Measures of Central Tendency (Mean, Median, Mode) – CBSE NCERT Study Resources

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11th - Economics

Measures of Central Tendency (Mean, Median, Mode)

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Overview

This chapter introduces the concept of Measures of Central Tendency, which are statistical tools used to identify the central or typical value in a dataset. The three primary measures discussed are Mean, Median, and Mode, each serving different purposes in data analysis. Understanding these measures is essential for interpreting economic data and making informed decisions.

Mean

The Mean, also known as the arithmetic average, is calculated by summing all the values in a dataset and dividing by the number of observations. It is sensitive to extreme values (outliers) and is widely used in economic analysis for its mathematical properties.

Median

The Median is the middle value in an ordered dataset. If the dataset has an even number of observations, the median is the average of the two middle values. Unlike the mean, the median is not affected by extreme values, making it useful for skewed distributions.

Mode

The Mode is the value that appears most frequently in a dataset. A dataset can have one mode (unimodal), more than one mode (bimodal or multimodal), or no mode at all. The mode is particularly useful for categorical data where numerical averages are not meaningful.

Comparison of Mean, Median, and Mode

Each measure of central tendency has its advantages and limitations. The mean is precise but affected by outliers, the median is robust but less efficient for further calculations, and the mode is simple but may not always exist. The choice of measure depends on the nature of the data and the purpose of analysis.

Applications in Economics

In economics, these measures help summarize large datasets, such as income distribution, price levels, or production outputs. For example, the mean income provides an average, while the median income highlights the middle point, and the mode identifies the most common income level.

All Question Types with Solutions – CBSE Exam Pattern

Explore a complete set of CBSE-style questions with detailed solutions, categorized by marks and question types. Ideal for exam preparation, revision and practice.

Very Short Answer (1 Mark) – with Solutions (CBSE Pattern)

These are 1-mark questions requiring direct, concise answers. Ideal for quick recall and concept clarity.

Question 1:
Define Mean in statistics.
Answer:
Definition: Sum of all values divided by number of observations.
Question 2:
What is the Median of 5, 8, 12, 17, 20?
Answer:
Median is 12 (middle value in ordered data).
Question 3:
Identify the Mode in 3, 5, 5, 7, 9.
Answer:
Mode is 5 (most frequent value).
Question 4:
When is Median preferred over Mean?
Answer:
When data has extreme values or is skewed.
Question 5:
Calculate Mean of 10, 20, 30, 40.
Answer:
Mean = 25 (sum=100, n=4).
Question 6:
Which measure is affected by outliers?
Answer:
Mean is affected by outliers.
Question 7:
Find Mode of 2, 4, 4, 4, 6, 8.
Answer:
Mode is 4 (highest frequency).
Question 8:
What is the Median of an even-sized dataset?
Answer:
Average of two middle values in ordered data.
Question 9:
Give an example where Mode is zero.
Answer:
Dataset: 0, 0, 1, 2, 3 (Mode=0).
Question 10:
Why is Mean called a rigid measure?
Answer:
It uses all data points in calculation.
Question 11:
Which measure works for qualitative data?
Answer:
Mode (e.g., most common color).
Question 12:
Calculate Median of 7, 9, 11, 13, 15.
Answer:
Median is 11 (middle position).
Question 13:
When does a dataset have no Mode?
Answer:
When all values occur equally (e.g., 1,2,3,4).
Question 14:
How does Mean handle open-ended classes?
Answer:
It cannot be calculated without limits.
Question 15:
What is the formula to calculate Median for an odd number of observations?
Answer:

For an odd number of observations, Median is the middle value when data is arranged in ascending or descending order.
Formula: Median = Value at (n+1)/2th position.

Question 16:
How is Mode determined in a dataset?
Answer:

Mode is the value that appears most frequently in a dataset. A dataset may have one mode, multiple modes, or no mode if all values are unique.

Question 17:
Why is Mean affected by extreme values?
Answer:

Mean includes all data points in its calculation, so extreme values (outliers) can significantly increase or decrease the average, making it less representative of the dataset.

Question 18:
When is Median a better measure of central tendency than Mean?
Answer:

Median is preferred when data is skewed or has outliers because it is not affected by extreme values, providing a better central value.

Question 19:
Give an example where Mode is the most appropriate measure of central tendency.
Answer:

Mode is best for categorical data, like finding the most common shoe size in a store or the favorite ice cream flavor in a survey.

Question 20:
Calculate the Mean of the numbers: 5, 8, 12, 15, 20.
Answer:

Sum = 5 + 8 + 12 + 15 + 20 = 60
Number of observations = 5
Mean = 60 / 5 = 12

Question 21:
Find the Median of the dataset: 7, 3, 9, 5, 11.
Answer:

Arrange in order: 3, 5, 7, 9, 11
Number of observations = 5 (odd)
Median = Value at (5+1)/2 = 3rd position = 7

Question 22:
Identify the Mode in the dataset: 4, 6, 4, 8, 6, 4, 9.
Answer:

Frequency: 4 appears 3 times, 6 appears 2 times, 8 and 9 appear once.
Mode = 4 (most frequent).

Question 23:
What is the relationship between Mean, Median, and Mode in a symmetrical distribution?
Answer:

In a perfectly symmetrical distribution, Mean, Median, and Mode are all equal and lie at the center of the dataset.

Question 24:
How does an outlier affect the Mean and Median differently?
Answer:

An outlier drastically changes the Mean due to its extreme value, while the Median remains relatively unaffected as it depends on the middle position.

Question 25:
Can a dataset have more than one Mode? Explain with an example.
Answer:

Yes, a dataset is bimodal or multimodal if multiple values have the same highest frequency.
Example: In 2, 3, 3, 4, 5, 5, both 3 and 5 are modes.

Very Short Answer (2 Marks) – with Solutions (CBSE Pattern)

These 2-mark questions test key concepts in a brief format. Answers are expected to be accurate and slightly descriptive.

Question 1:
What is the Median? How is it different from Mean?
Answer:

The Median is the middle value in a data set arranged in ascending or descending order.
Unlike Mean, it is not affected by extreme values.
For odd N: Middle value.
For even N: Average of two middle values.

Question 2:
Explain the term Mode with an example.
Answer:

The Mode is the value that appears most frequently in a data set.
Example: In {2, 3, 4, 4, 5}, the Mode is 4 as it occurs twice.

Question 3:
When is the Median a better measure of central tendency than the Mean?
Answer:

The Median is preferred when:

  • Data has extreme values (outliers).
  • The distribution is skewed.
  • Data is ordinal (rank-based).

Question 4:
Calculate the Mean of the data set: 10, 15, 20, 25, 30.
Answer:

Sum = 10 + 15 + 20 + 25 + 30 = 100.
Number of observations = 5.
Mean = 100 / 5 = 20.

Question 5:
Find the Median of the following data: 7, 12, 5, 9, 14.
Answer:

Arrange in order: 5, 7, 9, 12, 14.
Number of observations = 5 (odd).
Median = 9 (middle value).

Question 6:
Identify the Mode in the series: 3, 5, 7, 5, 2, 5, 8.
Answer:

Frequency of 3 = 1, 5 = 3, 7 = 1, 2 = 1, 8 = 1.
The Mode is 5 (highest frequency).

Question 7:
Why is the Mode useful in categorical data?
Answer:

The Mode identifies the most common category, making it ideal for non-numeric data (e.g., colors, brands).
Example: In {Red, Blue, Red, Green}, the Mode is Red.

Question 8:
What is a bimodal distribution? Give an example.
Answer:

A bimodal distribution has two modes (peaks).
Example: {1, 2, 2, 3, 4, 4, 4} has modes 2 and 4.

Question 9:
How does an outlier affect the Mean and Median?
Answer:

An outlier skews the Mean significantly but has minimal impact on the Median.
Example: In {1, 2, 3, 100}, Mean = 26.5 (affected), Median = 2.5 (stable).

Question 10:
Compare Mean, Median, and Mode in a symmetrical distribution.
Answer:

In a symmetrical distribution:

  • Mean = Median = Mode.
  • All three coincide at the center.
  • Example: Normal distribution.

Short Answer (3 Marks) – with Solutions (CBSE Pattern)

These 3-mark questions require brief explanations and help assess understanding and application of concepts.

Question 1:
Calculate the mean of the following data: 10, 15, 20, 25, 30. Show steps.
Answer:

Step 1: Sum all values → 10 + 15 + 20 + 25 + 30 = 100.
Step 2: Count the number of values (N) → 5.
Step 3: Apply mean formula → Mean = Σx / N = 100 / 5.
Result: Mean = 20.

Question 2:
Why is median a better measure of central tendency than mean for skewed data? Explain.
Answer:

Median is preferred for skewed data because:

  • It is not affected by extreme values (outliers), whereas mean gets distorted.
  • Example: In [3, 5, 7, 9, 100], mean = 24.8 (misleading), but median = 7 (accurate central value).
  • It better represents the typical value in asymmetrical distributions like income data.

Question 3:
Find the mode of the dataset: 4, 6, 6, 8, 8, 8, 10. What does it indicate?
Answer:

Step 1: Identify frequencies → 4 (1), 6 (2), 8 (3), 10 (1).
Step 2: Highest frequency is 3 for the value 8.
Result: Mode = 8.

Interpretation:

  • The number 8 occurs most frequently, indicating it is the most common observation.
  • Useful for categorical data analysis, like popular product sizes.

Question 4:
Explain the concept of weighted mean with a real-life application.
Answer:

Weighted mean assigns different weights to values based on their importance.
Formula: Weighted Mean = (Σw*x) / Σw, where w = weight, x = value.

Example: Student’s grade calculation:

  • Quizzes (weight 20%, score 80)
  • Exams (weight 50%, score 90)
  • Projects (weight 30%, score 85)

Calculation:
(0.2*80 + 0.5*90 + 0.3*85) / (0.2+0.5+0.3) = 86.5.

Application: Used in GPA, stock market indices, and economic indicators.

Question 5:
Define mean and explain its significance in statistical analysis.
Answer:

The mean is the average of a set of numbers, calculated by dividing the sum of all values by the number of values.
Formula: Mean = (Σx) / N, where Σx is the sum of all observations and N is the number of observations.

Significance:

  • It provides a central value representing the entire dataset.
  • Used in further statistical calculations like standard deviation.
  • Sensitive to extreme values (outliers), making it useful for identifying data skewness.

Question 6:
Differentiate between median and mode with suitable examples.
Answer:

Median is the middle value in an ordered dataset, while mode is the most frequently occurring value.

  • Example for Median: Dataset [5, 7, 9, 12, 15] → Median = 9 (middle value).
  • Example for Mode: Dataset [2, 4, 4, 6, 8] → Mode = 4 (repeats most).

Key difference:
  • Median is unaffected by outliers, whereas mode highlights data concentration.
  • Mode can be bimodal (two modes) or multimodal, but median is always singular.

Question 7:
Calculate the mean of the following data: 12, 15, 18, 21, 24.
Answer:

Step 1: Sum all values.
12 + 15 + 18 + 21 + 24 = 90.

Step 2: Divide by the number of values (5).
Mean = 90 ÷ 5 = 18.

Note: The mean represents the balanced center of the data.

Question 8:
Explain a situation where median is a better measure of central tendency than mean.
Answer:

The median is preferred when:

  • Data has extreme values (e.g., income distribution where a few high incomes skew the mean).
  • The dataset is ordinal (e.g., survey ratings like 1-5).

Example: House prices in a neighborhood with one luxury mansion. The median gives a realistic middle value, while the mean would be inflated.

Question 9:
Find the mode of the dataset: 4, 6, 6, 8, 8, 8, 10.
Answer:

Step 1: Identify the most frequent value.
Here, 8 occurs three times, while others occur less frequently.

Mode = 8.

Note: A dataset can have no mode (all values unique) or multiple modes (equal highest frequency).

Question 10:
How does an outlier affect the mean and median? Illustrate with an example.
Answer:

Outlier: An extreme value in the dataset.

Effect on Mean: Highly sensitive.
Example: 5, 10, 15, 20, 100. Mean increases from 12.5 to 30.

Effect on Median: Unaffected or slightly shifted.
Median remains 15 (original) vs. 17.5 (with outlier).

Conclusion: Median is robust for skewed data.

Long Answer (5 Marks) – with Solutions (CBSE Pattern)

These 5-mark questions are descriptive and require detailed, structured answers with proper explanation and examples.

Question 1:
Compare mean, median, and mode as measures of central tendency with real-world examples. Which is most suitable for skewed data and why?
Answer:
Theoretical Framework

We studied that mean is the arithmetic average, median is the middle value, and mode is the most frequent observation. Each has unique applications.

Evidence Analysis
  • Mean: Used in calculating average income (e.g., India’s per capita income: ₹1.72 lakh in 2023).
  • Median: Better for skewed data (e.g., wealth distribution where top 10% own 77% assets).
  • Mode: Useful for categorical data (e.g., most sold smartphone model).
Critical Evaluation

Median minimizes outlier impact, making it ideal for skewed datasets. Our textbook shows that GDP growth rates often use median to avoid extreme values distorting results.

Question 2:
Explain how weighted mean differs from simple mean. Provide two examples where weighted mean is indispensable.
Answer:
Theoretical Framework

The simple mean treats all values equally, while the weighted mean assigns importance (weights) to data points.

Evidence Analysis
  • Example 1: CBSE board exam scores use weighted mean (theory: 80%, practicals: 20%).
  • Example 2: Stock market indices like Nifty50 weight companies by market capitalization.
Critical Evaluation

Weighted mean reflects real-world priorities. Our textbook highlights its use in inflation calculations, where food prices have higher weights than luxury items.

Question 3:
Analyze the limitations of mode as a measure of central tendency. Support your answer with economic data examples.
Answer:
Theoretical Framework

Mode identifies the most frequent value but fails in continuous datasets or multimodal distributions.

Evidence Analysis
  • Limitation 1: No mode exists if all values are unique (e.g., individual CEO salaries).
  • Limitation 2: Multiple modes confuse interpretation (e.g., bimodal demand for ACs in summer/winter).
Critical Evaluation

As per NCERT, mode is ineffective for metric data like GDP growth. However, it excels in retail (e.g., identifying peak sales periods).

Question 4:
Discuss the role of median in economic policymaking with reference to income inequality. Use 2023 World Inequality Lab data.
Answer:
Theoretical Framework

Median divides the population into two equal halves, making it robust against extreme values.

Evidence Analysis
  • 2023 data shows India’s median income (₹1.25 lakh) is 40% lower than mean (₹2.1 lakh), revealing inequality.
  • Policies like progressive taxation rely on median to target the "middle class".
Critical Evaluation

Median-based analysis exposes how top 1% distortions affect averages. Our textbook cites its use in Minimum Support Price (MSP) calculations for farmers.

Question 5:
How do outliers affect the mean and median? Illustrate with hypothetical data on corporate profits.
Answer:
Theoretical Framework

Outliers disproportionately influence mean but leave median unaffected due to positional nature.

Evidence Analysis
CompanyProfit (₹Cr)
A50
B55
C1000
  • Mean: ₹368Cr (distorted by C).
  • Median: ₹55Cr (accurate middle value).
Critical Evaluation

As per NCERT, sectors like tech (with occasional mega-profits) must use median to avoid misrepresentation.

Question 6:
Explain the concept of Mean as a measure of central tendency. Discuss its merits and demerits with suitable examples.
Answer:

The Mean, also known as the arithmetic average, is a measure of central tendency calculated by summing all the values in a dataset and dividing by the number of observations. It is represented as:

Mean (x̄) = Σx / N

where Σx is the sum of all values and N is the number of observations.

Merits of Mean:

  • It considers all data points, making it a comprehensive measure.
  • It is easy to understand and calculate.
  • It is useful for further statistical analysis like standard deviation.
Demerits of Mean:
  • It is affected by extreme values (outliers), which can distort the result.
  • It cannot be calculated for open-ended class intervals.

For example, if the marks of 5 students are 10, 20, 30, 40, and 50, the mean is (10+20+30+40+50)/5 = 30. However, if an outlier like 100 is added, the mean becomes 41.67, showing its sensitivity to extreme values.

Question 7:
Compare Median and Mode as measures of central tendency. Highlight their suitability in different scenarios with examples.
Answer:

The Median is the middle value in an ordered dataset, while the Mode is the most frequently occurring value. Both are measures of central tendency but serve different purposes.

Comparison:

  • Calculation: Median requires data to be arranged in ascending/descending order, whereas Mode identifies the highest frequency.
  • Effect of Outliers: Median is unaffected by extreme values, but Mode depends on frequency, not magnitude.
  • Use Cases: Median is ideal for skewed distributions (e.g., income data), while Mode is best for categorical data (e.g., shoe sizes).

Examples:
1. For the dataset [5, 7, 7, 9, 11], the Median is 7, and the Mode is 7.
2. In a survey of favorite colors where Blue appears most often, Mode is the best measure.
3. For income data [20K, 30K, 35K, 40K, 200K], the Median (35K) better represents central tendency than the Mean due to the outlier.

Thus, the choice between Median and Mode depends on the nature of the data and the presence of outliers or categorical variables.

Question 8:
Describe a real-life situation where Mode is a more appropriate measure of central tendency than Mean or Median. Justify your answer.
Answer:

The Mode is most suitable when dealing with categorical or discrete data where frequency matters more than numerical values. For instance, a shoe manufacturer analyzing the most popular shoe size sold would use the Mode.

Justification:

  • Shoe sizes (e.g., 6, 7, 8) are distinct categories, and the Mode identifies the size with the highest demand.
  • Mean or Median could give fractional values (e.g., 7.2), which are meaningless in this context.

Example: If sales data shows sizes [6, 6, 7, 7, 7, 8, 8], the Mode is 7, indicating the most preferred size. Using Mean (6.85) or Median (7) would not provide actionable insights for inventory planning.

Question 9:
Define Mean, Median, and Mode as measures of central tendency. Explain with suitable examples how each is calculated and highlight one advantage and limitation of each.
Answer:

Mean, Median, and Mode are the three primary measures of central tendency used to summarize data.

Mean is the average of all observations. It is calculated by summing all values and dividing by the number of observations.
Example: For data set 5, 10, 15, Mean = (5 + 10 + 15) / 3 = 10.
Advantage: Uses all data points.
Limitation: Affected by extreme values.

Median is the middle value when data is arranged in ascending order.
Example: For 7, 3, 5, arrange as 3, 5, 7. Median = 5.
Advantage: Not affected by outliers.
Limitation: Ignores magnitude of other values.

Mode is the most frequently occurring value.
Example: In 2, 4, 4, 6, Mode = 4.
Advantage: Useful for categorical data.
Limitation: May not exist or be unique.

Question 10:
Compare and contrast Mean, Median, and Mode with respect to their applicability in different types of data distributions. Provide real-life scenarios where each measure is most appropriate.
Answer:

Mean, Median, and Mode serve different purposes based on data distribution.

  • Mean is best for symmetric distributions without outliers, e.g., calculating average student marks in a class.
  • Median is ideal for skewed data, e.g., income distribution where a few high earners skew the mean.
  • Mode is used for categorical data, e.g., identifying the most common shoe size in a store.

In real-life:
Mean: Useful for test scores where data is balanced.
Median: Preferred for housing prices due to outliers.
Mode: Best for survey responses like favorite color.

Question 11:
Explain the step-by-step process of calculating the Median for grouped data using the formula: Median = L + [(N/2 - CF) / f] × h. Illustrate with an example.
Answer:

To calculate Median for grouped data:

  1. Identify the median class where N/2 falls.
  2. Note the lower limit (L) of this class.
  3. Find the cumulative frequency (CF) before the median class.
  4. Determine the frequency (f) of the median class.
  5. Note the class width (h).

Example: For the data:
Class: 10-20, 20-30, 30-40
Frequency: 5, 12, 8
Cumulative Frequency: 5, 17, 25

Steps:
1. N = 25 → N/2 = 12.5 → Median class = 20-30.
2. L = 20.
3. CF = 5.
4. f = 12.
5. h = 10.
Median = 20 + [(12.5 - 5)/12] × 10 = 20 + 6.25 = 26.25.

Question 12:
Compare and contrast Median and Mode as measures of central tendency. Provide real-life scenarios where each would be more appropriate to use.
Answer:

The Median is the middle value in an ordered dataset, while the Mode is the most frequently occurring value. Both are measures of central tendency but serve different purposes.

Comparison:

  • Median is unaffected by extreme values, making it suitable for skewed distributions. Mode is useful for categorical data.
  • Median requires data to be arranged in order, while Mode does not.
  • Mode can have multiple values (bimodal or multimodal), whereas Median is always a single value.

Real-life Scenarios:

  • Median is ideal for income data, as extreme values (very high or low incomes) can skew the mean. For example, median household income gives a better representation of a typical household.
  • Mode is useful in retail to identify the most popular product size or color. For instance, a shoe store would use mode to stock the most frequently sold shoe size.

Question 13:
Explain the concept of Mean, Median, and Mode as measures of central tendency. Discuss their significance, limitations, and provide one real-life example where each is most appropriately used.
Answer:

The measures of central tendency are statistical tools that help summarize a dataset by identifying a central point around which the data clusters. The three primary measures are:

  • Mean: The arithmetic average of all data points, calculated by summing all values and dividing by the number of observations.
    Formula: Mean = (Σx) / N
    Significance: Provides a balanced representation of the dataset.
    Limitation: Highly affected by extreme values (outliers).
    Example: Calculating average income of a country to assess economic performance.
  • Median: The middle value when data is arranged in ascending or descending order.
    Significance: Less affected by outliers, ideal for skewed distributions.
    Limitation: Does not consider all data points.
    Example: Determining the median household income to understand typical earnings, avoiding distortion by extremely high or low incomes.
  • Mode: The most frequently occurring value in a dataset.
    Significance: Useful for categorical data and identifying popular choices.
    Limitation: May not exist or be unique in some datasets.
    Example: Identifying the most common shoe size in a store to optimize inventory.

Each measure has unique applications depending on the data characteristics. While the mean is precise for normally distributed data, the median is robust for skewed data, and the mode is ideal for nominal data analysis.

Question 14:
Explain the concept of Mean, Median, and Mode as measures of central tendency. Discuss their significance, limitations, and provide an example where each measure is most appropriate.
Answer:

The measures of central tendency are statistical tools used to identify the central or typical value in a dataset. The three primary measures are Mean, Median, and Mode.

Mean is the arithmetic average of all data points. It is calculated by summing all values and dividing by the number of observations.
Formula: Mean = (Σx) / N
Example: Calculating average income of a household.

Median is the middle value when data is arranged in ascending or descending order. It is less affected by extreme values (outliers).
Example: Finding the median price of houses in a locality to avoid skewness from luxury homes.

Mode is the most frequently occurring value in a dataset. It is useful for categorical data.
Example: Identifying the most common shoe size in a store.

Significance:

  • Mean provides a precise average.
  • Median offers robustness against outliers.
  • Mode highlights the most common value.

Limitations:

  • Mean is skewed by extreme values.
  • Median ignores the magnitude of other values.
  • Mode may not exist or be unique in some datasets.

Appropriate Use Cases:

  • Mean: When data is normally distributed (e.g., exam scores).
  • Median: For skewed data (e.g., income distribution).
  • Mode: For categorical data (e.g., favorite color).

Question 15:
Explain the concept of Mean, Median, and Mode as measures of central tendency with suitable examples. Discuss the advantages and limitations of each measure.
Answer:

Mean, Median, and Mode are the three primary measures of central tendency used to summarize data sets. Each provides a different perspective on the central value of the data.

Mean (Arithmetic Average): The mean is calculated by summing all the values in a data set and dividing by the number of values. For example, if the marks of 5 students are 10, 20, 30, 40, and 50, the mean is (10+20+30+40+50)/5 = 30.
Advantages: It uses all data points and is suitable for further statistical analysis.
Limitations: It is affected by extreme values (outliers), making it less reliable for skewed distributions.

Median (Middle Value): The median is the middle value when data is arranged in ascending or descending order. For an odd number of observations, it is the central value. For an even number, it is the average of the two middle values. Example: For the data set 12, 15, 20, 22, 25, the median is 20.
Advantages: It is not influenced by outliers and is ideal for skewed distributions.
Limitations: It does not consider all data points and is less useful for further mathematical operations.

Mode (Most Frequent Value): The mode is the value that appears most frequently in a data set. Example: In the data set 5, 8, 8, 10, 12, the mode is 8.
Advantages: It is easy to identify and useful for categorical data.
Limitations: A data set may have no mode (all values are unique) or multiple modes, reducing its reliability.

In summary, the choice of measure depends on the data type and distribution. The mean is best for symmetric data, the median for skewed data, and the mode for nominal data.

Case-based Questions (4 Marks) – with Solutions (CBSE Pattern)

These 4-mark case-based questions assess analytical skills through real-life scenarios. Answers must be based on the case study provided.

Question 1:
A survey recorded the monthly incomes (in ₹) of 10 workers: 15,000, 18,000, 20,000, 22,000, 25,000, 25,000, 30,000, 35,000, 40,000, 1,00,000. Analyze the mean, median, and mode. Which measure best represents the data? Justify.
Answer:
Case Deconstruction

The data has an outlier (₹1,00,000). Mean (₹31,000) is skewed, while median (₹25,000) and mode (₹25,000) are unaffected.

Theoretical Application
  • Mean: Distorted by extreme values.
  • Median: Robust for skewed distributions.
Critical Evaluation

Median is ideal here, as it reflects typical earnings without outlier influence. Example: GDP per capita often uses median for similar reasons.

Question 2:
The ages of participants in a marathon are: 22, 25, 26, 26, 28, 30, 32, 35, 40. Calculate all three measures of central tendency. Why might organizers prefer the mode?
Answer:
Case Deconstruction

Mean = 29.3, median = 28, mode = 26. Data is nearly symmetric.

Theoretical Application
  • Mode shows most frequent age group (26).
  • Organizers target largest demographic for sponsorships.
Critical Evaluation

Example: Retailers use mode for stock planning. Unlike mean, it ignores extreme values like 40-year-olds.

Question 3:
A class has test scores: 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. Compare mean and median. If the top score rises to 120, how does each measure change?
Answer:
Case Deconstruction

Original mean = 77.5, median = 77.5. After change: mean = 82 (+4.5), median remains 77.5.

Theoretical Application
  • Mean is sensitive to outliers.
  • Median resists changes in extreme values.
Critical Evaluation

Example: Inflation calculations often exclude volatile items (like median CPI) for stability.

Question 4:
A bakery’s daily sales (in ₹): 500, 600, 700, 700, 800, 900, 1000. The owner reports only the mean (₹742.86) to investors. Critique this choice.
Answer:
Case Deconstruction

Data is unimodal (mode = 700) and symmetric. Mean and median (700) are close.

Theoretical Application
  • Mean inflates performance by including ₹1000.
  • Median would show typical sales better.
Critical Evaluation

Example: Companies may highlight mean revenue during growth phases, masking variability.

Question 5:
A village’s land holdings (acres): 1, 1, 2, 2, 3, 4, 10, 20. Calculate measures. Discuss inequality using results.
Answer:
Case Deconstruction

Mean = 5.375, median = 2.5, mode = 1 & 2. Huge disparity (20 vs 1).

Theoretical Application
  • Median reveals 50% own ≤2.5 acres.
  • Mean distorted by large holdings.
Critical Evaluation

Example: Gini coefficient uses such comparisons. Policies should address median farmers, not averages.

Question 6:
A survey recorded the monthly income (in ₹) of 10 families in a locality: 15,000, 18,000, 22,000, 25,000, 30,000, 35,000, 40,000, 45,000, 50,000, 1,00,000. Analyze the mean, median, and mode of this data. Which measure best represents the 'typical' income here? Justify.
Answer:
Case Deconstruction

The data includes incomes ranging from ₹15,000 to ₹1,00,000, with one extreme value (₹1,00,000).

Theoretical Application
  • Mean: ₹38,000 (affected by outlier)
  • Median: ₹32,500 (middle value)
  • Mode: No mode (all unique)
Critical Evaluation

Median is most reliable as it isn't skewed by the outlier. Example: Textbook shows median is preferred for unequal distributions like wealth data.

Question 7:
The average marks of a class of 30 students is 72. Two new students join with marks 48 and 84. Recalculate the mean and explain how it compares to the median if the original data was symmetrical.
Answer:
Case Deconstruction

Original total marks = 72 × 30 = 2,160. New total = 2,160 + 48 + 84 = 2,292.

Theoretical Application
  • New mean: 2,292/32 ≈ 71.63 (slightly decreased)
  • Median: Unchanged if original data was symmetrical (middle values balanced)
Critical Evaluation

Mean is sensitive to new values, while median resists minor changes. Example: Our textbook highlights this in height datasets.

Question 8:
A shoe store sold pairs (size-wise) as: 5, 6, 6, 7, 7, 7, 8, 8, 9. Identify the mode and discuss its business utility. Contrast it with mean size if another size-12 pair is added.
Answer:
Case Deconstruction

Size 7 appears most frequently (3 times). Adding size-12 affects mean but not mode.

Theoretical Application
  • Mode: 7 (most demanded size)
  • New mean: Increases from 7.11 to ≈7.3
Critical Evaluation

Mode helps inventory planning (e.g., stocking size-7). Mean becomes less practical with outliers. Example: Retailers use mode for seasonal demand.

Question 9:
The table shows GDP growth rates (%) of 5 years: 4.5, 5.1, 5.1, 6.0, 7.2. Compute median and mean. Argue which measure policymakers might prefer and why.
Answer:
Case Deconstruction
YearGDP %
14.5
2-35.1
4-56.0,7.2
Theoretical Application
  • Median: 5.1% (middle value)
  • Mean: 5.58%
Critical Evaluation

Policymakers may prefer median to ignore extremes (e.g., 7.2% outlier). Example: RBI uses median inflation for stability.

Question 10:
A survey recorded the monthly incomes (in ₹) of 10 families in a locality: 15,000, 18,000, 22,000, 25,000, 30,000, 35,000, 40,000, 45,000, 50,000, 1,00,000. Analyze the mean, median, and mode of this data. Which measure best represents the 'typical' income here? Justify.
Answer:
Case Deconstruction

The data includes incomes ranging from ₹15,000 to ₹1,00,000, with one outlier (₹1,00,000).

Theoretical Application
  • Mean: ₹38,000 (sum of incomes ÷ 10).
  • Median: ₹32,500 (average of 5th and 6th values).
  • Mode: No mode (all values are unique).
Critical Evaluation

The median is the best measure as the mean is skewed by the outlier. Our textbook shows that medians resist extreme values in asymmetric distributions.

Question 11:
The ages (in years) of participants in a workshop are: 18, 20, 22, 22, 25, 25, 25, 30, 32, 40. Compare the central tendencies and explain why the mode might be significant here.
Answer:
Case Deconstruction

The dataset has repeated values (e.g., 22, 25) and a range of 18–40 years.

Theoretical Application
  • Mean: 25.9 years.
  • Median: 25 years.
  • Mode: 25 years (most frequent).
Critical Evaluation

The mode highlights the most common age group (25), useful for targeting workshops. We studied how modes identify peaks in categorical data, like age brackets.

Question 12:
A class scored the following marks (out of 50) in a test: 12, 15, 18, 20, 20, 22, 23, 25, 28, 30, 35. Calculate the mean and median. If two students scored 0, how would these measures change?
Answer:
Case Deconstruction

Original data has 11 values. Adding two zeros alters the distribution.

Theoretical Application
  • Original Mean: 22.7; New Mean: 18.5 (sum ÷ 13).
  • Original Median: 22; New Median: 20 (7th value).
Critical Evaluation

The mean drops sharply due to low outliers, while the median is less affected. This aligns with our lesson on robustness.

Question 13:
A bakery recorded daily sales (in ₹) for a week: 1,200, 1,500, 1,500, 1,800, 2,000, 2,500, 3,000. The owner claims the 'average' sale is ₹1,500. Is this correct? Critically evaluate using measures of central tendency.
Answer:
Case Deconstruction

The owner likely refers to the mode (₹1,500), but other measures exist.

Theoretical Application
  • Mean: ₹1,928 (sum ÷ 7).
  • Median: ₹1,800 (4th value).
  • Mode: ₹1,500.
Critical Evaluation

The owner’s claim is partially correct. While ₹1,500 is the mode, the mean and median better reflect overall performance, as taught in class.

Question 14:
A survey was conducted in a locality to find the average number of family members per household. The data collected is as follows: 3, 4, 2, 5, 3, 6, 4, 3, 5, 4. Calculate the mean, median, and mode of the data and explain which measure best represents the central tendency in this case.
Answer:

To calculate the mean, sum all the values and divide by the number of observations:
Sum = 3 + 4 + 2 + 5 + 3 + 6 + 4 + 3 + 5 + 4 = 39
Number of observations = 10
Mean = 39 / 10 = 3.9

To find the median, first arrange the data in ascending order: 2, 3, 3, 3, 4, 4, 4, 5, 5, 6
Since there are 10 observations (even number), the median is the average of the 5th and 6th values:
Median = (4 + 4) / 2 = 4

The mode is the most frequently occurring value. Here, both 3 and 4 appear three times, making the data bimodal (modes = 3 and 4).

The median (4) best represents the central tendency because the data has no extreme outliers and the mean is slightly skewed by the value 6. The mode is less reliable as it has two values.

Question 15:
In a school, the monthly pocket money (in ₹) of 8 students is recorded as: 500, 600, 700, 500, 800, 500, 600, 900. Determine the mean, median, and mode of the data. If a new student with pocket money of ₹1500 joins, how does it affect the measures of central tendency?
Answer:

Original data: 500, 600, 700, 500, 800, 500, 600, 900
Mean = (500 + 600 + 700 + 500 + 800 + 500 + 600 + 900) / 8 = 5100 / 8 = ₹637.5

Arranged data for median: 500, 500, 500, 600, 600, 700, 800, 900
Number of observations = 8 (even)
Median = (600 + 600) / 2 = ₹600

Mode = ₹500 (appears most frequently).

After adding ₹1500:
New mean = (5100 + 1500) / 9 = 6600 / 9 ≈ ₹733.33 (increases significantly due to the high value).
New median (arranged data): 500, 500, 500, 600, 600, 700, 800, 900, 1500
Median = ₹600 (unchanged as it is the middle value).
Mode remains ₹500 (unaffected).

The mean is highly sensitive to extreme values, while the median and mode are more robust in such cases.

Question 16:
A survey was conducted in a class of 30 students to find their monthly pocket money (in ₹). The data collected is as follows: 500, 600, 700, 800, 900, 1000, 1100, 1200, 1300, 1400, 1500, 1600, 1700, 1800, 1900, 2000, 2100, 2200, 2300, 2400, 2500, 2600, 2700, 2800, 2900, 3000, 3100, 3200, 3300, 3400. Calculate the mean, median, and mode of the data and explain which measure of central tendency best represents the data and why.
Answer:

To calculate the mean, we sum all the values and divide by the number of observations:
Sum = 500 + 600 + 700 + ... + 3400 = ₹58,500
Mean = Sum / Number of students = ₹58,500 / 30 = ₹1,950

To find the median, we arrange the data in ascending order (already given) and find the middle value. Since there are 30 observations (even number), the median is the average of the 15th and 16th values:
15th value = ₹1,900
16th value = ₹2,000
Median = (₹1,900 + ₹2,000) / 2 = ₹1,950

The mode is the value that appears most frequently. In this dataset, all values are unique, so there is no mode.

The mean and median both give ₹1,950, which is a good representation of the central tendency. Since the data is uniformly distributed without outliers, either measure is appropriate. However, the median is often preferred in skewed distributions.

Question 17:
In a factory, the daily wages (in ₹) of 10 workers are: 200, 220, 230, 240, 250, 260, 270, 280, 290, 3000. Calculate the mean and median of the wages. Identify the outlier and explain how it affects the measures of central tendency.
Answer:

To calculate the mean, sum all wages and divide by the number of workers:
Sum = 200 + 220 + 230 + ... + 3000 = ₹5,240
Mean = ₹5,240 / 10 = ₹524

For the median, arrange the data in ascending order (already given) and find the middle value. Since there are 10 observations (even number), the median is the average of the 5th and 6th values:
5th value = ₹250
6th value = ₹260
Median = (₹250 + ₹260) / 2 = ₹255

The outlier in this dataset is ₹3,000, which is significantly higher than the other wages. This outlier skews the mean upward (₹524), making it unrepresentative of most workers' wages. The median (₹255) is less affected by the outlier and better represents the central tendency in this case.

This example highlights the importance of choosing the appropriate measure of central tendency when outliers are present.

Question 18:
A survey was conducted in a locality to find the average number of family members per household. The data collected is as follows: 3, 4, 2, 5, 3, 6, 4, 3, 2, 5. Calculate the mean, median, and mode of the data and explain which measure of central tendency best represents this dataset.
Answer:

To calculate the mean, sum all the values and divide by the number of observations:
Sum = 3 + 4 + 2 + 5 + 3 + 6 + 4 + 3 + 2 + 5 = 37
Number of observations = 10
Mean = 37 / 10 = 3.7

To find the median, first arrange the data in ascending order: 2, 2, 3, 3, 3, 4, 4, 5, 5, 6
Since there are 10 observations (even number), the median is the average of the 5th and 6th values:
(3 + 4) / 2 = 3.5

The mode is the most frequently occurring value. Here, 3 appears most often (3 times).

The mean (3.7) is slightly higher due to the outlier (6), while the median (3.5) and mode (3) are closer to most data points. The median is often the best measure for skewed data as it is less affected by outliers.

Question 19:
In a class of 30 students, the following marks were obtained in a test (out of 50): 25, 30, 35, 40, 45, 20, 25, 30, 35, 40, 45, 20, 25, 30, 35, 40, 45, 20, 25, 30, 35, 40, 45, 20, 25, 30, 35, 40, 45, 50. Determine the mean, median, and mode of the marks and discuss which measure is most appropriate here.
Answer:

To calculate the mean, sum all the marks and divide by the number of students:
Sum = (25×5) + (30×5) + (35×5) + (40×5) + (45×5) + 20×4 + 50 = 125 + 150 + 175 + 200 + 225 + 80 + 50 = 1005
Number of students = 30
Mean = 1005 / 30 = 33.5

For the median, arrange the marks in ascending order: 20, 20, 20, 20, 25, 25, 25, 25, 25, 30, 30, 30, 30, 30, 35, 35, 35, 35, 35, 40, 40, 40, 40, 40, 45, 45, 45, 45, 45, 50
Since there are 30 observations (even number), the median is the average of the 15th and 16th values:
(35 + 35) / 2 = 35

The mode is the most frequent mark. Here, 20, 25, 30, 35, 40, and 45 each appear 5 times, making the data multimodal.

The mean (33.5) and median (35) are close, suggesting a symmetric distribution. However, the absence of a single mode makes the mean or median more reliable. The median is preferable as it is unaffected by the extreme value (50).

Question 20:
A survey was conducted in a locality to find the average number of family members per household. The data collected is as follows: 3, 4, 2, 5, 3, 6, 4, 3, 2, 4. Calculate the mean, median, and mode of the data and explain which measure of central tendency best represents this dataset.
Answer:

To calculate the mean, sum all the values and divide by the number of observations:
Sum = 3 + 4 + 2 + 5 + 3 + 6 + 4 + 3 + 2 + 4 = 36
Number of observations = 10
Mean = 36 / 10 = 3.6

To find the median, first arrange the data in ascending order: 2, 2, 3, 3, 3, 4, 4, 4, 5, 6
Since there are 10 observations (even number), the median is the average of the 5th and 6th values:
Median = (3 + 4) / 2 = 3.5

The mode is the most frequently occurring value. Here, both 3 and 4 appear three times, making the dataset bimodal with modes 3 and 4.

The mean (3.6) is slightly higher due to the outlier (6), while the median (3.5) balances the data better. The mode shows the most common family sizes. For this dataset, the median is the best measure as it is less affected by outliers.

Question 21:
In a school, the monthly pocket money (in ₹) received by 12 students is: 500, 600, 700, 500, 800, 600, 500, 900, 600, 700, 500, 1000. Determine the mean, median, and mode of the data. Which measure would a student advocate for if they wanted to highlight the 'typical' pocket money? Justify your answer.
Answer:

To calculate the mean, sum all values and divide by the number of observations:
Sum = 500 + 600 + 700 + 500 + 800 + 600 + 500 + 900 + 600 + 700 + 500 + 1000 = 7900
Number of observations = 12
Mean = 7900 / 12 ≈ 658.33

For the median, arrange the data in ascending order: 500, 500, 500, 500, 600, 600, 600, 700, 700, 800, 900, 1000
Since there are 12 observations (even number), the median is the average of the 6th and 7th values:
Median = (600 + 600) / 2 = 600

The mode is the most frequent value, which is 500 (appearing 4 times).

A student advocating for the 'typical' pocket money would likely choose the mode (₹500) because it represents the amount received by the majority. The mean is skewed higher by outliers (₹900, ₹1000), and the median, while balanced, does not reflect the most common value.

Question 22:
A survey was conducted in a locality to find the average monthly income of 10 families. The data collected (in ₹) is: 15,000, 20,000, 25,000, 18,000, 30,000, 22,000, 17,000, 28,000, 19,000, 21,000. Calculate the mean, median, and mode of the data. Which measure of central tendency best represents the data and why?
Answer:

To calculate the mean, sum all the values and divide by the number of families (10):


Sum = 15,000 + 20,000 + 25,000 + 18,000 + 30,000 + 22,000 + 17,000 + 28,000 + 19,000 + 21,000 = ₹2,15,000
Mean = 2,15,000 / 10 = ₹21,500

To find the median, arrange the data in ascending order:


15,000, 17,000, 18,000, 19,000, 20,000, 21,000, 22,000, 25,000, 28,000, 30,000
Since there are 10 values (even), the median is the average of the 5th and 6th values:
(20,000 + 21,000) / 2 = ₹20,500

The mode is the most frequently occurring value. Here, all values are unique, so there is no mode.


The median (₹20,500) best represents the data because it is less affected by extreme values (like ₹30,000) compared to the mean. It gives a clearer picture of the typical income in the locality.

Question 23:
In a school, the heights (in cm) of 12 students in a class are recorded as: 150, 152, 148, 149, 155, 153, 151, 150, 154, 152, 150, 156. Identify the mode and explain its significance in this context. Also, calculate the mean and median heights.
Answer:

To find the mode, identify the most frequently occurring value in the data:


150 appears 3 times, 152 appears 2 times, and others appear once.
Mode = 150 cm

The mode signifies the most common height among the students, useful for understanding the typical height in the class.


To calculate the mean, sum all heights and divide by 12:


Sum = 150 + 152 + 148 + 149 + 155 + 153 + 151 + 150 + 154 + 152 + 150 + 156 = 1,820 cm
Mean = 1,820 / 12 = 151.67 cm

For the median, arrange the data in ascending order:


148, 149, 150, 150, 150, 151, 152, 152, 153, 154, 155, 156
Since there are 12 values (even), the median is the average of the 6th and 7th values:
(151 + 152) / 2 = 151.5 cm
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