Work and Energy – CBSE NCERT Study Resources

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Work and Energy

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9th

9th - Science

Work and Energy

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Overview of the Chapter: Work and Energy

This chapter introduces the fundamental concepts of work and energy, which are crucial in understanding various physical phenomena. Students will learn how work is calculated, the different forms of energy, and the principle of conservation of energy.

Work: Work is said to be done when a force applied on an object causes displacement in the direction of the force. Mathematically, work (W) is the product of force (F) and displacement (s) in the direction of the force: W = F × s × cosθ, where θ is the angle between the force and displacement.

Energy: Energy is the capacity to do work. It exists in various forms such as kinetic energy, potential energy, heat energy, etc. The SI unit of energy is the joule (J).

Types of Energy

  • Kinetic Energy: The energy possessed by an object due to its motion. It is given by KE = ½ mv², where m is mass and v is velocity.
  • Potential Energy: The energy stored in an object due to its position or configuration. For example, gravitational potential energy is PE = mgh, where h is height.

Work-Energy Theorem

The work-energy theorem states that the work done by the net force on an object is equal to the change in its kinetic energy: W = ΔKE.

Conservation of Energy

Energy can neither be created nor destroyed; it only transforms from one form to another. The total energy in an isolated system remains constant.

Power

Power: Power is the rate of doing work or the rate of energy transfer. It is calculated as P = W/t, where W is work done and t is time. The SI unit of power is the watt (W).

Commercial Unit of Energy

The commercial unit of energy is the kilowatt-hour (kWh), commonly used in electricity bills. 1 kWh = 3.6 × 10⁶ J.

Summary of Key Formulas

Concept Formula
Work W = F × s × cosθ
Kinetic Energy KE = ½ mv²
Potential Energy PE = mgh
Power P = W/t

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define work in physics.
Answer:

Work is force multiplied by displacement in force's direction.

Question 2:
What is the SI unit of energy?
Answer:

The SI unit of energy is joule (J).

Question 3:
Give an example of potential energy from NCERT.
Answer:

A stretched bow has potential energy.

Question 4:
State the work-energy theorem.
Answer:

Work done equals change in kinetic energy.

Question 5:
Name the form of energy in a moving car.
Answer:

Kinetic energy.

Question 6:
What is 1 joule of work?
Answer:

1 joule is work done by 1N force over 1m.

Question 7:
Give a real-life example of mechanical energy.
Answer:

A swinging pendulum has mechanical energy.

Question 8:
What happens to energy when work is done?
Answer:

Energy is transferred or transformed.

Question 9:
Define power in physics.
Answer:

Power is the rate of doing work.

Question 10:
Name the energy stored in food.
Answer:

Chemical energy.

Question 11:
What is the law of conservation of energy?
Answer:

Energy cannot be created or destroyed.

Question 12:
Give an NCERT example of kinetic energy.
Answer:

A moving bicycle has kinetic energy.

Question 13:
What is the commercial unit of energy?
Answer:

Kilowatt-hour (kWh).

Question 14:
Name the energy conversion in a solar cell.
Answer:

Solar to electrical energy.

Question 15:
Define work in scientific terms.
Answer:

In science, work is said to be done when a force applied on an object causes displacement in the direction of the force.
Mathematically, Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between force and displacement.

Question 16:
What is the SI unit of work and energy?
Answer:

The SI unit of both work and energy is the joule (J).
1 joule is defined as the work done when a force of 1 newton displaces an object by 1 meter in the direction of the force.

Question 17:
State the law of conservation of energy.
Answer:

The law of conservation of energy states that energy can neither be created nor destroyed, but it can only be transformed from one form to another.
The total energy in an isolated system remains constant.

Question 18:
Differentiate between kinetic energy and potential energy with examples.
Answer:
  • Kinetic energy is the energy possessed by a body due to its motion (e.g., a moving car).
  • Potential energy is the energy stored in a body due to its position or state (e.g., water stored in a dam).
Question 19:
Calculate the work done when a force of 10 N moves an object by 5 m in the direction of the force.
Answer:

Work (W) = Force (F) × Displacement (s)
Given: F = 10 N, s = 5 m
W = 10 × 5 = 50 J

Question 20:
What is the commercial unit of energy? How is it related to joules?
Answer:

The commercial unit of energy is the kilowatt-hour (kWh).
1 kWh = 3.6 × 106 joules (J). It is used for measuring electrical energy consumption.

Question 21:
A boy lifts a 2 kg book to a height of 1.5 m. Calculate the work done against gravity. (g = 10 m/s²)
Answer:

Work done (W) = Force (F) × Displacement (s)
Force = Weight = mass (m) × gravity (g) = 2 × 10 = 20 N
W = 20 × 1.5 = 30 J

Question 22:
Name two forms of mechanical energy.
Answer:

The two forms of mechanical energy are:
1. Kinetic energy (energy due to motion)
2. Potential energy (energy due to position or configuration).

Question 23:
What is the power of a machine that does 200 J of work in 5 seconds?
Answer:

Power (P) = Work (W) / Time (t)
Given: W = 200 J, t = 5 s
P = 200 / 5 = 40 watts (W)

Question 24:
Why is no work done when you push a wall but it doesn't move?
Answer:

Work is done only when there is displacement in the direction of the applied force.
Since the wall doesn't move (displacement = 0), work done is zero.

Question 25:
Give an example where potential energy is converted into kinetic energy.
Answer:

When a stretched bow is released, the potential energy stored in it is converted into kinetic energy of the arrow.

Question 26:
What happens to the kinetic energy of an object if its velocity is doubled?
Answer:

Kinetic energy (KE) is proportional to the square of velocity (KE = ½ mv²).
If velocity is doubled, KE becomes four times the original value.

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
Define work in terms of physics.
Answer:

In physics, work is said to be done when a force applied on an object causes its displacement in the direction of the force.
Mathematically, Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between force and displacement.

Question 2:
What is the SI unit of work and energy?
Answer:

The SI unit of both work and energy is the joule (J).
1 joule is defined as the work done when a force of 1 newton displaces an object by 1 meter in the direction of the force.

Question 3:
Differentiate between potential energy and kinetic energy with an example.
Answer:

Potential energy is the energy stored in an object due to its position or state (e.g., water in a dam).
Kinetic energy is the energy possessed by an object due to its motion (e.g., a moving car).

Question 4:
A force of 10 N displaces an object by 5 m. Calculate the work done if the force and displacement are in the same direction.
Answer:

Given: Force (F) = 10 N, Displacement (s) = 5 m, θ = 0° (same direction).
Work (W) = F × s × cosθ
= 10 × 5 × cos0°
= 10 × 5 × 1
= 50 J.

Question 5:
What is the law of conservation of energy? Give an example.
Answer:

The law of conservation of energy states that energy can neither be created nor destroyed, only transformed from one form to another.
Example: In a pendulum, potential energy converts to kinetic energy and vice versa, but the total energy remains constant.

Question 6:
Why is the work done by centripetal force on a circular path zero?
Answer:

Centripetal force acts perpendicular to the direction of displacement (tangential) in circular motion.
Since work (W) = F × s × cos90° and cos90° = 0,
W = 0.

Question 7:
Calculate the kinetic energy of a 2 kg object moving at 3 m/s.
Answer:

Given: Mass (m) = 2 kg, Velocity (v) = 3 m/s.
Kinetic Energy (K.E.) = ½ mv²
= ½ × 2 × (3)²
= ½ × 2 × 9
= 9 J.

Question 8:
What is power? Write its SI unit.
Answer:

Power is the rate of doing work or the rate of energy transfer.
SI unit: watt (W), where 1 W = 1 joule/second.

Question 9:
A boy lifts a 5 kg book to a height of 1.5 m. Calculate the work done against gravity. (g = 10 m/s²)
Answer:

Given: Mass (m) = 5 kg, Height (h) = 1.5 m, g = 10 m/s².
Work done (W) = mgh
= 5 × 10 × 1.5
= 75 J.

Question 10:
Explain why no work is done when holding a heavy object stationary.
Answer:

Work is done only when there is displacement in the direction of the force.
Since the object is stationary (s = 0),
Work (W) = F × 0 = 0 J.

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
Define work in scientific terms and state its SI unit.
Answer:

In physics, work is defined as the product of the force applied on an object and the displacement caused by that force in the direction of the force.
Mathematically, Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between the force and displacement.
The SI unit of work is the joule (J), which is equivalent to 1 newton-meter (N·m).

Question 2:
Differentiate between potential energy and kinetic energy with one example each.
Answer:

Potential Energy is the energy stored in an object due to its position or configuration.
Example: A stretched rubber band has elastic potential energy.
Kinetic Energy is the energy possessed by an object due to its motion.
Example: A moving car has kinetic energy due to its velocity.

Question 3:
Explain the law of conservation of energy with an example from daily life.
Answer:

The law of conservation of energy states that energy cannot be created or destroyed; it can only be transformed from one form to another.
Example: When a pendulum swings, its potential energy at the highest point converts to kinetic energy at the lowest point, and vice versa, but the total energy remains constant.

Question 4:
Calculate the work done when a force of 15 N moves an object by 2 m in the direction of the force.
Answer:

Given: Force (F) = 15 N, Displacement (s) = 2 m, Angle (θ) = 0° (since force and displacement are in the same direction).
Work (W) = F × s × cosθ
W = 15 N × 2 m × cos0°
W = 15 × 2 × 1 (since cos0° = 1)
W = 30 J.
Thus, the work done is 30 joules.

Question 5:
What is power? How is it related to work and time?
Answer:

Power is the rate at which work is done or energy is transferred.
Mathematically, Power (P) = Work (W) / Time (t).
The SI unit of power is the watt (W), which is equal to 1 joule per second (J/s).
Higher power means work is done faster, while lower power means work is done slower.

Question 6:
A boy lifts a 5 kg book to a height of 1.5 m. Calculate the work done against gravity. (Take g = 10 m/s²)
Answer:

Given: Mass (m) = 5 kg, Height (h) = 1.5 m, Acceleration due to gravity (g) = 10 m/s².
Force required to lift the book = Weight = m × g = 5 kg × 10 m/s² = 50 N.
Work done (W) = Force × Displacement = 50 N × 1.5 m = 75 J.
Thus, the work done against gravity is 75 joules.

Question 7:
Explain the relationship between work and energy with an example.
Answer:

Work and energy are closely related concepts. Work is the transfer of energy from one object to another or the conversion of energy from one form to another. For example, when you lift a book from the ground to a table, you do work against gravity, and this work is stored as potential energy in the book.
Similarly, when the book falls, this potential energy is converted into kinetic energy, demonstrating the interchangeability of work and energy.

Question 8:
Calculate the work done when a force of 10 N displaces an object by 5 m in the direction of the force.
Answer:

Given:
Force (F) = 10 N
Displacement (s) = 5 m
Angle (θ) = 0° (since force and displacement are in the same direction)

Using the formula for work:
W = F × s × cosθ
W = 10 N × 5 m × cos0°
Since cos0° = 1,
W = 10 × 5 × 1 = 50 J
Thus, the work done is 50 joules.

Question 9:
State the law of conservation of energy and give a real-life example.
Answer:

The law of conservation of energy states that energy cannot be created or destroyed, but it can only be transformed from one form to another. The total energy in an isolated system remains constant.
Example: In a swinging pendulum, potential energy at the highest point converts to kinetic energy at the lowest point, and vice versa, but the total energy remains unchanged.

Question 10:
A boy lifts a 2 kg book to a height of 1.5 m. Calculate the work done against gravity. (Take g = 10 m/s²)
Answer:

Given:
Mass (m) = 2 kg
Height (h) = 1.5 m
Acceleration due to gravity (g) = 10 m/s²
Force required (F) = m × g = 2 × 10 = 20 N
Work done (W) = F × h
W = 20 N × 1.5 m
W = 30 joules (J).
Note: The work is done against the gravitational force.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Define work in scientific terms. Explain with an example when work is zero despite a force being applied.
Answer:
Concept Overview

In science, work is done when a force causes displacement in its direction. It is calculated as Work = Force × Displacement × cosθ.

Process Explanation

Work is zero if displacement is zero or force is perpendicular to displacement. For example, pushing a wall doesn’t do work as there’s no displacement.

Real-world Application

Our textbook shows a coolie carrying luggage horizontally—work done against gravity is zero since displacement is perpendicular to the force.

Question 2:
What is kinetic energy? Derive its formula KE = ½ mv² using an activity from NCERT.
Answer:
Concept Overview

Kinetic energy is the energy possessed by a moving object. It depends on mass (m) and velocity (v).

Process Explanation

We studied in NCERT how a rolling ball does work. Using Work = Force × Displacement and Newton’s laws, we integrate to derive KE = ½ mv².

Real-world Application

A faster cricket ball has more KE, causing greater impact—just like in our textbook example.

Question 3:
Explain potential energy with two examples. How is it different from kinetic energy?
Answer:
Concept Overview

Potential energy is stored energy due to position/stress, like a stretched spring or raised object.

Process Explanation

Our textbook shows water in a dam has gravitational PE. Unlike kinetic energy (motion-based), PE depends on height (PE = mgh).

Real-world Application

A bow stores elastic PE when drawn. When released, it converts to KE—just like NCERT’s archery example.

Question 4:
Describe the law of conservation of energy with a pendulum example from NCERT.
Answer:
Concept Overview

Energy cannot be created/destroyed—it only converts forms. Total energy remains constant.

Process Explanation

In NCERT’s pendulum example, PE at the top converts to KE at the bottom. Friction aside, the sum stays the same.

Real-world Application

A roller coaster mimics this: PE at the peak transforms into KE during the drop, just like our textbook explains.

Question 5:
What is power? Compare the power of two students climbing stairs—one fast, one slow—using NCERT’s definition.
Answer:
Concept Overview

Power is the rate of doing work (Power = Work/Time). It measures how fast energy is transferred.

Process Explanation

Our textbook defines power using stairs. If both students do equal work (same height), the faster one has higher power as time is less.

Real-world Application

Like a bulb’s wattage, higher power means quicker energy use—similar to NCERT’s electric appliances example.

Question 6:
Define work in scientific terms and explain how it relates to force and displacement. Provide an NCERT example and a real-world application.
Answer:
Concept Overview

Work is done when a force causes displacement in its direction. It is calculated as W = F × s × cosθ.

Process Explanation

Our textbook shows lifting a book: work is done against gravity. If force or displacement is zero, no work is done.

Real-world Application

Pushing a wall doesn’t do work as there’s no displacement, but pushing a cart does.

Question 7:
Differentiate between potential energy and kinetic energy with examples from NCERT and daily life.
Answer:
Concept Overview

Potential energy is stored energy (e.g., height), while kinetic energy is due to motion.

Process Explanation

NCERT shows a stretched bow (potential) and moving arrow (kinetic). Energy interconversion follows the law of conservation.

Real-world Application

A roller coaster at the top has potential energy, which converts to kinetic as it descends.

Question 8:
Explain the law of conservation of energy using an NCERT activity and a practical example.
Answer:
Concept Overview

Energy cannot be created or destroyed, only transformed. Total energy remains constant.

Process Explanation

NCERT’s swinging pendulum shows kinetic ↔ potential energy conversion without loss.

Real-world Application

In hydroelectric plants, water’s potential energy converts to electrical energy, conserving total energy.

Question 9:
Describe how power is calculated and compare two NCERT examples of high and low power tasks.
Answer:
Concept Overview

Power is work done per unit time (P = W/t). It measures how fast energy is transferred.

Process Explanation

NCERT compares a laborer lifting bricks slowly (low power) vs. a machine doing it faster (high power).

Real-world Application

A sprinter (high power) finishes a race faster than a marathon runner (low power).

Question 10:
What is commercial unit of energy? Relate it to household electricity consumption using NCERT data.
Answer:
Concept Overview

The commercial unit is kilowatt-hour (kWh), used for billing. 1 kWh = 3.6 × 106 J.

Process Explanation

NCERT states a 100W bulb running for 10 hours consumes 1 kWh, costing as per local rates.

Real-world Application

Our electricity bill depends on total kWh consumed by appliances like fans and refrigerators.

Question 11:
Define work in scientific terms and explain how it is calculated. Provide an example from NCERT and a real-world scenario.
Answer:
Concept Overview

In science, work is done when a force causes displacement. It is calculated as Work (W) = Force (F) × Displacement (s) × cosθ.

Process Explanation

Our textbook shows lifting a book vertically, where θ=0° and cosθ=1. If force is 10N and displacement is 2m, work done is 20J.

Real-world Application

Pushing a stalled car horizontally applies force, but if it doesn’t move, no work is done as displacement is zero.

Question 12:
Differentiate between kinetic energy and potential energy with NCERT and practical examples.
Answer:
Concept Overview

Kinetic energy is due to motion, while potential energy is stored due to position or state.

Process Explanation

NCERT explains a moving car has kinetic energy, whereas water stored in a dam has gravitational potential energy.

Real-world Application

A stretched rubber band has elastic potential energy, which converts to kinetic energy when released.

Question 13:
Explain the law of conservation of energy using an example from daily life and NCERT.
Answer:
Concept Overview

Energy cannot be created or destroyed, only transformed. Total energy remains constant.

Process Explanation

NCERT shows a swinging pendulum where potential energy converts to kinetic energy and vice versa, but total energy stays the same.

Real-world Application

In a hydroelectric plant, water’s potential energy converts to kinetic, then to electrical energy, conserving total energy.

Question 14:
Describe how power is related to work and time. Give an NCERT and real-life example.
Answer:
Concept Overview

Power is the rate of doing work, calculated as Power (P) = Work (W) / Time (t).

Process Explanation

NCERT compares two laborers lifting bricks: one taking 10s (higher power) and another taking 20s (lower power) for the same work.

Real-world Application

A faster electric motor pumps water quicker, demonstrating higher power than a slower one.

Question 15:
What is mechanical energy? Explain with an NCERT example and a practical application.
Answer:
Concept Overview

Mechanical energy is the sum of kinetic and potential energy in a system.

Process Explanation

NCERT describes a roller coaster: at the top, it has maximum potential energy, which converts to kinetic energy as it descends.

Real-world Application

A bouncing ball loses some mechanical energy as heat/sound but mostly converts between kinetic and potential energy.

Question 16:
Define work in scientific terms and state its SI unit. Explain with an example when work is said to be done and when it is not, even if force is applied.
Answer:

In Science, work is defined as the product of the force applied on an object and the displacement caused by that force in the direction of the force. Mathematically, it is expressed as:
Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between the force and displacement.

The SI unit of work is the joule (J), which is equivalent to 1 newton-meter (N·m).

Example of work done: When you push a box horizontally across the floor, and it moves in the direction of the force, work is done because both force and displacement are in the same direction (θ = 0°, cos0° = 1).

Example of work not done: If you hold a heavy bag stationary for some time, no work is done on the bag even though you apply a force because there is zero displacement (s = 0). Similarly, if you push a wall and it doesn’t move, no work is done despite applying force.

Question 17:
Differentiate between potential energy and kinetic energy with suitable examples. How can one form of energy be converted into the other? Explain with a real-life scenario.
Answer:

Potential Energy (PE) is the energy stored in an object due to its position or configuration. It depends on factors like height or elasticity.
Example: A book placed on a shelf has gravitational potential energy due to its height above the ground.

Kinetic Energy (KE) is the energy possessed by an object due to its motion. It depends on the mass and velocity of the object.
Example: A moving car has kinetic energy because of its motion.

Conversion of Energy: Potential energy can be converted into kinetic energy and vice versa.
Real-life scenario: When a roller coaster is at the top of a hill, it has maximum potential energy. As it descends, this energy is converted into kinetic energy, increasing its speed. At the bottom, most of the energy is kinetic, and as it climbs again, kinetic energy is converted back to potential energy.

This interconversion demonstrates the Law of Conservation of Energy, which states that energy cannot be created or destroyed, only transformed from one form to another.

Question 18:
Define work in scientific terms and explain the conditions under which work is said to be done. Provide an example to illustrate your answer.
Answer:

In science, work is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, it is expressed as:

Work (W) = Force (F) × Displacement (s) × cosθ

where θ is the angle between the force and displacement vectors.

For work to be done, the following conditions must be met:

  • A force must be applied to the object.
  • The object must undergo displacement due to the applied force.
  • The displacement must have a component in the direction of the force (i.e., θ ≠ 90°).

Example: Pushing a box across the floor. Here, the applied force causes the box to move (displacement), and since the force and displacement are in the same direction (θ = 0°), work is done.

Note: If you push a wall and it doesn’t move, no work is done because there is no displacement (s = 0). Similarly, holding a heavy bag stationary does no work as there is no displacement.

Question 19:
Define work in scientific terms and explain the conditions under which work is said to be done. Provide an example where a force is applied but no work is done, justifying your answer.
Answer:

In scientific terms, work is said to be done when a force applied on an object causes a displacement in the direction of the force. The two essential conditions for work to be done are:

1. A force must act on the object.
2. The object must undergo displacement in the direction of the force.

Mathematically, work (W) is calculated as:

W = F × d × cosθ

where F is the force applied, d is the displacement, and θ is the angle between the force and displacement.

Example where no work is done: If a person holds a heavy bag stationary for some time, no work is done because although a force is applied (to counteract gravity), there is no displacement in the direction of the force. Hence, W = 0.

Question 20:
Define work in scientific terms and explain its relationship with energy. Provide an example where work is done and another where no work is done, justifying your answers.
Answer:

In scientific terms, work is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, it is expressed as:

Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between the force and displacement vectors.

The relationship between work and energy is that work done on an object results in a change in its energy. For example, when work is done to lift an object, its potential energy increases. Similarly, when work is done to accelerate an object, its kinetic energy increases.

Example where work is done: Pushing a box across the floor. Here, force is applied in the direction of displacement, so work is done.

Example where no work is done: Holding a heavy bag stationary. Although force is applied, there is no displacement, so no work is done (since s = 0).

This concept is crucial in understanding how energy is transferred and transformed in real-world scenarios, aligning with the law of conservation of energy.

Question 21:
Define work in the context of physics. Explain with an example when work is said to be done and when it is not. Also, derive the expression for work done when a force acts on an object at an angle to the direction of displacement.
Answer:

In physics, work is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, work (W) is given by:

W = F × s × cosθ

where F is the force applied, s is the displacement, and θ is the angle between the force and the direction of displacement.

Example of work done: When you push a box horizontally across the floor, and the box moves in the direction of the applied force, work is done. Here, θ = 0°, so cosθ = 1, and W = F × s.

Example of work not done: If you hold a heavy bag stationary for some time, no work is done because there is no displacement (s = 0). Similarly, if you push a wall and it doesn’t move, no work is done.

Derivation of work done at an angle:

1. Consider a force F acting at an angle θ to the displacement s.
2. The component of force in the direction of displacement is Fcosθ.
3. Work done is the product of this component and displacement: W = (Fcosθ) × s.
4. Thus, W = F × s × cosθ.

This formula shows that work is maximum when θ = 0° (force and displacement are in the same direction) and zero when θ = 90° (force is perpendicular to displacement).

Question 22:
Define work in scientific terms and explain its relationship with energy. Support your answer with an example where work done results in a change of energy.
Answer:

In Science, work is defined as the product of the force applied on an object and the displacement caused by that force in the direction of the force. Mathematically, it is expressed as:

Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between the force and displacement vectors.

The relationship between work and energy is fundamental. Work is a way to transfer energy from one system to another. When work is done on an object, its energy changes. For example, if you lift a book from the ground to a table, you do work against gravity, and the book gains gravitational potential energy.

Example: Consider pushing a stationary bicycle to make it move. Here:

1. You apply a force on the bicycle.
2. The bicycle moves in the direction of the force (displacement).
3. The work done by you transfers energy to the bicycle, increasing its kinetic energy.

Thus, work and energy are interconnected—work done results in an energy change, and energy enables the capacity to do work.

Question 23:
Define work in the context of physics and explain its relationship with energy. Provide an example where work is done and another where no work is done, justifying your answer with the formula W = F × s × cosθ.
Answer:

In physics, work is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, it is expressed as W = F × s × cosθ, where W is work, F is the applied force, s is the displacement, and θ is the angle between the force and displacement vectors.

Work and energy are closely related. When work is done on an object, energy is transferred to or from it. For example, lifting a box against gravity increases its potential energy, while pushing a moving object increases its kinetic energy.

Example where work is done: Pushing a box horizontally across the floor. Here, the force and displacement are in the same direction (θ = 0°), so cosθ = 1, and work is done (W = F × s).

Example where no work is done: Holding a heavy bag stationary. Although force is applied, there is no displacement (s = 0), so W = 0. Similarly, if the force is perpendicular to displacement (θ = 90°), cosθ = 0, and no work is done.

Question 24:
Explain the law of conservation of energy with an example. How does this law apply to a swinging pendulum? Discuss the energy transformations involved.
Answer:

The law of conservation of energy states that energy can neither be created nor destroyed, but it can only be transformed from one form to another. The total energy of an isolated system remains constant.

Example: A swinging pendulum demonstrates this law perfectly. At the highest point of its swing, the pendulum has maximum potential energy (due to height) and zero kinetic energy (as velocity is zero). As it swings down:
- Potential energy converts to kinetic energy.
- At the lowest point, kinetic energy is maximum and potential energy is minimum.
- The cycle repeats, showing continuous energy transformation without loss (assuming no friction).

Energy Transformations:

  • Potential Energy → Kinetic Energy → Potential Energy (and so on).
  • Total mechanical energy (PE + KE) remains constant if dissipative forces like air resistance are ignored.

Question 25:
Explain the law of conservation of energy with an example. How does this law apply to a simple pendulum?
Answer:

The law of conservation of energy states that energy can neither be created nor destroyed, but it can only be transformed from one form to another. The total energy of an isolated system remains constant.

Example: When a ball is dropped from a height, its potential energy (due to height) converts into kinetic energy (due to motion) as it falls. At any point during the fall, the sum of potential and kinetic energy remains constant, ignoring air resistance.

Application in a simple pendulum:

  • At the highest point of its swing, the pendulum has maximum potential energy and zero kinetic energy (since it momentarily stops).
  • As it swings down, potential energy converts to kinetic energy.
  • At the lowest point, it has maximum kinetic energy and minimum potential energy.
  • The total mechanical energy (sum of kinetic and potential energy) remains constant if we ignore air resistance and friction.
Thus, the pendulum demonstrates the conservation of energy as energy continuously transforms between kinetic and potential forms.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
A boy pushes a box with a force of 20 N, moving it 5 m. The work done is calculated as 100 J. Later, he lifts a 2 kg book to a height of 1.5 m. Compare the work done in both cases using W = F × d and W = mgh.
Answer:
Case Summary

A boy performs work by pushing a box and lifting a book.

Scientific Principle
  • Work done (W) = Force (F) × Displacement (d)
  • Work against gravity (W) = mass (m) × g × height (h)
Solution Approach

For the box: W = 20 N × 5 m = 100 J. For the book: W = 2 kg × 10 m/s² × 1.5 m = 30 J. Our textbook shows similar examples like lifting water from a well.

Question 2:
A pendulum swings from point A to B. At A, it has maximum potential energy, and at B, it has maximum kinetic energy. Explain the energy transformation using the law of conservation of energy.
Answer:
Case Summary

A pendulum transforms energy between potential and kinetic forms.

Scientific Principle
  • Potential energy (PE) = mgh
  • Kinetic energy (KE) = ½mv²
  • Total energy remains conserved.
Solution Approach

At A, PE is max as height is max, and KE is zero. At B, KE is max as speed is max, and PE is zero. Our textbook shows this in the swinging pendulum example.

Question 3:
A battery-powered toy car moves 10 m in 5 s with a force of 2 N. Calculate its power. Compare this with a real-world example like a ceiling fan.
Answer:
Case Summary

A toy car's power is calculated and compared to a ceiling fan.

Scientific Principle
  • Power (P) = Work (W) / Time (t)
  • Work (W) = Force (F) × Displacement (d)
Solution Approach

W = 2 N × 10 m = 20 J. P = 20 J / 5 s = 4 W. A ceiling fan has higher power (e.g., 50 W) as it does more work. Our textbook explains power using lifting objects.

Question 4:
A spring is compressed by 0.1 m with a force of 10 N. Calculate its elastic potential energy. Relate this to NCERT's example of a stretched bow.
Answer:
Case Summary

A spring stores elastic potential energy when compressed.

Scientific Principle
  • Elastic PE = ½kx² (k = F/x)
Solution Approach

k = 10 N / 0.1 m = 100 N/m. Elastic PE = ½ × 100 × (0.1)² = 0.5 J. Our textbook shows a similar example with a stretched bow storing energy before releasing an arrow.

Question 5:
A force of 20 N displaces an object by 5 m in the direction of the force. Calculate the work done. Also, explain how this relates to the NCERT example of pushing a wall.
Answer:
Case Summary
Force = 20 N, Displacement = 5 m.
Scientific Principle
Work done = Force × Displacement (W = F × s).
Solution Approach
  • W = 20 N × 5 m = 100 J.
  • In NCERT, pushing a wall does zero work as displacement is zero.

This shows work depends on force and displacement, like lifting a bag (real-world example).

Question 6:
A boy lifts a 5 kg book to a height of 2 m. Calculate the potential energy gained. Compare this with the NCERT example of a stretched bow.
Answer:
Case Summary
Mass = 5 kg, Height = 2 m, g = 10 m/s².
Scientific Principle
Potential energy (PE) = mgh.
Solution Approach
  • PE = 5 × 10 × 2 = 100 J.
  • In NCERT, a stretched bow stores elastic PE, similar to lifting books (gravitational PE).

Both involve energy storage, like a raised hammer (real-world).

Question 7:
A car of mass 1000 kg moves at 10 m/s. Find its kinetic energy. How does this differ from the NCERT example of a rolling ball?
Answer:
Case Summary
Mass = 1000 kg, Velocity = 10 m/s.
Scientific Principle
Kinetic energy (KE) = ½mv².
Solution Approach
  • KE = ½ × 1000 × (10)² = 50,000 J.
  • NCERT’s rolling ball has lesser KE due to smaller mass.

KE depends on mass and speed, like a moving bus (real-world).

Question 8:
A machine delivers 200 J of work in 5 s. Calculate its power. Relate this to the NCERT example of a laborer carrying a load.
Answer:
Case Summary
Work = 200 J, Time = 5 s.
Scientific Principle
Power = Work/Time.
Solution Approach
  • Power = 200 J / 5 s = 40 W.
  • In NCERT, a laborer’s power is lower due to slower work rate.

Power measures work speed, like a faster engine (real-world).

Question 9:
A boy pushes a box with a force of 20 N, moving it 5 m. Work done is calculated as force × displacement. Case Summary: If the angle between force and displacement is 30°, how does work change?
Answer:
Case Summary

A boy applies force at an angle to displace a box.

Scientific Principle

Work (W) = F × d × cosθ. Our textbook shows this formula in Work and Energy chapter.

Solution Approach
  • Given: F = 20 N, d = 5 m, θ = 30°
  • W = 20 × 5 × cos30° = 100 × 0.866 = 86.6 J
Question 10:
A pendulum swings from A to B. Case Summary: At point A, it has maximum potential energy. Explain energy transformation using kinetic energy.
Answer:
Case Summary

A pendulum converts energy between potential and kinetic forms.

Scientific Principle

As per NCERT, at highest point (A), PE is max and KE is zero. At lowest point, KE is max and PE is zero.

Solution Approach
  • PE decreases as pendulum descends
  • KE increases due to velocity gain
  • Total energy remains conserved
Question 11:
A spring is compressed by 0.1 m with force 50 N. Case Summary: Calculate elastic potential energy stored using spring constant k = F/x.
Answer:
Case Summary

Spring stores energy when compressed.

Scientific Principle

We studied that EPE = ½kx². NCERT gives similar examples in Work and Energy.

Solution Approach
  • First find k = F/x = 50/0.1 = 500 N/m
  • EPE = ½ × 500 × (0.1)² = 2.5 J
Question 12:
A water pump lifts 50 kg water to 10 m height in 20 s. Case Summary: Compare work done and power using g = 10 m/s².
Answer:
Case Summary

Pump performs work against gravity.

Scientific Principle

Work = mgh, Power = Work/time. Our textbook shows similar calculations.

Solution Approach
  • Work = 50 × 10 × 10 = 5000 J
  • Power = 5000/20 = 250 W
  • Real-world example: Water pumps in farms
Question 13:

Rahul pushes a box with a force of 50 N for a distance of 10 m along a straight path. However, the box does not move. Based on this scenario, answer the following:

  • Is work being done on the box? Justify your answer.
  • If the box had moved, how would the work done be calculated? Show the steps.
Answer:

Answer:

Work is not being done on the box because displacement is zero. Work is defined as the product of force and displacement in the direction of the force (W = F × s × cosθ). Since the box does not move (s = 0), W = 0.


If the box had moved, the work done would be calculated as follows:


W = F × s
Given: F = 50 N, s = 10 m
W = 50 × 10 = 500 J


Note: If the force is applied at an angle, only the component of force in the direction of displacement does work.

Question 14:

A pendulum swings from point A to point B. At point A, it has maximum potential energy, and at point B, it has maximum kinetic energy. Explain:

  • How does the energy transformation occur during this motion?
  • What happens to the total mechanical energy of the pendulum if air resistance is neglected?
Answer:

Answer:

During the swing of the pendulum:

  • At point A, the pendulum has maximum potential energy (height is maximum) and zero kinetic energy (velocity is zero).
  • As it moves toward point B, potential energy converts to kinetic energy due to the decrease in height and increase in velocity.
  • At point B, all potential energy is converted to kinetic energy (velocity is maximum, height is minimum).

If air resistance is neglected, the total mechanical energy (sum of kinetic and potential energy) remains constant due to the law of conservation of energy.


Note: In real-world scenarios, air resistance causes energy loss as heat, reducing the total mechanical energy over time.

Question 15:
A student pushes a box of mass 5 kg with a force of 20 N over a distance of 10 m on a frictionless surface. However, the box was initially at rest.

(i) Calculate the work done by the student on the box.
(ii) If the same box is now pushed over the same distance but with a frictional force of 5 N opposing the motion, how does the work done change? Justify your answer.

Answer:

(i) Work done (W) is calculated using the formula:
W = Force × Displacement × cosθ
Here, θ = 0° (since force and displacement are in the same direction), so cos0° = 1.
Thus, W = 20 N × 10 m × 1 = 200 J.

(ii) When friction (5 N) opposes the motion, the net force acting on the box becomes:
Fnet = Applied Force − Frictional Force = 20 N − 5 N = 15 N.
Now, work done is: W = 15 N × 10 m × 1 = 150 J.

The work done decreases because part of the applied force is used to overcome friction, reducing the effective force contributing to displacement.

Key Concept: Work depends on the net force in the direction of displacement, not just the applied force.

Question 16:
A toy car of mass 0.5 kg is moving at a speed of 4 m/s. It collides with a spring fixed to a wall and compresses it by 0.1 m before coming to rest.

(i) Calculate the kinetic energy of the car before collision.
(ii) Assuming all kinetic energy is converted into the spring's potential energy, find the spring constant (k).

Answer:

(i) Kinetic energy (KE) of the car is given by:
KE = ½ × mass × velocity²
Substituting values: KE = ½ × 0.5 kg × (4 m/s)² = ½ × 0.5 × 16 = 4 J.

(ii) According to the law of conservation of energy, the car's KE is entirely converted into the elastic potential energy (PE) of the spring:
PE = ½ × k × x², where x is compression.
Given PE = KE = 4 J and x = 0.1 m, we solve for k:
4 J = ½ × k × (0.1 m)²
k = (4 × 2) / (0.1)² = 8 / 0.01 = 800 N/m.

Key Concept: Energy transforms from one form to another (here, kinetic → potential), but the total energy remains conserved.

Question 17:
A student pushes a box of mass 5 kg with a force of 20 N over a distance of 10 m on a frictionless surface.
(i) Calculate the work done by the student.
(ii) If the same box is lifted vertically upwards to a height of 2 m, calculate the work done against gravity. (Take g = 10 m/s²)
Answer:

(i) Work done on a frictionless surface:
Given: Force (F) = 20 N, Displacement (s) = 10 m
Since the force and displacement are in the same direction, θ = 0°.
Work done (W) = F × s × cosθ = 20 × 10 × cos0° = 200 × 1 = 200 J.

(ii) Work done against gravity:
Given: Mass (m) = 5 kg, Height (h) = 2 m, g = 10 m/s²
Force required to lift the box = Weight = m × g = 5 × 10 = 50 N
Work done (W) = Force × Displacement = 50 × 2 = 100 J.

Note: Work done depends on the direction of force and displacement. In lifting, work is done against gravity, while on a frictionless surface, work is due to applied force.

Question 18:
A toy car of mass 0.5 kg is moving with a velocity of 4 m/s.
(i) Calculate its kinetic energy.
(ii) If its velocity is doubled, what will be the new kinetic energy? How does it compare to the initial kinetic energy?
Answer:

(i) Initial Kinetic Energy:
Given: Mass (m) = 0.5 kg, Velocity (v) = 4 m/s
Kinetic Energy (KE) = ½ × m × v² = ½ × 0.5 × (4)² = 0.25 × 16 = 4 J.

(ii) New Kinetic Energy when velocity is doubled:
New Velocity (v') = 2 × 4 = 8 m/s
New KE = ½ × 0.5 × (8)² = 0.25 × 64 = 16 J.

Comparison: When velocity is doubled, kinetic energy becomes four times the initial value (since KE ∝ v²). This shows the quadratic dependence of kinetic energy on velocity.

Question 19:
A student pushes a box of mass 10 kg horizontally with a force of 50 N over a distance of 5 m on a frictionless surface. Calculate the work done by the student. Also, explain how the work-energy theorem applies in this scenario.
Answer:

The work done (W) is calculated using the formula: W = Force × Displacement × cosθ.
Here, the force (F) is 50 N, displacement (s) is 5 m, and θ = 0° (since force and displacement are in the same direction).
Thus, W = 50 × 5 × cos0° = 250 × 1 = 250 J.

The work-energy theorem states that the work done on an object equals the change in its kinetic energy.
Since the surface is frictionless, all the work done (250 J) converts into the box's kinetic energy, increasing its speed.

Question 20:
A ball of mass 0.5 kg is dropped from a height of 10 m. Calculate its potential energy at the initial position and its kinetic energy just before hitting the ground. Assume g = 10 m/s². Also, state the energy transformation taking place during the fall.
Answer:

The potential energy (PE) at height h is given by PE = mgh.
Here, m = 0.5 kg, g = 10 m/s², and h = 10 m.
Thus, PE = 0.5 × 10 × 10 = 50 J.

According to the law of conservation of energy, the kinetic energy (KE) just before hitting the ground equals the initial PE.
So, KE = 50 J.

During the fall, the ball's potential energy gradually converts into kinetic energy, maintaining the total mechanical energy constant (ignoring air resistance).

Question 21:
A student pushes a box of mass 5 kg with a force of 20 N over a distance of 10 m on a frictionless surface. Calculate the work done by the student. Also, explain how the work-energy theorem applies in this scenario.
Answer:

To calculate the work done, we use the formula: Work (W) = Force (F) × Displacement (s) × cosθ, where θ is the angle between force and displacement.


Given: F = 20 N, s = 10 m, and θ = 0° (since force and displacement are in the same direction).

Work done: W = 20 N × 10 m × cos0° = 200 J (since cos0° = 1).

According to the work-energy theorem, the work done on an object equals the change in its kinetic energy. Here, the box gains kinetic energy as it accelerates due to the applied force. Since the surface is frictionless, all the work done (200 J) is converted into the box's kinetic energy.

Question 22:
A cyclist pedals uphill, applying a constant force of 150 N to cover a vertical height of 6 m. The total mass of the cyclist and the bicycle is 80 kg. Determine the work done against gravity and explain the role of potential energy in this situation.
Answer:

Work done against gravity is calculated using: W = mgh, where m is mass, g is acceleration due to gravity (9.8 m/s²), and h is height.


Given: m = 80 kg, h = 6 m.

Work done: W = 80 kg × 9.8 m/s² × 6 m = 4704 J.

The cyclist does work to increase the gravitational potential energy of the system (cyclist + bicycle). The potential energy at the top is 4704 J, stored due to the elevated position. This energy can later be converted back to kinetic energy while descending.

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