magnetic field experiences a torque.

Construction:
1. It consists of a rectangular coil suspended between the poles of a permanent magnet with a cylindrical soft iron core.
2. The coil is wound on a lightweight aluminum frame and attached to a phosphor-bronze strip.
3. A mirror is fixed to the suspension to measure deflection using a lamp and scale arrangement.

Working:
When current I flows through the coil, it experiences a torque τ = NIAB (N=number of turns, A=area, B=magnetic field). This torque is balanced by the restoring torque (k=restoring couple per unit twist, θ=deflection angle). At equilibrium:
NIAB = kθ
Thus, θ = (NAB/k)I, showing deflection is proportional to current.

Current Sensitivity (Sᵢ):
Defined as θ/I = NAB/k
To increase Sᵢ:
1. Increase N, A, or B: More turns, larger coil area, or stronger magnet.
2. Decrease k: Use a weaker suspension fiber (reduces restoring torque).
However, increasing sensitivity may reduce the instrument's durability and speed of response.

Question 14:
State Biot-Savart Law and use it to derive the expression for the magnetic field due to a current-carrying circular loop at its center. Discuss how this principle is applied in devices like helmholtz coils.
Answer:

The Biot-Savart Law states that the magnetic field (dB) due to a small current element (Idl) at a point is:
$$ dB = \frac{μ₀}{4π} \frac{Idl sinθ}{r^2} $$
where μ₀ is permeability of free space, θ is the angle between Idl and the position vector r.

Derivation for Circular Loop:
1. Consider a circular loop of radius R carrying current I.
2. For each element Idl, the angle θ is 90°, so sinθ = 1.
3. The magnetic field at the center due to one element is:
$$ dB = \frac{μ₀}{4π} \frac{Idl}{R^2} $$
4. Integrating over the entire loop:
$$ B = \frac{μ₀}{4π} \frac{I}{R^2} ∫dl = \frac{μ₀}{4π} \frac{I}{R^2} (2πR) $$
5. Simplifying gives:
$$ B = \frac{μ₀I}{2R} $$

Application in Helmholtz Coils:
Helmholtz coils consist of two identical circular coils placed coaxially at a distance equal to their radius. They produce a nearly uniform magnetic field in the central region, which is useful in experiments like electron deflection and magnetic field calibration. The combined field is:
$$ B_{total} = \frac{8μ₀NI}{5^{3/2}R} $$
where N is the number of turns in each coil.

Question 15:
Explain the principle, construction, and working of a cyclotron with a neat labeled diagram. Discuss its limitations and applications.
Answer:

A cyclotron is a device used to accelerate charged particles, such as protons or deuterons, to high energies using a combination of electric and magnetic fields. It operates on the principle that a charged particle moving perpendicular to a uniform magnetic field experiences a Lorentz force, causing it to move in a circular path. The particle gains energy each time it passes through an alternating electric field between two hollow dees (semi-circular electrodes).

Construction: A cyclotron consists of:

  • Two dees (D1 and D2) placed in a vacuum chamber.
  • A strong electromagnet to provide a uniform magnetic field perpendicular to the plane of the dees.
  • A high-frequency alternating voltage source connected across the dees.
  • An ion source at the center to inject charged particles.

Working:

  • The charged particle is released at the center and accelerated by the electric field between the dees.
  • The magnetic field forces the particle into a circular path.
  • Each time the particle crosses the gap between the dees, the polarity of the voltage reverses, providing acceleration.
  • The radius of the path increases as the particle gains energy, forming a spiral.

Limitations: Cyclotrons cannot accelerate electrons (due to relativistic mass increase) or neutral particles. They are also limited by the size of the magnet and frequency constraints.

Applications: Cyclotrons are used in nuclear physics research, medical isotope production (e.g., for PET scans), and cancer treatment (proton therapy).

Question 16:
Derive the expression for the force per unit length between two infinitely long parallel current-carrying conductors. State how this principle is used to define the SI unit of current, the ampere.
Answer:

The force per unit length between two parallel current-carrying conductors can be derived using Ampère's law and the concept of magnetic fields due to currents.

Derivation:


1. Consider two infinitely long parallel conductors separated by distance d, carrying currents I1 and I2.
2. The magnetic field (B1) due to I1 at the location of the second conductor is given by:
B1 = (μ0I1)/(2πd)
3. The force (F2) experienced by the second conductor (length L) due to B1 is:
F2 = I2LB1sinθ (θ = 90° for parallel conductors)
4. Substituting B1:
F2 = (μ0I1I2L)/(2πd)
5. Force per unit length (F/L):
F/L = (μ0I1I2)/(2πd)

Definition of Ampere: The ampere is defined as the constant current which, if maintained in two straight parallel conductors of infinite length and negligible cross-section, placed 1 meter apart in a vacuum, would produce a force of 2 × 10−7 newtons per meter of length. This directly follows from the derived expression.

Question 17:
Explain the principle, construction, and working of a cyclotron with a neat labeled diagram. Derive the expression for the cyclotron frequency and discuss its limitations.
Answer:

A cyclotron is a device used to accelerate charged particles (like protons, deuterons) to high energies using a combination of electric and magnetic fields. It operates on the principle that a charged particle moving perpendicular to a uniform magnetic field follows a circular path, and an alternating electric field can accelerate it repeatedly.

Construction:
1. Two hollow semicircular metal chambers called dees (D1 and D2) are placed in a vacuum chamber.
2. The dees are connected to a high-frequency alternating voltage source.
3. A strong uniform magnetic field is applied perpendicular to the plane of the dees using electromagnets.
4. A source of charged particles (e.g., protons) is placed at the center.

Working:
1. The charged particle is injected at the center and accelerated by the electric field between the dees.
2. Inside the dees, the magnetic field causes the particle to move in a semicircular path.
3. The alternating voltage is synchronized such that the particle is accelerated each time it crosses the gap.
4. The radius of the path increases with energy, and the particle spirals outward until it exits.

Cyclotron Frequency:
The time taken for a half-circle is t = πr/v, where r = mv/qB (from centripetal force balance).
Thus, the frequency f = 1/T = qB/2πm, which is independent of velocity and radius.

Limitations:
1. Relativistic effects: At high speeds, mass increases, disrupting synchronization.
2. Electron acceleration is impractical due to their small mass and high energy loss.
3. Requires a uniform magnetic field, which is challenging for large sizes.

Question 18:
Explain the principle and working of a cyclotron with a neat labeled diagram. Derive the expression for the cyclotron frequency and discuss its limitations.
Answer:

A cyclotron is a device used to accelerate charged particles, such as protons or deuterons, to high energies using a combination of electric and magnetic fields. It operates on the principle that a charged particle moving perpendicular to a uniform magnetic field follows a circular path, and an alternating electric field is used to accelerate the particle in steps.

Working Principle:

  • The cyclotron consists of two hollow semicircular electrodes called dees (D1 and D2), placed in a vacuum chamber.
  • A strong uniform magnetic field acts perpendicular to the plane of the dees.
  • An alternating high-frequency electric field is applied between the dees.
  • The charged particle is injected near the center and accelerated each time it crosses the gap between the dees.
  • The magnetic field keeps the particle in a spiral path of increasing radius.

Derivation of Cyclotron Frequency:
The centripetal force required for circular motion is provided by the magnetic force:
qvB = mv²/r
Simplifying, the angular velocity (ω) is:
ω = v/r = qB/m
The cyclotron frequency (f) is:
f = ω/2π = qB/2πm

Limitations:

  • At high velocities, relativistic effects increase the mass of the particle, causing a mismatch with the alternating electric field frequency.
  • Maintaining a uniform magnetic field over a large area is challenging.
  • It cannot accelerate neutral particles or electrons efficiently due to energy loss via radiation.

Diagram: (A labeled diagram of a cyclotron showing the dees, magnetic field direction, particle path, and alternating voltage source should be included.)

Question 19:
State Biot-Savart's law and derive the expression for the magnetic field due to a current-carrying circular loop at its center. How does the direction of the magnetic field relate to the current direction?
Answer:

Biot-Savart's law gives the magnetic field (dB) produced by a small current element (Idl) at a point. Mathematically:
dB = (μ₀/4π) (Idl × r̂)/r²
where μ₀ is permeability of free space, is the unit vector from the current element to the point, and r is the distance.

Derivation for a Circular Loop:
Consider a circular loop of radius R carrying current I. For a small element dl, the magnetic field at the center is:
dB = (μ₀/4π) (Idl sinθ)/R²
Since θ = 90° (angle between dl and ), sinθ = 1.
Integrating over the entire loop:
B = ∫dB = (μ₀I/4πR²) ∫dl
The total length of the loop is 2πR, so:
B = (μ₀I/4πR²) × 2πR = μ₀I/2R

Direction of Magnetic Field:
The direction is given by the right-hand thumb rule. If the fingers curl in the direction of current, the thumb points in the direction of the magnetic field at the center. For a circular loop, the field is perpendicular to the plane of the loop.

Additional Insight:
The field at the center of a circular loop is stronger than that of a straight wire because the circular geometry concentrates the field lines at the center.

Question 20:
Explain the principle, construction, and working of a cyclotron with a neat labeled diagram. Discuss its limitations and applications in modern physics.
Answer:

A cyclotron is a device used to accelerate charged particles to high energies using a combination of electric and magnetic fields. It operates on the principle that a charged particle moving perpendicular to a magnetic field experiences a Lorentz force, causing it to move in a circular path. The electric field is used to increase the particle's energy in steps.

Construction: A cyclotron consists of two hollow semicircular metal chambers called dees (D1 and D2) placed in a strong uniform magnetic field perpendicular to their plane. The dees are connected to a high-frequency alternating voltage source. The entire setup is enclosed in a vacuum chamber to prevent collisions with air molecules.

Working:
1. A charged particle (e.g., proton) is injected near the center of the dees.
2. The magnetic field causes the particle to move in a circular path.
3. Each time the particle crosses the gap between the dees, the alternating electric field accelerates it.
4. The radius of the path increases as the particle gains energy, forming a spiral trajectory.
5. The particle is ejected when it reaches the outer edge with high kinetic energy.

Limitations:
- Cannot accelerate electrons (due to relativistic mass increase).
- Requires very high magnetic fields for heavy particles.
- Energy is limited by the size of the dees and magnetic field strength.

Applications:
- Used in nuclear physics experiments.
- Production of radioisotopes for medical imaging (e.g., PET scans).
- Cancer treatment through particle therapy.

Question 21:
Derive the expression for the force per unit length between two infinitely long parallel current-carrying conductors. Explain how this principle is used to define the SI unit of current, the ampere.
Answer:

The force between two parallel current-carrying conductors can be derived using Ampère's force law and the concept of magnetic fields due to currents.

Derivation:
1. Consider two infinitely long parallel conductors separated by distance d, carrying currents I1 and I2.
2. The magnetic field (B1) due to I1 at the location of the second conductor is given by: B1 = (μ0I1)/(2πd).
3. The force experienced by the second conductor (F2) is: F2 = I2L × B1 (where L is length).
4. Since the field and current are perpendicular, the magnitude is: F2 = I2LB1sin90° = I2L(μ0I1)/(2πd).
5. Thus, force per unit length: F/L = (μ0I1I2)/(2πd).

Definition of Ampere:
The ampere is defined based on this expression. When I1 = I2 = 1A and d = 1m, the force per unit length is exactly 2 × 10-7 N/m. This precise measurement forms the basis for the SI definition of the ampere.

Significance:
- Shows that currents in the same direction attract, while opposite currents repel.
- Fundamental for understanding electromagnetic interactions in devices like motors and transformers.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
A solenoid of length 0.5 m has 500 turns and carries a current of 5 A. Magnetic field at its center is measured. (i) Derive the formula used. (ii) Calculate the field strength.
Answer:
Case Deconstruction

We studied that the magnetic field inside a solenoid is uniform and given by B = μ₀nI, where n is turns per unit length.


Theoretical Application
  • Given: N = 500, L = 0.5 m, I = 5 A
  • n = N/L = 1000 turns/m
  • B = (4π × 10⁻⁷)(1000)(5) = 6.28 × 10⁻³ T

Critical Evaluation

Our textbook shows this formula assumes ideal solenoid (infinite length). Practical solenoids show edge effects, but center field matches closely.

Question 2:
An electron moves at 10⁶ m/s perpendicular to a magnetic field of 0.1 T. (i) Explain why path is circular. (ii) Find radius (r).
Answer:
Case Deconstruction

We know F = qvB acts as centripetal force, causing circular motion.


Theoretical Application
  • F = mv²/r = qvB
  • r = mv/qB
  • Substituting values: r = (9.1×10⁻³¹)(10⁶)/(1.6×10⁻¹⁹)(0.1) = 5.69 × 10⁻⁵ m

Critical Evaluation

Our textbook shows this matches cyclotron motion principles. Real-world applications include mass spectrometers where r determines particle mass.

Question 3:
Two parallel wires 10 cm apart carry 2 A and 5 A in same direction. (i) Identify force type. (ii) Calculate force per unit length.
Answer:
Case Deconstruction

We studied that parallel currents attract via magnetic interaction (F = μ₀I₁I₂/2πd).


Theoretical Application
  • Given: I₁ = 2 A, I₂ = 5 A, d = 0.1 m
  • F/L = (4π×10⁻⁷×2×5)/(2π×0.1) = 2 × 10⁻⁵ N/m

Critical Evaluation

This matches Ampere's force law. Practical examples include overhead power lines where spacing prevents excessive attraction.

Question 4:
A cyclotron accelerates protons to 10 MeV. (i) Explain frequency condition. (ii) If B = 1.5 T, find oscillator frequency.
Answer:
Case Deconstruction

Cyclotron resonance requires f = qB/2πm for sustained acceleration.


Theoretical Application
  • Proton mass m = 1.67×10⁻²⁷ kg
  • f = (1.6×10⁻¹⁹×1.5)/(2π×1.67×10⁻²⁷) = 22.9 MHz

Critical Evaluation

Our textbook shows relativistic effects limit practical cyclotrons to ~20 MeV for protons. Medical cyclotrons use this principle for isotope production.

Question 5:
A moving coil galvanometer has N = 50 turns, A = 2×10⁻⁴ m², B = 0.2 T, and spring constant k = 10⁻⁶ Nm/rad. (i) Derive current sensitivity expression. (ii) Calculate sensitivity.
Answer:
Case Deconstruction

Torque τ = NIAB balances spring torque , giving θ/I = NAB/k.


Theoretical Application
  • Sensitivity S = (50×2×10⁻⁴×0.2)/10⁻⁶
  • S = 2000 rad/A or ~3.49 × 10⁴ °/A

Critical Evaluation

High sensitivity requires strong B and low k. Practical limitations include mechanical oscillations and temperature effects on springs.

Question 6:
A student observes that a current-carrying solenoid behaves like a bar magnet. Explain this phenomenon using Ampère’s circuital law and compare the magnetic field lines of both.
Answer:
Case Deconstruction

A solenoid with current acts as a magnet due to aligned magnetic dipoles. Ampère’s law confirms the field inside is uniform and axial.

Theoretical Application
  • Solenoid’s field: B = μ₀nI, where n is turns per unit length.
  • Bar magnet’s field resembles a solenoid’s, with lines emerging from N to S pole.
Critical Evaluation

Both exhibit dipole behavior, but solenoid’s field is controllable via current. Example: MRI machines use solenoids for adjustable fields.

Question 7:
An electron moving at 2 × 10⁶ m/s enters a uniform magnetic field of 0.1 T perpendicularly. Calculate the radius of its path and justify why it doesn’t gain energy.
Answer:
Case Deconstruction

Using F = qvB, the electron experiences a centripetal force, forming a circular path.

Theoretical Application
  • Radius: r = mv/qB = (9.1×10⁻³¹ × 2×10⁶)/(1.6×10⁻¹⁹ × 0.1) ≈ 1.14×10⁻⁴ m.
  • Magnetic force is perpendicular to velocity, so work done = 0 (no energy gain).
Critical Evaluation

Example: Cyclotrons use this principle to keep particles in orbit without energy loss.

Question 8:
Two parallel wires carry currents in the same direction. Analyze the force between them and derive its dependence on current and distance.
Answer:
Case Deconstruction

Parallel currents attract due to magnetic interaction, as per Ampère’s force law.

Theoretical Application
  • Force per unit length: F/L = μ₀I₁I₂/2πd, where d is separation.
  • Force ∝ product of currents (I₁I₂) and inversely ∝ distance (1/d).
Critical Evaluation

Example: Power lines use this to minimize sagging. Critical for designing stable electrical grids.

Question 9:
A galvanometer with a coil resistance of 50 Ω shows full-scale deflection at 5 mA. Design a voltmeter for 10 V range using this galvanometer.
Answer:
Case Deconstruction

Galvanometers measure small currents; converting to voltmeter requires a series resistor.

Theoretical Application
  • Total resistance needed: R = V/Ig − G = (10/0.005) − 50 = 1950 Ω.
  • Series resistor = 1950 Ω to limit current to 5 mA at 10 V.
Critical Evaluation

Example: Multimeters use such modifications. Ensures precise voltage measurements without damaging the coil.

Question 10:
A student observes that a current-carrying solenoid behaves like a bar magnet. Explain why this happens and how the magnetic moment of the solenoid is determined.
Answer:
Case Deconstruction

A solenoid with current acts like a bar magnet due to aligned magnetic dipoles from circular loops of current. Our textbook shows that the magnetic moment (m) arises from current (I), area (A), and number of turns (N).

Theoretical Application
  • Magnetic moment formula: m = NIA
  • Direction follows right-hand thumb rule.
Critical Evaluation

Example: A 50-turn solenoid with 2A current and 0.01m² area has m = 1 Am². This matches experimental observations of torque in external fields.

Question 11:
An electron moving at 106 m/s enters a uniform magnetic field of 0.1T perpendicularly. Calculate the radius of its path and compare it with a proton under the same conditions.
Answer:
Case Deconstruction

We studied that charged particles in magnetic fields follow circular paths due to the Lorentz force. Radius (r) depends on mass (m), velocity (v), charge (q), and field (B).

Theoretical Application
  • Formula: r = mv/qB
  • Electron radius: ~5.7 × 10−5 m
  • Proton radius: ~1.0 × 10−3 m (1840× heavier)
Critical Evaluation

The proton’s larger radius confirms its higher inertia. This aligns with cyclotron experiments in our NCERT examples.

Question 12:
Two parallel wires carry currents in the same direction. Analyze the force between them and explain how this principle is used in defining the ampere.
Answer:
Case Deconstruction

Our textbook shows that parallel currents attract due to magnetic interaction. Force per unit length (F/L) is given by F/L = (μ₀I₁I₂)/(2πd).

Theoretical Application
  • Example: 1A currents 1m apart exert 2 × 10−7 N/m force.
  • The ampere is defined using this baseline force.
Critical Evaluation

This matches SI unit definitions. Practical applications include current balance experiments.

Question 13:
A cyclotron accelerates protons to 10MeV. Derive the required magnetic field if the dees have a radius of 0.5m and discuss relativistic limitations.
Answer:
Case Deconstruction

Cyclotrons use uniform B-fields to spiral particles. The final energy (K) relates to B, charge (q), mass (m), and radius (R).

Theoretical Application
  • Formula: B = √(2Km)/(qR)
  • For 10MeV protons: B ≈ 0.72 T
Critical Evaluation

At high energies, relativistic mass increase disrupts resonance. Modern synchrotrons overcome this, as noted in NCERT.

Question 14:

A student sets up an experiment to study the force acting on a current-carrying conductor placed in a magnetic field. The conductor is placed perpendicular to the magnetic field, and the current is varied. The student records the following observations:

  • When current I = 2 A, the force F = 0.04 N
  • When current I = 4 A, the force F = 0.08 N

Based on the observations, answer the following:

  1. State the principle governing this phenomenon.
  2. If the length of the conductor is 10 cm, calculate the magnetic field strength.
Answer:

1. Principle: The phenomenon is governed by Fleming's Left-Hand Rule, which states that when a current-carrying conductor is placed in a magnetic field, it experiences a force perpendicular to both the direction of current and the magnetic field.


2. Calculation of magnetic field strength:


The force on a current-carrying conductor is given by F = BIL, where:

  • F = Force (N)
  • B = Magnetic field strength (T)
  • I = Current (A)
  • L = Length of conductor (m)

Using the first observation (I = 2 A, F = 0.04 N):


0.04 = B × 2 × 0.1 (convert cm to m)


B = 0.04 / (2 × 0.1) = 0.2 T


Cross-verifying with the second observation (I = 4 A, F = 0.08 N):


0.08 = B × 4 × 0.1


B = 0.08 / 0.4 = 0.2 T (consistent)


Thus, the magnetic field strength is 0.2 Tesla.

Question 15:

A circular loop of radius 0.5 m carries a current of 3 A and is placed in a uniform magnetic field of 0.2 T. The plane of the loop is perpendicular to the magnetic field. Answer the following:

  1. Calculate the magnetic dipole moment of the loop.
  2. Determine the torque acting on the loop when its plane makes an angle of 30° with the magnetic field.
Answer:

1. Magnetic dipole moment (m):


The magnetic dipole moment of a current loop is given by m = I × A, where:

  • I = Current (3 A)
  • A = Area of the loop = πr²

Area A = π × (0.5)² = 0.785 m²


m = 3 × 0.785 = 2.356 A·m²


2. Torque (τ) at 30°:


Torque is given by τ = mB sinθ, where:

  • θ = Angle between magnetic moment and field (30°)
  • B = Magnetic field (0.2 T)

τ = 2.356 × 0.2 × sin30°


sin30° = 0.5


τ = 2.356 × 0.2 × 0.5 = 0.2356 N·m


Note: The torque is maximum when θ = 90° and zero when θ = 0° or 180°.

Question 16:
A student sets up an experiment to study the force acting on a current-carrying conductor placed in a magnetic field. The conductor is placed perpendicular to the magnetic field. The student varies the current and observes the deflection of the conductor.

Based on the experiment, answer the following:

  • What is the direction of the force experienced by the conductor? Use Fleming's Left-Hand Rule to explain.
  • How does the magnitude of the force change if the current is doubled while keeping the magnetic field constant?
Answer:

The direction of the force experienced by the conductor can be determined using Fleming's Left-Hand Rule. According to this rule:

  • Stretch the thumb, forefinger, and middle finger of your left hand perpendicular to each other.
  • If the forefinger points in the direction of the magnetic field and the middle finger points in the direction of the current, then the thumb gives the direction of the force acting on the conductor.

If the current is doubled while keeping the magnetic field constant, the magnitude of the force also doubles. This is because the force (F) acting on a current-carrying conductor in a magnetic field is given by the formula:


F = I * L * B * sinθ

where I is the current, L is the length of the conductor, B is the magnetic field, and θ is the angle between the current and the magnetic field. Since θ = 90° (perpendicular), sinθ = 1, and the force is directly proportional to the current.

Question 17:
A circular loop of radius r carries a current I and is placed in a uniform magnetic field B such that the plane of the loop is parallel to the magnetic field.

Answer the following:

  • What is the net force and torque acting on the loop? Justify your answer.
  • If the loop is rotated by 90° such that its plane becomes perpendicular to the magnetic field, how does the torque change?
Answer:

When the plane of the loop is parallel to the magnetic field:

  • The net force acting on the loop is zero because the forces on opposite sides of the loop cancel each other out.
  • The torque acting on the loop is maximum because the angle between the magnetic moment (μ) and the magnetic field (B) is 90°. The torque is given by:

τ = μ * B * sinθ

where θ = 90°, so sinθ = 1, resulting in maximum torque.

If the loop is rotated by 90° such that its plane becomes perpendicular to the magnetic field:

  • The torque becomes zero because the angle between μ and B is now 0° or 180°, and sinθ = 0.

This demonstrates that the torque depends on the orientation of the loop relative to the magnetic field.

Question 18:

A student sets up an experiment to study the force acting on a current-carrying conductor placed in a magnetic field. The conductor is placed perpendicular to the magnetic field, and the current is varied. The student records the following observations:

  • When current I = 2 A, force F = 0.04 N
  • When current I = 4 A, force F = 0.08 N
  • When current I = 6 A, force F = 0.12 N

Based on the observations, answer the following:

(a) State the relationship between the force F and the current I.

(b) If the length of the conductor inside the magnetic field is 10 cm, calculate the magnitude of the magnetic field B.

Answer:

(a) The relationship between the force F and the current I is directly proportional. This is evident from the observations where doubling the current doubles the force, and tripling the current triples the force.


(b) The force acting on a current-carrying conductor in a magnetic field is given by the formula: F = BIL sinθ.


Given: θ = 90° (since the conductor is perpendicular to the field), sin90° = 1.
L = 10 cm = 0.1 m.
Using the first observation (I = 2 A, F = 0.04 N):
0.04 = B × 2 × 0.1
B = 0.04 / 0.2 = 0.2 T.

The magnitude of the magnetic field B is 0.2 Tesla.

Question 19:

A circular loop of radius 0.5 m carries a current of 3 A and is placed in a uniform magnetic field of 0.2 T. The plane of the loop makes an angle of 30° with the direction of the magnetic field. Answer the following:

(a) Calculate the magnetic moment of the loop.

(b) Determine the torque acting on the loop.

Answer:

(a) The magnetic moment (m) of a current-carrying loop is given by: m = I × A, where A is the area of the loop.


Given: I = 3 A, radius r = 0.5 m.
Area A = πr² = 3.14 × (0.5)² = 0.785 m².
m = 3 × 0.785 = 2.355 A·m².

(b) The torque (τ) acting on the loop is given by: τ = mB sinθ, where θ is the angle between the magnetic moment and the field.


Given: B = 0.2 T, θ = 30°.
τ = 2.355 × 0.2 × sin30° = 2.355 × 0.2 × 0.5 = 0.2355 N·m.

The torque acting on the loop is 0.2355 N·m.

Question 20:
A circular loop of radius R carrying current I is placed in a uniform magnetic field B perpendicular to its plane.

(a) Derive the expression for the torque acting on the loop.

(b) If the loop is free to rotate, what will be its orientation in equilibrium? Justify.

Answer:

(a) The torque (τ) acting on a current-carrying loop in a magnetic field is given by:
τ = m × B, where m is the magnetic moment (m = IAN).
For a circular loop, area A = πR² and number of turns N = 1.
Thus, m = IπR².
Since B is perpendicular to the plane, the angle between m and B is 90°.
Therefore, torque τ = mBsin90° = IπR²B.

(b) In equilibrium, the loop will orient itself such that its plane is perpendicular to B (i.e., magnetic moment m aligns parallel to B).
This minimizes potential energy (U = −m·B) and results in zero torque, stabilizing the loop.

Question 21:
A proton and an electron are projected with the same velocity perpendicular to a uniform magnetic field.

(a) Compare the radii of their circular paths.

(b) Explain how the direction of their paths differs due to their charges.

Answer:

(a) The radius (r) of the circular path is given by r = mv/qB.
Since both particles have the same velocity (v) and magnetic field (B), the radius depends on mass (m) and charge (q).
A proton has ~1836 times the mass of an electron but the same charge magnitude.
Thus, the proton's path has a larger radius than the electron's.

(b) The direction of the circular path is determined by the Lorentz force (F = q(v × B)).

  • The proton (+q) follows a clockwise path when viewed along B.
  • The electron (−q) follows a counterclockwise path due to the opposite charge.

Question 22:
A student sets up an experiment to study the force acting on a current-carrying conductor placed in a magnetic field. She uses a flexible wire suspended between the poles of a horseshoe magnet and connects it to a battery. When current flows, the wire deflects.

Explain the underlying principle of this deflection and derive the expression for the force experienced by the wire. Also, state how the direction of force is determined.

Answer:

The deflection of the wire is due to the magnetic force acting on a current-carrying conductor placed in a magnetic field. This is governed by Fleming's Left-Hand Rule.

The force (F) experienced by the wire is given by:
F = I * L * B * sinθ
where:
I = current in the wire,
L = length of the wire in the magnetic field,
B = magnetic field strength,
θ = angle between the current direction and the magnetic field.

When the wire is perpendicular to the field (θ = 90°), the force is maximum (F = I * L * B).

The direction of the force is determined using Fleming's Left-Hand Rule:

  • Stretch the thumb, forefinger, and middle finger of the left hand mutually perpendicular to each other.
  • Forefinger points in the direction of the magnetic field (B).
  • Middle finger points in the direction of the current (I).
  • Thumb gives the direction of the force (F).
Question 23:
A circular loop of radius 10 cm carries a current of 2 A. It is placed in a uniform magnetic field of 0.5 T such that the plane of the loop is perpendicular to the field.

Calculate the magnetic dipole moment of the loop and the torque acting on it. What happens to the torque if the loop is rotated by 30°? Explain with reasoning.

Answer:

The magnetic dipole moment (m) of the loop is given by:
m = I * A
where:
I = current (2 A),
A = area of the loop = πr² = π * (0.1)² = 0.0314 m².
Thus, m = 2 * 0.0314 = 0.0628 A·m².

The torque (τ) acting on the loop is given by:
τ = m * B * sinθ
where:
B = magnetic field (0.5 T),
θ = angle between m and B (initially 90°).
Thus, τ = 0.0628 * 0.5 * sin90° = 0.0314 N·m.

When the loop is rotated by 30°, the angle θ becomes 60°.
The new torque is: τ = 0.0628 * 0.5 * sin60° = 0.0272 N·m.

The torque decreases because the sinθ term reduces as θ moves away from 90°. The torque is maximum when θ = 90° and zero when θ = 0°.

Question 24:
A student sets up an experiment to study the force acting on a current-carrying conductor placed in a magnetic field. The conductor is placed perpendicular to the magnetic field, and the current is varied. The student records the following observations:

Current (A) | Force (N)
1.0 | 0.05
2.0 | 0.10
3.0 | 0.15

Based on the data, answer the following:
1. State the relationship between the current and the force experienced by the conductor.
2. If the length of the conductor is doubled while keeping the current constant at 2.0 A, what will be the new force experienced? Justify your answer.
Answer:

1. The relationship between the current (I) and the force (F) experienced by the conductor is directly proportional. This is evident from the data, as doubling the current (from 1.0 A to 2.0 A) doubles the force (from 0.05 N to 0.10 N), and tripling the current (to 3.0 A) triples the force (to 0.15 N). This aligns with the formula F = IBL sinθ, where B is the magnetic field, L is the length of the conductor, and θ is the angle between the current and the magnetic field (here, θ = 90°, so sinθ = 1).


2. If the length of the conductor is doubled while keeping the current constant at 2.0 A, the new force will be 0.20 N. This is because the force is also directly proportional to the length of the conductor (L) as per the formula F = IBL. Since the original force at 2.0 A was 0.10 N, doubling the length will double the force to 0.20 N.

Question 25:
A circular loop of radius 0.1 m carries a current of 2 A and is placed in a uniform magnetic field of 0.5 T. The plane of the loop is perpendicular to the magnetic field. Calculate:
1. The magnetic dipole moment of the loop.
2. The torque acting on the loop. What happens to the torque if the plane of the loop is rotated to make an angle of 30° with the magnetic field?
Answer:

1. The magnetic dipole moment (m) of the loop is given by the formula:
m = I × A, where I is the current and A is the area of the loop.
Area of the loop, A = πr² = π × (0.1)² = 0.0314 m².
Thus, m = 2 × 0.0314 = 0.0628 A·m².


2. The torque (τ) acting on the loop when the plane is perpendicular to the magnetic field is:
τ = mB sinθ, where θ is the angle between m and B.
Here, θ = 90°, so sin 90° = 1.
Thus, τ = 0.0628 × 0.5 × 1 = 0.0314 N·m.


If the plane of the loop is rotated to 30°, the angle between m and B becomes θ = 60° (since m is perpendicular to the plane of the loop).
The new torque is τ = 0.0628 × 0.5 × sin 60° = 0.0628 × 0.5 × 0.866 = 0.0272 N·m.
The torque decreases because the component of the magnetic moment perpendicular to the field reduces.

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